Hi! Thanks for making these informative videos !! They really help. But I am getting stuck on one concept. How do we know when to use which centroid formula for a triangle ? Why didn't we use the 1/3 b for the centroid as opposed to the 2/3b? What is the main difference? Thanks for all your help.
Thanks, but yeah that was my bad. I didn't bother because at the time when I made this it was a just precursor to simple distributed loading problems wihh vertical loads in which the y bar is never needed, but it could be for sloped members or wind/pressure loading etc... So whoops sorry!
The center of area of a full circle is in "the middle." Just draw a semicircle by itself and try to locate the "middle." You wouldn't draw the middle touching an edge, it would be about where I have drawn it in this video. Make sense? circles and semicircles are different shapes.
The shape on the right is a semi circle. It is 3 units tall (see y axis). That means the diameter of the (would be full circle) semicircle is 3. Radius is 1/2 diameter, = 3/2 =1.5
Yes whoops, I should have also demonstrated ybar. I didn't, because in most statics problems like this, you only need xbar, but ybar is the same, just swap all the x's for y's. so ybar=ΣyiAi/ΣAi
The the centroid of a semicircle is 4r/3π away from the flat edge, and halfway between the top and bottom when it's oriented like this. y coordinate is therefore r away from both the top and the bottom
This 9 minute video was better than the 3 hours worth of lectures in my statics class. Thank you!
Thanks bruh. You can check out all the free statics videos I made at engineer4free.com/statics cheers!
@@Engineer4Free understandable
Thanks dude. Explained it better than the education I'm PAYING for.
TH-cam University FTW :)
wow same. I'm currently studying all the modules the night before my midterms. And I can say i learned a lot more than months worth at school
@@Engineer4Free hii
Jesus private highshools suck that bad?
@@Luka_c123 colleg ;(
Wow!! I was able to watch the proofs and examples in less time than one lecture. Thank U!!
Glad it was helpful!!! =)
There is special place in heaven for such teachers....
Thanks Sohaib 🙌
First off I appreciate the audio and video quality, and thanks for making it so simple!
Hey thanks! I do try to keep it professional 👌👌
wow great explanation, i guess i can become an engineer on youtube instead of in school
hahaha basically... TH-cam University FTW
I think your website is great too, its real nice looking and really easy to use and follow, great job
Thanks! :)
well said
A lovely little tutorial. Very well explained, good example used. Ten out of ten. Thank you.
Thanks a lot James =) =)
48 people DIDN’T find this helpful??? This is what will help me pass the test tomorrow.
Same here 😂
Hope it went well!!!
You are literally a lifesaver, thank you so much!
Happy to help!! You can also see a few more videos on the topic here: engineer4free.com/statics see videos 58-65 =)
this is the best physics lesson i never had b4
This was a ton of help! Thank you!
Cheers dude, glad to hear it!
in 9th grade doing this it’s so stressful but you came in clutch
9th grade, wow! Thats a record I think.🤜🤛
9th grade? Bro where you going to school at? MIT high school?
your explanation is spot on
Thanks!! =)
So if (5.08, y) is the centroid, how can the y-coordinate be found? Love your videos by the way, they're saving my life this semester!
You can find the y coordinate by doing the exact same process, just switching every instance of "x" with "y"
The dislikes are from all the teachers and professors who are obsolete because of you
😂 maybeee
Thankyou idol its Helpful clear explanation than my teacher
Happy to help =) the full playlist is here: engineer4fee.com/statics
@@Engineer4Free waoh thanks a lot idol👍🤞❤
Another great video thank you!
Thanks Luis!! 🙂
Now I am your scriber dude...
Love from india thank-you
Glad to have you Raja! Tell some friends 🙂🙂
thanks man you've helped clarify things
the centroid of semi circle is 0.63 so the x3 will be 2+6+0.63=8.63
i Came .. i Saw .. i Subscribed ! 😇
Awesome, thanks Sharad!!! =)
Hi! Thanks for making these informative videos !! They really help. But I am getting stuck on one concept. How do we know when to use which centroid formula for a triangle ? Why didn't we use the 1/3 b for the centroid as opposed to the 2/3b? What is the main difference?
