Non Perfect Square Root निकालने की सबसे शानदार Trick | Vedic Maths
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- เผยแพร่เมื่อ 5 ก.ย. 2024
- We can easily find square root of perfect squares but in case of non perfecr square root like √19 we got stuck. Through vedic maths tricks we can easily find square root of non perfect square roots in not more than 5 seconds.
Short trick to Get √17 in just 3 second
Follow these Steps :-
We know the Non Perfect Square root number like √16 , √25, √100, √144 etc.
Now, we have to Find the square root √7
So, we have follow this method:-
Step 1:
To Find the square root we divied. the number into nearby perfect square number and non -perfect square number like √9-2
Step 2 :
Now put the value in this formula
√x+y = √x + y/2√x
√9-2 = 3 + 1/2 x 3
= 3.16
So solve this and get the answer of under root 17 .
Therefore , √7 = 2.67
so Final answer is 2.67
This method is very easy to find non perfect square root
More example -
√10 = √9+1
√9+1 = 3 + /2x3
= 3.16
This trick is basically from chapter application of derivative of class 12thmathematics. it is a small part of the topic approximation. That formula come after we differentiate the root x by basic differentiation. by this method we can find approximate many other functions like cube root , x raise to the power 1/4 and so on.
These Fast Maths tricks will help you solve the Questions asked in the Quantitative Aptitude Section of the various Bank and Government Exams like RBI Grade B, SBI PO, IBPS RRB Officer, SSC CGL, SSC CPO and Railway RRB Exams. All such exams require candidates to solve a high number of Questions in Less Time.
Square Root of Numbers that are Not Perfect Squares
Remember this formula which is given below:
Using this formula we can find any nonperfect square root.
Example 1: √5
√5 we can also write √4+1. Therefore, 4= x and 1 =y
According to the formula: x is always a perfect square, Like here 4’s perfect square is 2.
Then, √4 + (1/2√4) =2 + (1/2*2) = 2+ (1/4) = 2 + 0.25 = 2.25.
Hence the answer is 2.25.
Example 2: √14
√5 we can also write √16-2. Therefore, 16= x and 2 =y
According to the formula: x is always a perfect square, Like here 16’s perfect square is 4.
Then, √16 - (2/2√16) =4 - (2/2*4) = 4- (1/4) = 4 - 0.25 = 3.75.
Hence the answer is 3.75.
Keywords:
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Thank You...
My god first time TH-cam has recommended a very useful video 😄
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
Correct
Same here
Yup😂
Exactly
CBSE should also include Vedic Mathematics as an extra subject for small children ..
Chup chutiye yaasehi chote bache normal math hi handle nahi karpatai
Rbse me pahle ye kuch years tha but ye vedik methamatics nhi hai ye to bus normal si tricks because vedik time me 0 नहीं था
they will never 😒
@@its_culture_boy2943 .....kya?
0 tha vadik mathematics me
Vashishth samhita me use hua hai zero ka
"Haha you andhbhakt " some random liberandu
For those wondering how this works, here's an example.
19 = 16 + 3
19 = 4² + (2*3*4)/(2*4)
19 = 4² + 2*4*{3/(2*4)} + {3/(2*4)}² - {3/(2*4)}²
Now on RHS, the first three terms form a perfect square identity.
19 = {4 + 3/(2*4)}² - {3/(2*4)}²
You can ignore the last term on RHS as we are finding "non perfect roots"
√19 = 4 + 3/(2*4)
And this is the formula he said in the video.
Same logic can be applied on any number you want.
Sincerely, an Indian student. :)
Nice work!
Like this explanation a lot 👍😀
Op bro
@@anjugupta9488 it's very small...
@@anjugupta9488 Because as compared to the first term, it is a small value. You could technically go on expanding to get a closer answer but I didn't bother doing that because of the formula he used in the video.
