Wow! such an easy way to explain what permittivity is! I couldn't find an easy explanation anywhere! As soon as you showed the flow chart with the word 'resistance'. It all made sense! Thanks!
That was helpful. Thank you sir. I've read a lot of electric smartass wannabe's articles that explained permittivity and none of them can explain it in basic form. Thanks a lot
Oml Mr. Anderson I've been watching all your physics, chemistry and biology videos and honestly yr vids r the most helpful and best so far... thank you so much for helping... love from India
Looking at the examples starting around 3:40, what would you expect would happen if you charged the cap with a glass dielectric (@3:52) and then disconnected the power? Now remove the glass, what is the charge on the cap? Take the glass dielectric plate you removed, and place it between the plates of a second uncharged capacitor. Does it charge? What does the result of the second capacitor becoming charged almost to the same value of the first do to your understanding of what was presented in this video? What is really happening?
4:02 Could anyone explain why does the electric permittivity increase resistance while it also increases the capacitance? I didn't take ap physics 2 but have to know this concept for the subject test
Not so sure either but, I think without any dielectic medium the charges accumulated at the two plates would create Electric field which would make them to loose energy And adding those mediums with "resistance" would allow some of those fields to be cancelled i.e., leass field and thus more chage would be stored in a capacitor
The thing is that capacitance is equal to Q/V, where V is the voltage (difference of potential). Meanwhile, if the electric field is constant (like in this case) V=E*d, where d is the gap between the plates. Because the dielectric increases resistance, it reduces the electric field and so E*d becomes smaller, so V becomes smaller and the quotient Q/V increases. Hence, the capacitance increases.
Very nice and wonderful video. It very informative and concise to understand the concept very clearly. Thanks a lot. Please upload more videos like this.
Mr. Anderson if a matter has the ability to resist the electric field and vaccum has the ability too which is constant so it is proving existence of ether as medium in space
@@lunam7249 it's really controversies between theories we assume some of constants on experimental values but to prove their existence in theoretical physics is tough I have never thought I will get a reply after so many years
@@surbhisoni4282 i am a world renown physicist, as a "good" physicist it is in my nature to instinctivily raise a point of opposition to a theory , only to trigger a support to a new theory....like yours....well capacitors have been in outer space and continue to "function" as made which is in support of your theory....i can futher support your theory....in outer space ( where space is "empty")..there still exists a resistance....376 ohms....why is that? it should be ZERO ohms....and there are not enough random electrons floating in outer space to account for that either... space = 10E-27 KG/M^3..so i agree with your theory...futhermore a light-second generates an induction force of 59 newtons (15 pounds)....so how does light generate 15 pounds of force? and repelling against "what"?....i believe more as you, as modern physics has become a melting pot of 11 dimesional tensor mathematics and excessive quantum "suppositions", and the "many worlds" nonsence...and the whole world now spits iut the word "quantum" just to "appear" smart....quantum coffee, quantum yoga, quantum crayons...ect.....if they actualy spent 3 days trying to solve 1 schrodinger equation...im sure they would hate quantums forever!!!😳😳😅😅😅😹😹😹
@@surbhisoni4282 gravity constant = 6.67E-11 , the most meassured scientific number on earth, yet no one clear definition as to the cause.... the fabric of space-time is a decent analogy but not an answer.....i think the point is not a answer "a to b" , but the enjoyment of the journey🌝🤓
Thank you so much for this video. you clear my all doubts in a very easy manner. The way you represent the opposite electric field of di electric is much more tha Awesome!! Thank you again
If 'permittivity' is a measure of a medium's tendency to RESIST the establishment of an electric field within it, why was it ever called 'permittivity' in the first place which suggests that something is being 'permitted' or allowed to happen? Its no wonder that scientific terminology is so confusing!!
Dave Humphreys Our teacher told us to think over it and that Science don't just name things randomly . He said that there was a definite reason for it but didn't tell what it was .
Dave Humphreys This was my first thought too so I sat here and thought about it. I think maybe a couple of reasons and I think of it as a permitivity 'level' or 'raiting' (like wire gauges), rather than 'how well it lets electrons pass (the latter would lead you to believe that higher numbers = better conductivity).' When they discovered permitivity they probably hadn't tested all materials, so they may have said 'let's just imagine 0 is a perfect material that has perfect permitivity and higher numbers would be higher resistance.' Personally I think it should be called reluctance or impedence but maybe those were taken?
