you gotta tell me man, on the 2nd activity, how did you find the reaction force (Fn) when you don't knoe the mass? Seems like a load of confusion to me
In part b, set fnet = force of friction. This gets you a result of ma = umg where “u” is the coefficient of friction. If you simplify the expression the mass “m” cancels itself out leaving you with the statement a = u*g. Hope this helps!!
@@Elec2ricLearning Yo, Electric, I got a request, could you also do Higher Level physics, like A.4 which is about rotational motion and how rotational stuff works? You are really good at explaining, and your knowledge would come in handy.
Frictional force is always opposite of applied force because friction of the surfaces of objects works to prevent objects from sliding past on another. This in essence then is working to prevent the movement of the ball to the right, meaning it applies the force to the left. If the ball was being pushed to the left, the fractional force would then be drawn to the right. It is always opposite. I hope that helps!
thanks for the videos! they help a lot (p.s. we don't get the weight of the box in activity 2 so we cant calculate the friction, or am i missing something?)
![NEW 2025 EXAM - IB Physics A.2 - Forces & Momentum PART 2 [SL/HL] - Interactive Lecture](http://i.ytimg.com/vi/Bx1F1gw5TWY/mqdefault.jpg)
![NEW 2025 EXAM - IB Physics A.2 - Forces & Momentum PART 2 [SL/HL] - Interactive Lecture](/img/tr.png)
![NEW 2025 EXAM - IB Physics A.1 - Kinematics [SL/HL] - Interactive Lecture](http://i.ytimg.com/vi/BD-ZdSNjQbQ/mqdefault.jpg)
![Forces and Newton’s laws [IB Physics SL/HL]](http://i.ytimg.com/vi/N0q10pkbxJc/mqdefault.jpg)
part two please great videos
I'm watching this before my exam and I have to inform you that g = 9.8 ms^-2 in the 2025 booklet
You are correct. 9.8 m s-2 is more accurate.
you gotta tell me man, on the 2nd activity, how did you find the reaction force (Fn) when you don't knoe the mass? Seems like a load of confusion to me
In part b, set fnet = force of friction. This gets you a result of ma = umg where “u” is the coefficient of friction. If you simplify the expression the mass “m” cancels itself out leaving you with the statement a = u*g. Hope this helps!!
@Elec2ricLearning oh that is actually busted...
@@Elec2ricLearning Yo, Electric, I got a request, could you also do Higher Level physics, like A.4 which is about rotational motion and how rotational stuff works? You are really good at explaining, and your knowledge would come in handy.
hi, could you explain why the frictional force at minute 11:45 is towards the left?
Frictional force is always opposite of applied force because friction of the surfaces of objects works to prevent objects from sliding past on another. This in essence then is working to prevent the movement of the ball to the right, meaning it applies the force to the left. If the ball was being pushed to the left, the fractional force would then be drawn to the right. It is always opposite. I hope that helps!
This is amazing
thanks for the videos! they help a lot
(p.s. we don't get the weight of the box in activity 2 so we cant calculate the friction, or am i missing something?)
That information is within the handout which you can find linked in the video description!
@@Elec2ricLearning okay thanks!