मैं इस चैनल पर राजीव दीक्षित भाई साहब का वैदिक मैथ का तरीका सुनके आया हूं, गुरूजी सच में बहुत ही शानदार शूत्र बताए है आपने ये हमारी प्राचीन गणित विधि है और बहुत ही उपयोगी है।। आपका बहुत बहुत धन्यवाद।।
Ma bhi
Same here 😊 Rajiv Dixit amar rahe ❤
Am also
I am from Telangana State board... And my school started Vedic Mathematics for Classes 4th to 10th mandatory for everybody. Difficulty increasing for every standard. I was in 5th during that and now I am in 12th .Classes being taken twice a week and regular exams included in quarterly and half-yearly too. This was just particular my school having extra curriculum.
Personal👆 number lene ke liye WhatsApp karo👆......
wow! that's great!
hey can you tell me which school you studied in and about the study material they provided
OMG !absolutely fantastic.....it will help tremendously in competitive exams....👊
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
@@serdalhocailematematik1930 th-cam.com/video/3Zp8s4_fGEU/w-d-xo.html
Yes🤣🤣.... I helps alot
@@animekshokeen3301 th-cam.com/users/shortszatCVTRINLE?feature=share
Bhai caclulation kese krni a
Ans-
√83=9.11
√105=10.25
√129=11.3
√171=13.07
Really great video sir.... Power of vedic maths can never be Understimated ..... Thnku so much sir😊
thank
√3 ka nikalo
@@factandeducationhubomsharm5260
I already solved...
√3=1.75
@@factandeducationhubomsharm5260 1.5
@@factandeducationhubomsharm5260
I tried.. Lekin single digit k liye ye work nhi kar rha h 😐
Answer is coming out to be 2(using this method) lekin approx value is 1.732(i remember this lol!)
Under root 83 is equal to 9.11
under root 129 is equal to 11.3
under root 105 is equal to 10.25
under root 171 is equal to 13.07 .
Its within root not under root.... By the way you have done perfectly...
@@reality1496 no it's under root
Are मूर्खों कुछ भी बोल lo karna to wahi hai na...
@@user-wl9hx4qp7l Wahi yaar.
Bro isko solve kaise karna hai
Thanks very helpful video❤
The ans of the questions are :
√83 = 9.11
√129 = 11.3
√105 = 10.25
√ 171 = 13.7
root 11 value is 11.36
OMG 😱 Vedic math should be a subject in schools. Thanks 👍 it help a lot.
Class 12 cbse maths me hai
√83~9.11
√105~10.25
√129~11.36
√171~13.076
I have found a so knowledgeable video... Keep it up sir👍👍👍
Correct , I have also done it 👏👏👏
105 ka samajh nahi aaya
This shows knowledge and feel of early Indian Mathematicians.
🗣️
⁸⁹⁵⁰⁵¹⁹⁶⁵⁶,,, ok.....
Happy New year sir
Really Great Video Sir. Power of Vedic Maths Can Never Be Underestimated 💪
Bro, this chapter is already teaching on. In 12 th class chapter name Approximation.
@@user-of9ug7or1t ok !!
@@user-of9ug7or1t approximation is based on differentiation. And that's a long method to solve such roots. Plz Don't mislead, I'm seeing your same comment in all chat boxes.
@@Omega_Plus849 right,I m in twelve now ,
Brilliant
हमारे वेदों और पुराणों और उपनिषदों और रामायण और महाभारत को काल्पनिक बताकर हमें अपने इतिहास से दूर रखा गया है ताकि हम आर्य है वह कभी भी जान ना सके। लेकिन आज हम आप जैसे ज्ञान के उपासकों की वजह से हमारे पूर्वजों के सच के करीब पहुंच रहे हैं। सनातन धर्म की जय 🙏🙏। हर हर महादेव 🙏🙏
Under root 83 is equal to 9.11
under root 129 is equal to 11.3
under root 105 is equal to 10.25
under root 171 is equal to 13.07
also the trick was good and makes calculations easy
thank you
U r right
Your math is too good👍👍
Bro, Under root 105 = 11.35 (calculator)
Or 11.5 (Vedic Maths)
Ye kaise kiye ho
Mere ko bhi batao
It's a very useful trick to gain the answer of non perfect square
Bahut hi achhi jankari aap ne dee.dhanyabad.
