Volume with cross sections: intro | Applications of integration | AP Calculus AB | Khan Academy
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- เผยแพร่เมื่อ 7 ก.พ. 2025
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Using definite integration to find volume of a solid whose base is given as a region between function and whose cross sections are squares.
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Such a beautiful explanation. For guy like me with no spatial imagination this video is a gem.
This is what years of mathematics has come full circle to, the application to the third dimension. Phenomenal explanation!
Full sphere
How long until we do 4th dimension math?
This video was absolutely incredible. I wish textbooks would just use your videos
Amazing explanation. Khan Academy is alright at teaching people arithmetically (at least in physics), but they’re sure as heck great at explaining concepts.
Thank you to whomever had the idea for this video, it really helped.
Your drawing skill is so amazing...
The exact video to my requirement, finally got it after a long quest.
I love you
You make math so easy to understand for me. 💜
Amazing explanation and equally amazing drawing! Cleared it up for me really well!
Wooow! His drawing skills is better than most artists today! 😂😂
You have got a great drawing skill sir!!
In layman's terms: Integral from Xi to Xf of ((f(x) - g(x))^2) dx
This video got me hyped to do math
absolute perfection
(top minus bottom)^2 from 0-2
He makes it sound so easy 😂
Absolute god-send. I thank you good sir for taking your time to explain this.
thank you
why is this video so satisfying to watch lol
Thank you so much Bro. You are my hero
Wow man you are amazing
your drawing is satisfaction
Wow thanks!
Can you do it for 4 object?
Thank you!
thaaaank you
Whatis the formal name for what we calculated ?
I mean the volume of what ?
Good!
this is a great video but at the end of the day why do i need to know how to do this 😭
Isn't volume = double integration? i don't get why here you use only 1 integration, the result you found is the area isn't?
Sometimes i feel ur examples not like ours😂😂😂😂😂
that is not in my book but has the same name
PAIN
hey where can I find that calculator :(
just look up download for ti-84
how about sir if my concern is only the equation that describes the cross sectional area at x = 0 to x = 2 ??
how to find that equation?
Nice video.
I wonder if Sal ever responds to a youtube comment. :>
Fredde I guess not 😂
「どうやってやるの？」、
i have to do this for school and like, good explanation but i still understand none of it