Thanks for all your help.
the smaller side I believe you use the 1/3 and the bigger one you use 2/3 when you divide the triangle from the middle
Jahh ✌️
what I want to know is when do I use 2/3 or 1/3 for triangles
the centroid is 1/3 of the way from the tall side, and 2/3 of the way from the short side, for right angle triangles in this orientation
@@Engineer4Free Alright thank you
Very very Tqq Sir...❤🎉🎉❤❤
Could you please upload y-axis video as well. Thanks
great explanation, but it would have been better if you do the y bar as well.
Thanks, but yeah that was my bad. I didn't bother because at the time when I made this it was a just precursor to simple distributed loading problems wihh vertical loads in which the y bar is never needed, but it could be for sloped members or wind/pressure loading etc... So whoops sorry!
sir can you do a video on getting y bar?
Who's bad professor is the reason they are here in 2021!? XD
Me 😂
My teacher “taught” me this in 90 minutes when she could have done it in 9!
😏
that was useful .. thank you Mr.
Thanks for watching and letting me know :)
greatttttt thanx MR this is helpful
Awesomeee thanks for the comment!
Is the y(bar) the sam method except using y values?
Yeah, sorry in hindsight I should have also calculated it in this example. See videos 58 and 59 here: engineer4free.com/statics for more info ✌️
Small advice on u is dat the colour that u are using is not well visible how about to use black or red colour?
Hey yeah, I made this video quite a long time ago, and have since tried to make the pen stokes more visible. Thanks for the feedback!!
Which software is it that you use to make this video? It looks really nice
Hey thanks, I have a full list of software and hardware that I use at engineer4free.com/tools check it out!
Sir, when will xbar or ybar for the centroid of a shape be equal to zero?
X bar will be zero if the centroid lays on the y axis. Y bar will be zero if the centroid lays on the x axis.
Thank you Sir :)
Hello. I have a question. about to find the x bar for triangle. Im confused wether to use 1/3 or 2/3 . TQ
The centroid is 1/3 of the way away from the tall side, and 2/3 of the way away from the short side 😊
Why isn't the x of the semi circle 0 here?
The center of area of a full circle is in "the middle." Just draw a semicircle by itself and try to locate the "middle." You wouldn't draw the middle touching an edge, it would be about where I have drawn it in this video. Make sense? circles and semicircles are different shapes.
i have a question bro if i want to get the y-bar is it just y-bar=sum(YiAi)/sum(A
)
yeah
Probably late but is the Ybar equal to 0.1630?
hye if the triangle is upside down. for y bar i need to use 2(b)/3 again? because it will start from the shortest one?
If the triangle was flipped vertically, the short side would still be on the left, so the calculation would be the same.
@@Engineer4Free thank u so much
8 units away form the origin??? so thats start from zero Right??
Yea
I don't get where you found ??1.5??
The shape on the right is a semi circle. It is 3 units tall (see y axis). That means the diameter of the (would be full circle) semicircle is 3. Radius is 1/2 diameter, = 3/2 =1.5
What about for y?
Yes whoops, I should have also demonstrated ybar. I didn't, because in most statics problems like this, you only need xbar, but ybar is the same, just swap all the x's for y's. so ybar=ΣyiAi/ΣAi
Why is it the x component of the triangle is 2(b)/3?
because hes taking all the measurements from the origin of the graph. the component is 2/3rds from the origin or 1/3 from the nearest side.
Yeah thanks for being a bro Kody.
Woahh thanks this helped me a lot in my statics exam. 😁
Glad to hear it!!!
absolutely lit fam
What will be the y coordinate of the Center of mass of semicircle
The the centroid of a semicircle is 4r/3π away from the flat edge, and halfway between the top and bottom when it's oriented like this. y coordinate is therefore r away from both the top and the bottom
Great video but so disappointed u didn't do y bar😢
So for y I have to use 1/3 ??
Yeah, for the triangular section, it ybar is 1/3 of the way up the triangle vs height, from y=0
What about the y for the triangle?
for a triangle in this orientation, centroid is 1/3 base away from the bottom right corner, and 1/3 height away from the bottom right corner.
does any one did, the (y) i have 1.44
Yup that is correct!
salim nour Haa sxp
10/10
Sir pls ask in hindi
You're not that audible though
Is the sector of a circle is 2/3 r sinƁ/Ɓ
@batica