Indhu you can check this out n.stucor.in/semester/STUCOR_CS8501-SH.pdf?_ga=2.122065548.689456102.1683907333-1450337193.1671938057&_gl=1*j246td*_ga*MTQ1MDMzNzE5My4xNjcxOTM4MDU3*_ga_N9LJVDX1HR*MTY4MzkwNzMzMy4zNi4wLjE2ODM5MDczMzMuMC4wLjA.*_ga_D6D5Z4RF97*MTY4MzkwNzMzMy4zNy4wLjE2ODM5MDczMzMuMC4wLjA.*_ga_54331VJR2D*MTY4MzkwNzMzMy4zNS4wLjE2ODM5MDczMzMuMC4wLjA.
In previous video for a^nb^n you considered 3 cases 1) y belongs to a 2) y belongs to b 3) y belongs to a and b why havent you considered any such cases here in this example
In my case, If we have xy^2z which needs to applied on S = 1^p 0^p 1^p 0^p We have , i=2, x=1^p y^2=(0^p 1^p)^2 z=0^p How to write y part , y = 0^p 1^p 0^p 1^p Or y= 0^p 0^p 1^p 1^p Sir , Give me the correct expansion!
Sir condition 2 satisfy agumla |y|>0
Mention timestamp of doubt.
Sir is pumping lemma a problem based question??
No. MOstly will be theorem only
important 2 mark question sollunga sir... Pls
Indhu you can check this out n.stucor.in/semester/STUCOR_CS8501-SH.pdf?_ga=2.122065548.689456102.1683907333-1450337193.1671938057&_gl=1*j246td*_ga*MTQ1MDMzNzE5My4xNjcxOTM4MDU3*_ga_N9LJVDX1HR*MTY4MzkwNzMzMy4zNi4wLjE2ODM5MDczMzMuMC4wLjA.*_ga_D6D5Z4RF97*MTY4MzkwNzMzMy4zNy4wLjE2ODM5MDczMzMuMC4wLjA.*_ga_54331VJR2D*MTY4MzkwNzMzMy4zNS4wLjE2ODM5MDczMzMuMC4wLjA.
Generic la u^p u^p -solve panna kutadha .
Previous sum la generic a^p b^p mattum pannom .
Given language in terms of p pananum
i=1 yedukalaam la sir
Yes u can , one doubt y he not took y in three cases as shown in previous example
You can take any i, but we should try to take value where it fails.
Sir why did we consider only this configuration op1p0p1p why not 1p0p1p0p ....?
We can consider any form. But should find a example where our assumption doesnt hold.
Sir why we cannot take y as three cases as shown in previous example
Mention time stamp of doubt.
In previous video for a^nb^n you considered 3 cases
1) y belongs to a
2) y belongs to b
3) y belongs to a and b
why havent you considered any such cases here in this example
@@rajarajeswarisingaravelan6229 It depends on the language given in question
i=1 yeduthaaa then it will be belongs to the language laa sir.? Why dont we do that
We want a case where it fails. Thats why
In my case,
If we have xy^2z which needs to applied on S = 1^p 0^p 1^p 0^p
We have ,
i=2,
x=1^p
y^2=(0^p 1^p)^2
z=0^p
How to write y part ,
y = 0^p 1^p 0^p 1^p
Or y= 0^p 0^p 1^p 1^p
Sir , Give me the correct expansion!
Its difficult to understand from this comments. Can you please share the solved screenshot to venkat.kvhapp@gmail.com. I can check and tell you
Exam la generic method or specific method la pannanuma sir?
Generic is better
Sir power p en podrom nu soldringla
Refer my previous video, its basically the lemma.
Sir generic approch kandipa pannanuma illaya
Its better if you write it.
S value kandu pidika kastama irukku
Practise few questions then you will understand it better.
Sir maximum repeated sums tha kepangala,neega pothuerukura model la
For which topic?
@@because2022 for pumping lemma sir
@@muthumuruganharish Yes
@@because2022 sir and one more question sir in aiml 25 mark edhutha pass ah like web essential
@@muthumuruganharish If its same kind of paper without integrated lab, then it will remain the same.
sir i ooda value kandu pudika specific method irrukah ella namba eduthu karathu thaan na
NO method. You can take random value.
Sir pumping lemma sum la both basic and generic approach podanuma sir?
Generic is mre imprtnt.
Apa first method podama straight ah generic podalama sir
Belongs to L nu varudhu sir
10:33
Sometimes it may belong to L. But we should find cases where it fails
@@because2022 ok..thanks sir
Sir if pumping lemma questionla u^m.u^n apdinu keta epd sir i value consider panradhu
If u is part of 0,1.. take any sample string for random m and n.. eg m=3 n=2 means 00011. Then take any value of i.
@@because2022 thank you sir
sir slide for this is not available
drive.google.com/drive/u/1/folders/1dio9t8lsx3CQLCMR7MQ2t6mThDINtLUT
Sir, Specific la potalum mark potuvanghala
Depends on the evaluator. Mudinja generalized a podunga. Tough a iruntha specific a podunga.
Sir i value enna venna eduthukalama
Yes.
✨
Keep watching.