The relative permittitivity is a ratio of the material's permitivitty in relationship to the permittivity of vacuum. That's why vaccum's 1. This also means it has no units! e_r = 1, for vacuum, not 1 F/m.
It's amazing kids are learning this in high school now. I didn't even have the option to take classes of of this nature when I was in high school 10 years ago.
Also note permittivity changes with freq, value at dc-10kHz isn't the same as the value at 300MHz. Dielectric constant typically refers to the permittivity in those low freqs/DC
Gauss's law shows that the amount of flux intersecting a spherical Gaussian surface is: Eo(4πr²)=Φ=Q(inside)/εo. Therefore: Q(ins)/Eo·A=εo. This is the charge density per electric field, or the charge per flux line intersection with the Gaussian surface. It gives an indication of how much charge is permitted on a surface. The higher the permittivity value, the more charge is permitted on surfaces but this will lower the net electric field Enet _inside the dielectric_ (vector sum of the free space plate fields Eo & the induced dielectric fields Ei) as the fields cancel out more if there are more _induced_ charges of opposite sign on surfaces inside facing the outer surface _plates_ , which is what happens in a capacitor with a dielectric. A dielectric lowers the net electric field Enet=Eo↓ + Ei↑=Eo↓+(-bEo↓)=(1-b)Eo↓=Eo↓/κ, by a factor sometimes called _the dielectric constant_ κ. If the charged plates remain the same, as a dielectric is inserted between them, the new permittivity would be: Q/(Eo/κ)A=κ·εo=ε, Where Q/A=σ=charge density on Gaussian surface with area A.
Great video ! great presentation One question, I am surprised 3 volts managed to permiate through the plastic dielectric in the middle? I know cling film has a lower break down but surprised 3v managed to break it down? Thanks! James
sir can you help n fundamental charges each of charge q are to be distributed as two point charges separated by a fixed distance , then maximum to minimum force bears a ratio(n is even and greater than 2
This is probably stupid, but at 4:20 you say that the dielectric creates a 'resistive field' to appose the electric field, but how does that increase the permittivity because then surely the electrons have nothing to be attracted to if there is no overall force there? Because before they would be attracted to one side of the plates, which in turn repels the electrons on the other side. I don't know if that makes sense, I'm only an a level student so I don't think my understanding is quite right? Thanks for any help :)
I would like to clarify that permittivity of free space is *not* referred to as the "dielectric constant". The dielectric constant, and permittivity of free space are two different things. You could say, however, that the relative permittivity is known as the dielectric constant. Therefore, the relative permittivity or dielectric constant of a vacuum is 1 F/m. Where as the permittivity of free space is 8.854e-12 F/m.
Why is charge increasing after adding dielectric? Actually as dielectric is forming electric field in opposite direction, doesnt electrons of dielectric flow towards positive side of capacitor and decrease the charge?
I could be wrong but I think because the force produced is from a point or spherical charge is the same in all directions, it is spread evenly over the surface of an imaginary sphere. Where surface area = 4×pi×r^2, the force is inverse to that, hence 1/4×pi×r^2 (The r^2 is in the other term).
Can you explain why permittivity is effected by frequency in water? Relative permittivity is 80-81 for RF spectrum but 1.77 for visible light spectrum. I can't understand that phenomenon. I thought it was a material constant.
I have a question sir... Why does the charge on capacitor plates increase when we put an dielectric inbetween... I understand the resistance in electric firld concept but i dont get the why there is increasement in charge on the plates?
awesome vid. quick question - why do the cap plates have to be in close proximity to eachother? why doesn't a capacitor work if the distance between the plates is massive? i'm guessing the further away the plates, the higher the permittivity of the electrical field? or does the permittivity value not work in that way? Cheers!!
Wow! such an easy way to explain what permittivity is! I couldn't find an easy explanation anywhere! As soon as you showed the flow chart with the word 'resistance'. It all made sense! Thanks!
this guy understands physics at the deepest level a human can
going back and re-reading the wiki entry on relative permittivity feels intuitive now.
one of the finest explanations i ever had on you tube, thanks a lot.
Mr. Anderson, I love you. You're a lifesaver!
