How to find side length of a square inside a triangle | Area of square inside a triangle
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- เผยแพร่เมื่อ 5 ก.พ. 2025
- How to find side length of a square inside a triangle | Area of square inside a triangle
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A recent video on another channel used that ( a = bh/b + h ) without demonstrating that property of a square within a triangle as you've done so well here.
Thanks so much
Theorems are used the same way. Once proved and shown, they are applied in geometry problems without proving them again
Sir I did this way triangle
ABC Area - ARS Area - BPS Area - QCR Area = a^2
Triangle BPS and QCR base is equal to (10-a) .
Thanks
Similarity of triangles:
(h-a)/a = h/b = 8/10
h/a - 1 = h/b
h/a = h/b +1
a = h / (h/b+1)
a = 8 / (8/10+1) = 80/18
a = 40/9 cm
Similarity of triangles:
(h-a)/a = h/b. = 8/10
(h-a) = 4/5 a
a + (h-a) = h
a + 4/5 a = 8
9/5 a = 8
a = 40/9 cm ( Solved √ )
Triangles ABC and ASR are similar due to their angles, therefore; If the ratio between the base and the height of triangle ABC is 4:5, then the same ratio applies to triangle ARS. Consequently, if the base = a then the height = 5a/4. Finally a + 5a/4 = 10. We obtain that a = 40/9.
then height = 4a/5 (not 5a/4)
Finally a + 4a/5 = 8 (not 10)
We obtain a = 40/9
or
then b-a = 5a/4 ( not height )
Finally a + 5a/4 = 10
We obtain a = 40/9
Similarity of triangles:
a / b = (h-a) / h
(h-a) = a. 8/10
Also:
(h-a) + a = 8
Replacing:
8/10 a + a = 8
a (1+4/5)=8
a= 8 / (1+4/5) = 8 / (9/5)
a= 40/9 cm
Label the side lengths, add up the areas =40. Works to give 40/9.
Well, I used area of triangle ars + area of trapezoid srcb.
Seems that you are assuming an acute triangle. Doesn't work for an obtuse triangle, unless I am missing something.
a=40/9
Eheu! Id est a= 40/9 unit. Responsimus.
a=40/9