In this video, you will learn about Eddy current and its losses and derive the expression for the same. Department: Electrical Engineering Subject: DC Machines and Transformer Year: 2
as the crossectional area for the resistor is incresed resistance decreases and therefore the power losses should be reduced? Why did you say it was the opposite?
For your clarity, in rotating electrical machines, eddy current flows in the whole surface or maximum cross-sectional area of the rotor core. If cross-sectional area of the rotor is maximum, the resistance offered by the rotor is minimum and the induced eddy currents will be maximum. Due to this, the eddy current losses will be maximum. It is obvious that if the cross-sectional area of the eddy current path is reduced; the eddy current losses will also be less. This is explained in this video.
The iron loss of a transformer at 400 Hz is 10 W. Assuming that eddy current and hysteresis losses vary as the square of flux density, the iron loss of the transformer at rated voltage but at 50 Hz would be....... watt. (a) 80 (b) 640 (c) 1.25 (d) 100 How to solve it?
this is best educational channel out there...
Thank you for all your comments, your inputs are well taken, we will work upon it.
Your videos are always best, to listen too more than other.
The great class good and lots of thanks and love to the guys behind this
Great video. Do these calculations for eddy current losses apply for sheets of aluminium/copper too?
as the crossectional area for the resistor is incresed resistance decreases and therefore the power losses should be reduced? Why did you say it was the opposite?
For your clarity, in rotating electrical machines, eddy current flows in the whole surface or maximum cross-sectional area of the rotor core. If cross-sectional area of the rotor is maximum, the resistance offered by the rotor is minimum and the induced eddy currents will be maximum. Due to this, the eddy current losses will be maximum. It is obvious that if the cross-sectional area of the eddy current path is reduced; the eddy current losses will also be less. This is explained in this video.
How Area of ABCD loop is equal to 2hx instead of L×H... please anyone explain me
Excellent and unbelievable videos quality and understand
Super explanation
The iron loss of a transformer at 400 Hz is 10 W. Assuming that eddy current and hysteresis losses vary as the square of flux density, the iron loss of the transformer at rated voltage but at 50 Hz would be....... watt.
(a) 80
(b) 640
(c) 1.25
(d) 100
How to solve it?
The narration was kind of annoying
Play @ 1.5x speed thank me later