@Noe River shut up both you
@@dae1925 haha, both are bots
@@lowendpotato3021 yes
No book could do this to me. Stunningly simple and yet crisp to the point. Thanks a ton Mr Bozeman
Practical and impeccable description. The simulation is pretty handful as well. Thanks for this video.
this is by far the best video i have ever seen thank you so much
That was helpful. Thank you sir. I've read a lot of electric smartass wannabe's articles that explained permittivity and none of them can explain it in basic form. Thanks a lot
sir,you are lifesaver.
Oml Mr. Anderson I've been watching all your physics, chemistry and biology videos and honestly yr vids r the most helpful and best so far... thank you so much for helping... love from India
Brief and well explained. Thank you!
These videos rock.
Sir, you become my physics guru(teacher) . Love from India.
Your videos always rock mr. Anderson!
Mr. Anderson much love for you. from South Africa
Looking at the examples starting around 3:40,
what would you expect would happen if you charged the cap with a glass dielectric (@3:52) and then disconnected the power?
Now remove the glass, what is the charge on the cap?
Take the glass dielectric plate you removed, and place it between the plates of a second uncharged capacitor. Does it charge?
What does the result of the second capacitor becoming charged almost to the same value of the first do to your understanding of what was presented in this video?
What is really happening?
I have seen a lot of science videos but this one is really creative , making a capacitor from foil and plastic ingenious !
4:02 Could anyone explain why does the electric permittivity increase resistance while it also increases the capacitance?
I didn't take ap physics 2 but have to know this concept for the subject test
Not so sure either but,
I think without any dielectic medium the charges accumulated at the two plates would create Electric field which would make them to loose energy
And adding those mediums with "resistance" would allow some of those fields to be cancelled i.e., leass field and thus more chage would be stored in a capacitor
The thing is that capacitance is equal to Q/V, where V is the voltage (difference of potential). Meanwhile, if the electric field is constant (like in this case) V=E*d, where d is the gap between the plates. Because the dielectric increases resistance, it reduces the electric field and so E*d becomes smaller, so V becomes smaller and the quotient Q/V increases. Hence, the capacitance increases.
omg this is the best lesson ever, I hope they teach us like this in school
Such a great explanation sir.... I found this lecture really helpful... I Love watching your lectures....
Very nice and wonderful video. It very informative and concise to understand the concept very clearly. Thanks a lot. Please upload more videos like this.
Mr. Anderson if a matter has the ability to resist the electric field and vaccum has the ability too which is constant so it is proving existence of ether as medium in space
outer space has a "temperature" even though almost "zero" atmosphere is providing for it
the distance between the plates is the "resistance", a millimeter to an electron is like los angeles to new york to a human....a long way
@@lunam7249 it's really controversies between theories we assume some of constants on experimental values but to prove their existence in theoretical physics is tough
I have never thought I will get a reply after so many years
@@surbhisoni4282 i am a world renown physicist, as a "good" physicist it is in my nature to instinctivily raise a point of opposition to a theory , only to trigger a support to a new theory....like yours....well capacitors have been in outer space and continue to "function" as made which is in support of your theory....i can futher support your theory....in outer space ( where space is "empty")..there still exists a resistance....376 ohms....why is that? it should be ZERO ohms....and there are not enough random electrons floating in outer space to account for that either... space = 10E-27 KG/M^3..so i agree with your theory...futhermore a light-second generates an induction force of 59 newtons (15 pounds)....so how does light generate 15 pounds of force? and repelling against "what"?....i believe more as you, as modern physics has become a melting pot of 11 dimesional tensor mathematics and excessive quantum "suppositions", and the "many worlds" nonsence...and the whole world now spits iut the word "quantum" just to "appear" smart....quantum coffee, quantum yoga, quantum crayons...ect.....if they actualy spent 3 days trying to solve 1 schrodinger equation...im sure they would hate quantums forever!!!😳😳😅😅😅😹😹😹
@@surbhisoni4282 gravity constant = 6.67E-11 , the most meassured scientific number on earth, yet no one clear definition as to the cause.... the fabric of space-time is a decent analogy but not an answer.....i think the point is not a answer "a to b" , but the enjoyment of the journey🌝🤓
Thank you so much for this video. you clear my all doubts in a very easy manner. The way you represent the opposite electric field of di electric is much more tha Awesome!!
Thank you again
If 'permittivity' is a measure of a medium's tendency to RESIST the establishment of an electric field within it, why was it ever called 'permittivity' in the first place which suggests that something is being 'permitted' or allowed to happen? Its no wonder that scientific terminology is so confusing!!
