@@aryamallick5426 so (x+y)(x+z) = x + xz + yx + yz = x + x(z+y) + yz = x(1+z+y) +yz //(1+z+y)=1 since true or anything between true or false is always true =x + yz //I was literally trying to find the answer for like hours , thanks for helping me out
Amazing proof for absorption law! I love the idea of reverse distributive property
@4:35 the final answer must be 1*~B+A = ~B+A
What about this 48:6(4+4) do I do 48:48 or do I do 8(8)
Thank you! This was helpful!
(x+y)(x+z) = x^2 +xz +xy +yz. How is that equal to x+(yz) ?
X2=x
And take x common. 1 + something = 1
Apply them
@@aryamallick5426
so (x+y)(x+z)
= x + xz + yx + yz
= x + x(z+y) + yz
= x(1+z+y) +yz
//(1+z+y)=1 since true or anything between true or false is always true
=x + yz
//I was literally trying to find the answer for like hours , thanks for helping me out
bro forgot the video is about boolean algebra
04:36 there is a mistake.
te result should be =1(B'+A)=B'+A
Thank you so much.
1:35 i do not understand this
=x+(yz)
@@thankyouthankyou1172 Yea, that does not make sense to me either
feel sorry for the people in the comments who dont realize this is a video about the distributive law in boolean algebra not regular algebra lol
1.16 has a mistake it should be = x+ (y.z)