Acidic and Basic Buffers

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 61

  • @sofieberanda8587
    @sofieberanda8587 ปีที่แล้ว +28

    This video was made 8 years ago, but still an INCREDIBLE VIDEO!!! I understood more in these 12 minutes than I have in my entire 2 years of A-level.

    • @AlleryChemistry
      @AlleryChemistry  ปีที่แล้ว +10

      Thanks! Chemistry doesn't really change much at A level especially buffers, seems to be an exam board favourite!😀

  • @kemuelfavour9292
    @kemuelfavour9292 5 หลายเดือนก่อน +3

    I just understood three weeks worth of buffer lessons in 12 minutes. Allery i love you, you're a gem❤❤

  • @riki2993
    @riki2993 6 หลายเดือนก่อน +3

    you're actually the best chem teacher on youtube, and your videos are consise and quick, so helpful for last minute cramming lol, thanks so much

  • @theothompson2987
    @theothompson2987 2 ปีที่แล้ว +9

    Unbelievable video always struggled with buffers due to the questionable teaching methods by my teacher. Thanks to this man I shall walk into my A2 exam with confidence.

  • @jamesperry8395
    @jamesperry8395 ปีที่แล้ว +3

    Phenomenal video - genuinely so much easier spending 10 minutes watching these videos as opposed to trying to process the content of the text book (which are generally very poor)

  • @ntandoryan01
    @ntandoryan01 3 ปีที่แล้ว +5

    Thank you! You saving my academic life 6 years later!

  • @joannadaniel9396
    @joannadaniel9396 ปีที่แล้ว +1

    watched so many vids on the topic this defo was the best one thanks

  • @asthav3000
    @asthav3000 7 ปีที่แล้ว +6

    such a life saver!!! you make it so much simpler! thank youu :)

  • @fatimaasif929
    @fatimaasif929 ปีที่แล้ว +6

    Wouldn’t the equilibrium shift to the right for when acid is added to the acidic buffer, as the addition of H* ions will make more CH3COOH, so to counteract this change the equilibrium will shift to the right to produce more CH3COO- and H*. Could you help me out with this I am a bit confused.

    • @liamread7200
      @liamread7200 6 หลายเดือนก่อน

      i think it’s because it forms more CH3COOH on the RHS so to equal out the concentrations it shifts to the left, i’m not sure, this is how i remember it though.

  • @zakz6447
    @zakz6447 7 ปีที่แล้ว +36

    for the basic buffer when you added alkali why did the equilibrium shift to the left?

    • @ederah7983
      @ederah7983 6 ปีที่แล้ว

      Zak z I am also confused about this...

    • @sethcrockett9061
      @sethcrockett9061 5 ปีที่แล้ว +3

      Because the OH- reacts wit the NH4+ to form NH3 and water bish

    • @Nebenthez87
      @Nebenthez87 4 ปีที่แล้ว +1

      to remove the excess OH- ions from the solution and keep the pH constant

    • @ajtrott1
      @ajtrott1 3 ปีที่แล้ว +5

      Learn definitions of buffers (weak acid or base PLUS its corresponding salt) and weak acids/bases (ie only partially dissociate into H+ or OH- ions in water hence WEAK, so establishing an equilibrium/reversible reaction with them). Then apply LeChateliers principle - which is just like negative feedback mechanism in biology. Homeostasis is the term used to describe 'keeping things the same' - for example body temperature (an internal thermostat) or blood pH. Carbonic acid/hydrogen carbonate ions in blood is great example of an acidic buffer, which can resist SMALL changes in pH maintaining blood pH around 7.4 (vital to staying alive!). I hope that helps to give context for learning/understanding buffers!
      With regards to basic buffer though, you just apply LeChateliers principle in the same way as you would for acidic buffers - since XS OH- ions are added, the equilibrium must shift in the direction to OPPOSE this action(ie remove the XS OH-). So SOME (but not all) of the ammonium ions NH4 + present in solution (formed from both weak base ammonia and its salt) react with the XS OH- ions to reform ammonia NH3 (and water H20), so shifting equilibrium to the lefthand side.
      In this way, a buffer maintains a constant pH - but only for SMALL additions of acid or alkali! I hope this helps to clarify as buffers are tricky I know!

  • @omardawood376
    @omardawood376 2 ปีที่แล้ว +1

    Perfect explanation.. A tricky concept made SIMPLE! ty

  • @ayesharana9802
    @ayesharana9802 3 ปีที่แล้ว +4

    7 year aniversary of this video tomorrow

  • @missmegan9208
    @missmegan9208 6 ปีที่แล้ว

    fab video. you made it really easy to understand and I got it first time around.

  • @ederah7983
    @ederah7983 6 ปีที่แล้ว +1

    Why does the equilibrium shift to the left when you add hydroxide ions to the basic buffer? Thanks for the videos😊

  • @laysa6095
    @laysa6095 ปีที่แล้ว

    sir you are amazing !! no better explanation ! thanks a lot

  • @jamooon0
    @jamooon0 7 ปีที่แล้ว +6

    Thank you so much for this amazing video i am from ksa I well give you fallow

    • @AlleryChemistry
      @AlleryChemistry  7 ปีที่แล้ว +1

      Thanks very much! Thanks for your follow too.

