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2^^x*2^^x=20; (2^^x)^^2=202^^2x=202x*log(2)=log(20)2x=log(20)/log(2)2x=1,301/0.3012x=4,322x=4,322/2x=2.161
2^x * 2^× = 4^x = 20 --> log4 (4^×) = x = log4 (20).
x=2.1609
2^2x=202^(2x-1)÷10Log2(2x-1)=12x-1=1/log2x=1/2(1+1/log2)
10, -1 graph. Scar my parking spot
{10+10}=20 10^10 5^5^5^5 2^3^2^3^2^3^2^3 1^1^1^1^1^1^2^3 2^3 ((x ➖ 3x+2).
2^x*2^x=202^2x=202x=log_2(20)=4.3219280949x=2.16096404745You dont believe?Ok: 2^2,16096404745*2^2,16096404745=20
2^^x*2^^x=20; (2^^x)^^2=20
2^^2x=20
2x*log(2)=log(20)
2x=log(20)/log(2)
2x=1,301/0.301
2x=4,322
x=4,322/2
x=2.161
2^x * 2^× = 4^x = 20 --> log4 (4^×) = x = log4 (20).
x=2.1609
2^2x=20
2^(2x-1)÷10
Log2(2x-1)=1
2x-1=1/log2
x=1/2(1+1/log2)
10, -1 graph. Scar my parking spot
{10+10}=20 10^10 5^5^5^5 2^3^2^3^2^3^2^3 1^1^1^1^1^1^2^3 2^3 ((x ➖ 3x+2).
2^x*2^x=20
2^2x=20
2x=log_2(20)=4.3219280949
x=2.16096404745
You dont believe?
Ok: 2^2,16096404745*2^2,16096404745=20