Dave Humphreys
Our teacher told us to think over it and that Science don't just name things randomly . He said that there was a definite reason for it but didn't tell what it was .
Dave Humphreys and i thought i was the only one😉.
It means how much is being pemitted and how much is being resisted
Dave Humphreys This was my first thought too so I sat here and thought about it. I think maybe a couple of reasons and I think of it as a permitivity 'level' or 'raiting' (like wire gauges), rather than 'how well it lets electrons pass (the latter would lead you to believe that higher numbers = better conductivity).'
When they discovered permitivity they probably hadn't tested all materials, so they may have said 'let's just imagine 0 is a perfect material that has perfect permitivity and higher numbers would be higher resistance.'
Personally I think it should be called reluctance or impedence but maybe those were taken?
I think of it as how much is permitted negatively, as negativity, permit-ivity, and remember that so it’s how much is negatively permitted
you teach better than my lecturer, thanks!!!!
The relative permittitivity is a ratio of the material's permitivitty in relationship to the permittivity of vacuum. That's why vaccum's 1. This also means it has no units! e_r = 1, for vacuum, not 1 F/m.
Wow best explanation ever . Thank you very much sir
Very clear explanation! I just can't understand why it is called "permittivity" if the final result is that it "RESISTS", not "PERMITS". Thank you!
Here Permittivity means that the materials of the medium" allows or permits " it's atoms to resist the formation of electric field .
Here Permittivity means that the materials of the medium" allows or permits " it's atoms to resist the formation of electric field .
thanks for the video. I was for searching the same question for a while now..... it helped a lot!!!!
An awesome video that saves my life. Thank you!
This is brilliant. Thank you!
just owsome.. plz make videos on susceptibility, magnetic induction etc
It's amazing kids are learning this in high school now. I didn't even have the option to take classes of of this nature when I was in high school 10 years ago.
Well, don't bother about the pass. If you have a passion in physics, it's never too late to start to indulge into it now. Go for it :-)
Thank you
Also note permittivity changes with freq, value at dc-10kHz isn't the same as the value at 300MHz. Dielectric constant typically refers to the permittivity in those low freqs/DC
Your channel is awesome!!
animations are always helpful
Thank u for explaining. This was really helpful
Gauss's law shows that the amount of flux intersecting a spherical Gaussian surface is: Eo(4πr²)=Φ=Q(inside)/εo.
Therefore: Q(ins)/Eo·A=εo.
This is the charge density per electric field, or the charge per flux line intersection with the Gaussian surface.
It gives an indication of how much charge is permitted on a surface.
The higher the permittivity value, the more charge is permitted on surfaces but this will lower the net electric field Enet _inside the dielectric_ (vector sum of the free space plate fields Eo & the induced dielectric fields Ei) as the fields cancel out more if there are more _induced_ charges of opposite sign on surfaces inside facing the outer surface _plates_ , which is what happens in a capacitor with a dielectric.
A dielectric lowers the net electric field
Enet=Eo↓ + Ei↑=Eo↓+(-bEo↓)=(1-b)Eo↓=Eo↓/κ,
by a factor sometimes called
_the dielectric constant_ κ.
If the charged plates remain the same, as a
dielectric is inserted between them,
the new permittivity would be:
Q/(Eo/κ)A=κ·εo=ε,
Where Q/A=σ=charge density on
Gaussian surface with area A.
Thank you for saving my life
at 2:32 there is a little mistake, the relative permittivity is a ratio, so it shouldn't be 1 F/m but just 1.
I'm sorry, aren't those two field lines at the outest (top and bottom) edges at 2:15 supposed to bend outward due to electromagnetic interaction?
Thank you
Super concise, super helpful 💥 def subscribed
Man I hope the rest of your videos are like this one 🤙🤙🤙
That's great. Thank you so much
Very well explained. Bravo. Keep up the good work👍🎉
Damn, I wish that my physics prof can explain like this. He often gives us introductory definitions that are in terms of equations, not concepts
Very good explanation.
Nice work
Great video ! great presentation
One question, I am surprised 3 volts managed to permiate through the plastic dielectric in the middle?
I know cling film has a lower break down but surprised 3v managed to break it down?
Thanks!
