Compound Interest | CI | Annually - Half Yearly - Quarterly | Formula of compound interest

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#compoundinterest #ci #si #ujjwalmaths

[@GOAT4INDIA]

This video is much helpful, Many hours I have wasted in useless video,but lastly it helped me.

[@akilahmed7583]

Yes

[@parvatidevi8987]

Sir chota sa mistake kar diye

[@4angels776]

3:29

[@youtubers6914]

​@@4angels776ddddf

[@AnasMohd-zu6gm]

Sir half yearly Wale me Aapka answer 2661 aaya hai lekin answers 2662 hai

[@naveeng9002]

Seeing video before exam😃😃😃😃
They are ultra legends!
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Like!

[@mushtakkha113]

Thank you very much sir for preparing this Excellent video you solve a lot of problems from this concept thanks again🤗🤗

[@Studenthouse.]

Kash app hamare school ke math teacher hote to hum log math me brilliant ho jate☺️☺️

[@azmatkhan5282]

I was in huge problem you rescuved me thank you from core of my heart 💜💜💜💜

[@addlakshya5786]

Thanku sir for prepare this video heartly welcome ❤️❤️ tomorrow is my exam

[@vaishnavmate9082]

Very good explained

[@UJJWALMATHS]

Keep watching

[@sanjeev034]

​@@UJJWALMATHS❤❤

[@Vaishnavi06-V]

10:25 2×1331 = 2662* but nice explained 😍😍
Best math 🧮 teacher 🥰🥰

[@ssacademy9876]

yes I was also wondering

[@omchaturvedi1402]

You are an awesome teacher

[@curls2010]

Thank you sir for helping at the moment when no one was helping ❤❤

[@nayidunya9479]

Sir ji dil khush ho gya.kasam se jo bhi padhate ho bilkul clear ho jata hai

[@UJJWALMATHS]

🥰🥰❣❣💕💕💕

[@avilipsasahoo2002]

Amusing tricks, grateful for this

[@user-zv5xg8jt8o]

Your education processing system is so good ❤❤❤

[@humeranaznin6578]

Thankyou so much this was honestly soo helpful for me

[@shivamchaudharysoajitkumar6486]

Sir you are best teacher please you are teaching manjeet singh book of class 8

[@sarlaphool1188]

Thank you sir apne compound interest bohot easy kr diya 🙏🙏

[@sangamsahu2546]

You are the best teacher for maths

[@Akfleetgamerz]

That type of teachers are the god for the students ❤❤❤❤

[@GurpreetKaur-ew8mq]

Thnx sir bhut time ho gya c es confusion nu ajj clear hoyi a

[@curiousinsaan7250]

Thank you soo much sir tommorow is my exam but i cant understand this concept any video but you are the teacher who can solve and give knowledge to thousands of people thnx sir

[@akilahmed7583]

Yeah

[@kismatmiya3150]

Love you sir kya padate hai mujhe e wala chapter samjh nhi pa rha tha school me jab aap padaye to sab ekdam acche se smj aagya thankyou sir love you sir 💜😍

[@Ajit8114]

Thank you so much sir ji 😊😊😊😊

[@youtubers6914]

Best teaching plateform

[@chanakyabora1745]

"Bhai mere" hits different. Thank you Sir.

[@zainab___monawar_7238]

Very well explained sir👍🏻

[@ypsr56]

sir now I got it clearly thank you so much sir..

[@RammohanSingh-qj6im]

Nice sir isi tarah compound interest ki videos send karte rahiye

[@vijayeeram4819]

outstanding explaining

[@dailyspecialvid4831]

Thankyou so much now all doubt is clear 😊😊

[@panditpawanjha3919]

Thank you very much 😰🙏🙏

[@unknownperson3556]

Very helpful,,thank you so much

[@rahulpatil8495]

Thank you so much sir bhot video dekhne ke baad samj ne aayaa 😢😢 thanks sir ❤

[@janvijennifer1669]

Sir your trick of deriving formula is what I wanted to know so thankuu sir

[@shubhamsinghshubh3951]

Sir ye video dekhne se pehle mujhe iss chapter ka kuch bhi samajh nhi aata tha ayr parso mera maths ka exam h final prr aapki vdo dekh krr to lgg rha h maths mein mai hi top krunga 😁😁 boht acha samjhaya sir aapne thanks sir

[@Suhil866]

Thank you so much sir 🌹🌹❤
Best math teacher 🧚‍♀️🧚‍♀️

[@UJJWALMATHS]

Most welcome

[@TxFF66]

Thank you so much 💓 sir
Bahot acche se samajh aya

[@vishaldrives6432]

Thankyou so much sir 😊🙏🏼❤️

[@imaginarycreations794]

Gjb keep it up bro

[@hahatthiek6380]

Thank you so much sir keep it up

[@shreyanshtiwari913]

Very nice teacher you are 🙏

[@pramendrakumar1493]

Time fraction is clear 👌👌 last minute in this video is great Full h

[@user-vb2sg4gy4u]

Bro keep it up
I learned much by this video

[@varadpatankar2418]

thanks.. very helpful..

[@Priyanshu_xyz_01]

Thank you sir love you❤

[@rekhasingh4829]

Thank u sir for easy method
Sir ab kal hum class mai aag laga denge

[@riya3220]

Thank you so much sir... since 3days im searching for this type of explanation...now I got it..well explained 👍

[@UJJWALMATHS]

You are most welcome

[@DAILY-CREATION.]

