Challenged accepted Name - Kartik Jani Ans.... - 19 - b , 20 - b And the question given by you is - 31.66 kmph Solution - 19 - We have to add the distance of train 🚂 and divide by speed 20 - Sorry ( Too long ) Solution of questions given by you 15 + 20 + 60 / 3 Ans... - 31.66 kmph
20..diameter/2-radius Circumference -2*π*r 2*22/7*35=220cm 400time-60 sec 1sec=20/3 times 220cm=2.2m 2.2*20/3m=44/3 m per sec 44/3 m per sec *18/5=52.8 km/h
19.Length of X train-475m Length of Y train be Am The total time to cross y train is 42 sec.. Speed of X train is 26m/sec Distance/speed -time 475+am/26-42 A-617m (b)
MY NAME IS PRANAV PLEASE TAKE MY NAME CORRECTLY I AM FROM BIHAR ' THE ANSWER OF Q.18. B Q.20. B THE QUESTION YOU ASK , I WILL GIVE YOU THE ANSWER ANSWER IS 11.875 THANKS FOR TEACHING 🙏🙏🙏🙏🙏
Questio no 1 Sol- Dis=42×26=1092m Length of train Y-1092-475-617m Ans-617m Q2-D-70cm Circum-220cm 400times/min-220*400 -88000cm/sec In km/h-88000*3/50000 Speed in Km/hr-5.28km/hr Ans-5.28km/hr Todays score -17/18 From Uttar Pradesh Up sainik ka score 140 kya sir hoga ya nahi
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SIR I AM NABEEL CHALLENGE EXCEPTED AND MY ANSWER IS 35.5KM ANSWER LOVE YOU SIR 🔥❤❤❤❤ LOVE FROM JAMMU AND KASHMIR
Q.19 B
Q.20 B
Garvit parihar from hisar haryana🔥🔥🔥🔥🔥
3. C ( 4 . 5 hr . )
19Q.b
20Q.b
Name-HARDIK SATI
State-UTTARAKHAND
Sir please take my name 🙏🙏
6. B
5. C
Q,6। B
2. A (520kM)
3.C (4.5 hr.)
Jai Jaat ❤❤❤❤❤
Challenged accepted
Name - Kartik Jani
Ans.... - 19 - b , 20 - b
And the question given by you is - 31.66 kmph
Solution - 19 - We have to add the distance of train 🚂 and divide by speed
20 - Sorry ( Too long )
Solution of questions given by you
15 + 20 + 60 / 3
Ans... - 31.66 kmph
Name - Subhosmita Biswas
Class -5
State - West Bengal
Score - 18/18
Q19.B
Q20.B
NAME--ARYAN GOUTAM
ANS 19.B
20.A
FROM--MADHYA PRADESH
Q19.B
Q. 19:- B
Q. 20:- B
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Question 13 a
question 19c
Question 124 a
4.C (80 km/h )
SIR CHALLENGE ACCEPTED MY ANS IS 19.B 20.B FROM UP AYODHYA
21..avg. speed=total distance / total time
3 equal distance respectively x,x and x
Total distance=3x
Total time=x/15+x/20+x/60= 8x/60
3x/8x/60= 22 .5
19.B
Challenge -22.5 😎😎
Harsh Nath DARK GOD
Uttarakhand
Sir love you and Thanos ARMY 🪖🪖❤❤
520
20..diameter/2-radius
Circumference -2*π*r
2*22/7*35=220cm
400time-60 sec
1sec=20/3 times
220cm=2.2m
2.2*20/3m=44/3 m per sec
44/3 m per sec *18/5=52.8 km/h
19 b
20 b
First comment
First comment 😊
19.B
Q,3 । C
19.b
20.b
Second
3
19. B. Utkarsh Singh
Option B
Name - Aryan Yadav
From - Haryana
19. B
20. B
EXTRA QUESTION = 11.875 km/hr.
Q, 4 ।। C
19.b 20.b from punjab
19.Length of X train-475m
Length of Y train be Am
The total time to cross y train is 42 sec..
Speed of X train is 26m/sec
Distance/speed -time
475+am/26-42
A-617m (b)
MY NAME IS PRANAV PLEASE TAKE MY NAME CORRECTLY
I AM FROM BIHAR '
THE ANSWER OF
Q.18. B
Q.20. B
THE QUESTION YOU ASK , I WILL GIVE YOU THE ANSWER
ANSWER IS 11.875
THANKS FOR TEACHING
🙏🙏🙏🙏🙏
I am anshi from Himachal
Q,9। A
Q,8। C
Questio no 1
Sol- Dis=42×26=1092m
Length of train Y-1092-475-617m
Ans-617m
Q2-D-70cm
Circum-220cm
400times/min-220*400
-88000cm/sec
In km/h-88000*3/50000
Speed in Km/hr-5.28km/hr
Ans-5.28km/hr
Todays score -17/18
From Uttar Pradesh
Up sainik ka score 140 kya sir hoga ya nahi
Q.19 .B
Q.20 B
THANOS ARMY ❤
your name
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@@SamriddhiRMS id do
16d
13c
Q,10 ।। C
4.C 80 km/hr
I am ritik 35.5
प्रदेश
A. 520
sir i am akash
19=b
20=b
Ans-19.b and 20.a
28:11
Sir I'm a new student
My name is Ananya Gupta...please check my solution that I have given
90km
540
Challenge question -7.5 hour
Anmol
19 bbbb
20 ddddddd
Challenge accepted
Aaa
Sir 13 is wrong
It's correct
Perimeter =2×1200=2400
2400/16 =75min
75/60 = 1.2 hours
3.C
Q, 7। B
Q 7. c
20. B. Utkarsh Singh
Q,11। C
Q,12।। C
28:32
Sir 13 is wrong
Q,5।। C