James
Hey..u r a genius..the concept has got ingrained in my mind now..thnx a lot 👏👏👏👏😝
3:12 I thought the relative permittivity has no dimension?
You were right to think that.
It doesn't
Hope that was helpful? you sir deserve a medal. that's how helpful you were :-D
wow, so clear! thank you!
That was really useful, Thank you so much
It was helpful, I am subscribed
sir can you help
n fundamental charges each of charge q are to be distributed as two point charges separated by a fixed distance , then maximum to minimum force bears a ratio(n is even and greater than 2
This is probably stupid, but at 4:20 you say that the dielectric creates a 'resistive field' to appose the electric field, but how does that increase the permittivity because then surely the electrons have nothing to be attracted to if there is no overall force there? Because before they would be attracted to one side of the plates, which in turn repels the electrons on the other side. I don't know if that makes sense, I'm only an a level student so I don't think my understanding is quite right? Thanks for any help :)
Jennifer Bartlett exactly my pt!
very useful information got in a few minutes.
Very helpull thanks a lot. . .
The best explanation
EXCELLENT VIDEO!!! thank you!!
Amazing! Thank you very much.
Did you mention what F or m stood for?
F = FARAD = AMPERE x SECOND ------- m = meter
Very helpful and simple
I would like to clarify that permittivity of free space is *not* referred to as the "dielectric constant". The dielectric constant, and permittivity of free space are two different things. You could say, however, that the relative permittivity is known as the dielectric constant. Therefore, the relative permittivity or dielectric constant of a vacuum is 1 F/m. Where as the permittivity of free space is 8.854e-12 F/m.
plz help me out to explain permitivty vs frequncy plot for ferroelectric material.plz
What kind of software is that it calcurate capacitence by diffarent materual please let me know name please.
Thank u so much! I learned a lot
that was awsome thank you!
Thank you, good job
Charge is collected on plate or between plate
Why is charge increasing after adding dielectric? Actually as dielectric is forming electric field in opposite direction, doesnt electrons of dielectric flow towards positive side of capacitor and decrease the charge?
Thanks sir ❤
you are great ❤
Why are the protons not be shifted as well which would subsequently cancell out the effect the electrons had and therefore not affect the field ?
Great, but I’ve never heard of Reynolds wrap so I have no idea what it’s made from, aluminium ? tin? Thanks
Great. Thank you sir!
excellent sir you are a genius
Thank you!!
Very helpful 😊
Thank you so so much.
Is dielectric constant reciprocal of permittivity?
It was a great lecture
Nice I really needed that :)
Very Helpful...
Thank U
Are capacitors used in mobile phones for the vibration purpose or something else is used? Please answer anyone!
small moter is use their
Vibrations are created by spinning a motor whose weight is not evenly distributed about the axel
For filter purposes i think it is generally used in a circuit which regulated signals
It is used in amplifiers,rectifiers and different electronic components
Why 1/4pi Epsilon for that constant???
I could be wrong but I think because the force produced is from a point or spherical charge is the same in all directions, it is spread evenly over the surface of an imaginary sphere. Where surface area = 4×pi×r^2, the force is inverse to that, hence 1/4×pi×r^2 (The r^2 is in the other term).
what happens to the force between 2 charges when we put any material other than air in between them?
super helpful!
Can you explain why permittivity is effected by frequency in water? Relative permittivity is 80-81 for RF spectrum but 1.77 for visible light spectrum. I can't understand that phenomenon. I thought it was a material constant.
The explanation was superb! Specially that simulation, can anybody tell me the name of that simulation software
Awesome bro
If 2 point charges have 'K' 81 in water then what force these charges Will experience in air
Are electric permittivity and dielectric constant same thing?
Is it possible to accelerate a metal peice( infinite dielectric constant) To a speed Any where near to light by using a capacitor .?
rail guns in usa navy = 6 miles / second
I have a question sir... Why does the charge on capacitor plates increase when we put an dielectric inbetween... I understand the resistance in electric firld concept but i dont get the why there is increasement in charge on the plates?
Same doubt bro, did u get the answer?
what a god.
Very nice
thanks.....great video
awesome vid. quick question - why do the cap plates have to be in close proximity to eachother? why doesn't a capacitor work if the distance between the plates is massive? i'm guessing the further away the plates, the higher the permittivity of the electrical field? or does the permittivity value not work in that way?
Cheers!!
Thank-you Sir! That was great! :)
Really helpful.