_SIR MUJHSE TO _*_KOI QUESTON BAN HI NAHI RAHA THA_*_ PAR AB MAI _*_PRO_*_ HU_

[@tejassharma9284]

Sir you are best teacher

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Love ❤ his accent

[@adityajha5500]

Waah sir apne to bahut hi acha samjhaya Thank you sir🙏

[@UJJWALMATHS]

Welcome ❤❤

[@divyadivya9785]

Thank u so much for such osm explanation

[@UJJWALMATHS]

Most welcome 😊

[@varshakshatri1094]

Thanks sir you are such a Albert Einstein 🙏

[@UJJWALMATHS]

So nice of you

[@iftikharmehdi2702]

Waah sir moj karadi.

[@dhan8140]

V.nice sir aise aur video dalna 🙏

[@heybeauty6313]

Thank you sir

[@Artistic-Diary]

Excellent.. 👍 ❤COOL 😎 👌

[@pranavtejwani5690]

Thank you sir.

[@UJJWALMATHS]

Most welcome

[@BinduDevi-bb3et]

Thank you thank you thank you thank you thank you thank you thank you thank you so so so so so much sir 😊

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[@SpacEWeather-G]

Very helpful sir thank you

[@AnkitKumar-iw6cm]

you are great sir 🎉❤

[@adityatech88]

please make video on Volume and Surface Area Of Solid.

[@mr.sensei1502]

so well explained thx

[@prakashgaikwad9684]

Thank you sir!

[@ayushjha1846]

Parnam Sir🙏🙏🙏🙏🙏🙏

[@akasheditornarve1797]

Good teach sir

[@amandeepgill7292]

Thankyou for teaching

[@UJJWALMATHS]

It's my pleasure

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Sir Mara mummy na bola ki Koi teacher ho to apka jasa ab ma vi kisi ko paraha sakta hu Sir thank you sir 😀😀😀

[@UJJWALMATHS]

Wow

[@user-rb3uk6eu6r]

Thank you sir kl mera final exam hai.

[@harandrayadav5536]

Thanks. Sir

[@kavyanshgupta3937]

bro it is too helpful for my final examiation

[@hindisahityasargam608]

सर! आपने compounding interest को बहुत अच्छी तरह से एक्सप्लेन किया है, जिसके लिए आपको बहुत बहुत धन्यावाद। परन्तु मेरा एक सवाल है कि 407895 का 6.5% के हिसाब से 2 साल, 11 महीने और 29 दिन के लिए compounding quarterly interest on FD के हिसाब से कैसे कैलकूलेट करेंगे? कृपया मार्गदर्शन करें🙏 क्योंकि मुझे जो बैंक मेच्योरिटी दे रहा है वह अमाऊंट 494856.10 दे रहा है। तो इसको चेक करने के लिए कौन सा फार्मूला यूज करेंगे???🙏🙏🙏

[@AdityaKumar-yv9iw]

Thank you so much sir aap kas hmare school ke teacher hote

[@ranjuyadav9682]

Thanks u so much

[@shivanisaroj8643]

Thankyou so much sir

[@kunal_kaur]

exam is hear
Not nead to fear
When ujjwal sir is hear

[@UJJWALMATHS]

💕💕

[@Mr.physcoscroll]

Sir mujhe accha laga apse pedne me 🥰🥰🥰🥰

[@amulyakaranji5399]

Supper u told nice i thanks❤

[@user-eh7uh5mw7q]

Thanks sir

[@HarshDhiman12]

Helped me a lot

[@hahatthiek6380]

Sir like your explanations

[@user-ed3oe5tw7h]

Thanks sir❤❤❤❤❤❤

[@rohitrawat7195]

Thnks bhai❤❤

[@blikforever3]

Sir plz make a vid on how to find principal when amount , time and rate is given

[@GauravKumar-nx5bi]

Jabardast

[@rahulrajbhar-ataskoflife2660]

Well explained sir👍

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Welcome ❤❤

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Thanks you so much sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

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👍 really nice session

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Thank you ❤

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Thank you 👍

[@rogconfuze6837]

thank you sir this concept was very hard for me 😄😄😄😄😄

[@saijalnagar4807]

sir thank you so much 👨‍💼

[@AmitFitness0.5]

Thanks 🙏🏻 guruji

[@virendersingh8648]

If we have an odd number as the rate in the case of compounded half yearly...how we will solve it??

[@JatinSingh-wl8ex]

Thanks bro 👍

[@binaymishra8963]

Sir Ques if in annually there will be in fraction in time then what will I do

[@Snndsnkskmw8282]

Sir aap. To. Bohot accha padhate ho

[@priyankadarekar1736]

Bhai kaha the ab tak ? wonderful teaching skill ❤ competition exam ke questions lelo bhai bohot help hoga hame 😅

[@miliahmed8707]

Sir I have a question can you please solve this:
Harpreet borrowed ₹20000 from her friend at 12% per annum simple interest. She lent it to Alam at the same rate but compounded annually. Find her gain after 2 years....
Thank you sir you're very helpful to us I can't understand maths from my teacher but I could understand it from you😊

[@marvelarmy2796]

❤

[@Varsharaj_20]

For Harpeet
SI__ 12/100 * ₹20000*1
12*200
2400
Amount___2400+20000
22400
For alam
CI__ P[(1+R)^T - (1)
... . 5088
Amount__25, 088
Profit ₹25088- ₹22400
2688
Am I right? If yes then tell

[@RakeshYadav_ya]

​@@Varsharaj_20
Answer is 1000 (C.I. - S. I.)

[@RakeshYadav_ya]

See solution will be👇
#S.I.=
(20000*12*2) /100
S.I. = 4800
Now to find C. I. We will first find amount...... So,
A= 20000(1+12/100)^2
= 20000*112/100*112/100
= 25088
Now find C.I.
C. I. = Amount - Principal
= 25088-20000
C. I. = 5080
Now, difference between compound interest (C.I.) and simple interest(S.I.)
C. I. - S. I.
= 5800 - 4800
=1000
Hence, according to me answer should be 1000rs.
I am right?