    • @timothylopez717
      @timothylopez717 7 ปีที่แล้ว +1

      youaremyreasonforliving

  • @batmAN-fe1dn
    @batmAN-fe1dn 7 ปีที่แล้ว +5

    Thank you for this really useful video. Hoping to see more videos in time for exams :)

  • @mudassirraza3625
    @mudassirraza3625 6 ปีที่แล้ว +1

    Truly outstanding video you taught me better about buffer than my teacher, keep it up😌

  • @archisketch6420
    @archisketch6420 2 ปีที่แล้ว +1

    Absolute Legend!

  • @AG-ql1sy
    @AG-ql1sy 2 ปีที่แล้ว

    12:00 i dont get whats being opposed. surely if OH- reacts with NH4+ then you are reducing the concentration of NH4+ so i would assume the equilibrium shifts right to make more of the NH4+ thats been used up by reacting with OH-?

  • @rectoverso6398
    @rectoverso6398 3 ปีที่แล้ว +1

    Thanks! Really helpful

  • @CaptainAashish
    @CaptainAashish 8 ปีที่แล้ว +6

    A buffer solution means resisting change in Ph right? So when an acid(H+) is added to that solution, the H+ reacts with the COO- and produces a higher concentration of COOH? Doesn't this mean the value of Ph decreases?

    • @AlleryChemistry
      @AlleryChemistry  8 ปีที่แล้ว +6

      +Aashish_Menon Yes that's right. But remember pH is a measure of H+ ions. COOH dissociates weakly and hence does not produce many H+ ions. For this reason the pH value doesn't go lower. Hope this helps?

    • @cowardlyheroine
      @cowardlyheroine 8 ปีที่แล้ว

      +Allery Chemistry Hi, I'm really confused about a certain part in the acidic buffer section. How come CH3COO-NA+ dissociates completely? I thought that for an acidic buffer, the salt has to be weak as well?

    • @AlleryChemistry
      @AlleryChemistry  8 ปีที่แล้ว +4

      +Lilith Salts dissociate fully. The salt doesn't have to be weak only the acid has to be weak. Buffers don't work with strong acids.

    • @cowardlyheroine
      @cowardlyheroine 8 ปีที่แล้ว +1

      Thank you!

  • @hollabelle5242
    @hollabelle5242 7 ปีที่แล้ว +2

    What about mixing an excess of weak acid with a strong base?

  • @TheBala1999
    @TheBala1999 7 ปีที่แล้ว +2

    Is it not Possible to write the Two equations as one?

  • @user-wq6hr9xi2n
    @user-wq6hr9xi2n 6 ปีที่แล้ว

    Very well explained, thanks 🙂

  • @marissahosein1273
    @marissahosein1273 7 ปีที่แล้ว +7

    This video was extremely helpful to me, thank you sir and continue making videos

  • @rushvi1611
    @rushvi1611 5 ปีที่แล้ว

    Thank you for the video, however I don’t get why the solution has to be a buffer solution in the situation where e.g OH- is added to an acidic buffer, cause the conjugate base from the salt doesn’t play a role in the reaction in resisting the change in pH

  • @esotericmedic2841
    @esotericmedic2841 2 ปีที่แล้ว

    Am I correct in saying when you add an X-moles of acid to an acidic buffer, the moles of acid increase by X and the moles of salt decrease by X? ( And vice versa for adding an alkali to an acid) And then those new mole values are what you use for Ka calculations? Thank you :)

  • @nomfundisomniki2473
    @nomfundisomniki2473 6 ปีที่แล้ว

    thank you sir, great explanation

  • @MegaSuperDevna
    @MegaSuperDevna 6 ปีที่แล้ว

    Hi, why does sodium ethanoate break up readily?

  • @BinyIII
    @BinyIII 8 หลายเดือนก่อน

    Why are the concentrations of the salts low ?

    • @Suzan557
      @Suzan557 หลายเดือนก่อน

      I know i'm a bit late but.... salts dissociate very readily in solution. Just think of common table salt and how easily that dissolves in water. Due to this extensive dissociation there is a low concentration of the salt but a high concentration of its ions in solution.

  • @sandman951
    @sandman951 8 ปีที่แล้ว +2

    Don't the salts (CH3COO-Na+) dissociate completely? WHy are they represented by an equilibrium in your video? Great explanations btw! Thank you!

    • @AlleryChemistry
      @AlleryChemistry  8 ปีที่แล้ว +2

      Yes this is an assumption that is made, not quite reality. That is why the equilibrium arrow is included.

  • @daniabasit1078
    @daniabasit1078 6 ปีที่แล้ว

    Thanks a lot it really helped out🤗🤗

  • @thetwinnies5970
    @thetwinnies5970 6 ปีที่แล้ว

    hiya, just wondering you can also make acidic buffer from weak acid and strong base. How does this work?x thanks in advance for any help :)

  • @afifizwan3107
    @afifizwan3107 4 ปีที่แล้ว

    Can i ask, for the basic buffer H+ and OH- reaction wouldnt it affect the overall pH?

  • @rarain846
    @rarain846 8 ปีที่แล้ว +1

    What exam board do you base your videos on?

    • @AlleryChemistry
      @AlleryChemistry  8 ปีที่แล้ว +2

      +Rida Arain They are generic and will apply to all boards.

  • @ZiftTM
    @ZiftTM 8 ปีที่แล้ว +4

    Why must we add the salt of ammonia to the buffer?

    • @AlleryChemistry
      @AlleryChemistry  8 ปีที่แล้ว +4

      +Zift™ All buffers are made from a weak acid/base and its salt. So in this case you are talking about making a basic buffer.

  • @user-nf2su4xq4z
    @user-nf2su4xq4z 6 หลายเดือนก่อน +2

    such a cutie