This is the power of our Sanatan Hindu Dharma 🚩🙏🏻 🕉 which people in the world are underestimating.
Thank u For such a great knowledge 🙏🏻
You're right that this is a very useful Vedic maths trick, but hindu dharam has nothing to do with this. Even Muslim mathematicians like Al' khwarizmi discovered algebra. Thank all our ancestors, not just hindu mathematicians
@@arxalier2956 plz study Vedic Mathematics deeply, then u will get me what I am trying to say :)
@@arxalier2956 al khwarzmi didnt invent algebra lol.. He copied the work of Bhaskaracharya , translated and modified thats all dont utter bs
@@byron-ih2ge source?
@@thorstark4114 those peimitive arabs and their primitive cult was devoid of anything known as maths but then they imvded india.. The caliphate was sucessful in capturing " SINDH" and when that happened thats when they unserstood whats maths is for real..
To understand why it works. This is truncated taylor series approximation.
F(x) := F(a) + F'(a)(x - a)
So, if F(x) = √x
Then, F'(x) = 1 / (2√x)
√x := √a + (x - a) / (2√a)
Mujhe toh Taylor series ka itne application hai patahi nhi tha
saala sab kuch indian logon ne khoja tha lekin sab angrej le gaye
@@rishiloona2409 Language is also of Indian origin. Sanskrit is the mother of all Indo-european languages.
Small examples:
Naam = Name
Matru = Mother
Bhratar = Brother
Vividh = Vivid
You can find many such examples. The existence of dual, not just singular and plural in Sanskrit, compared to partial existence of dual in Latin, explains a lot.
Though I think some people reinvented certain concepts independently and credit should be given to them as well.
I would say this what westerners did was they robbed the colonies not only of their wealth but also ideas and culture. They also erased a lot of our culture.
Search for Madhava Of Sangamagrama. He was studying and teaching infinite series and calculus way ahead of newton and leibniz.
@@nishantshelar8887 arre mene bhi wahi likha hai ki sab kuch indian ne dhoonda lekin angrej sab le gaye
@@rishiloona2409 Yes, wanted to give you more info. 😊
Thank you Thank you Thank you So much Sir.... Aap ke jaisa easy me aajtak koi nhi mujhe Root nikalna sikhaya ❤️ Thank you So much Sir ❤️
Bahut achhi video hai Bhaiya.....
Ab tak TH-cam ne sabase achha video recommend kiya hai...👌👌🤩🤩🇮🇳🇮🇳
This kind of math is been taught in +2 level in the form of approximation. f(x+delta x) = f(x) + f'(x)* delta x is the approximation formula for any function.
Yes... Everyone steal from India
What is Delta??
Yepp.. right
∆
@@ideoamay3594 ∆
I don't know how to thank you, I had watched many videos but not even a single one is totally applicable but this one is awesome, it's help me a lot. Thank you Brother for this ❤
Personal👆 number lene ke liye WhatsApp karo👆......
Nice, Just loved it Sir!!! 😊😊, And Again nice job ✌️✌️👍👍
1. 9.11
2. 11.36
3. 10.25
4. 13.076
I Have done these by your given method, the question you gave us at last...... ✌️✌️😄😄
Well done!
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
My deep heartily regards to Vedic mathematics. It made my work simpler by not only this method but also several other methods.
Personal👆 number lene ke liye WhatsApp karo👆.....
Bhi meme apni jindagi me pahal asa youtuber dekha h jo vadik mathes ki trick sikhakar apni sanakriti aur apne vedo ke prati logo ko sikha raha h 😙😙😙 Thank you
Sir Literally Maja Aa Gaya
√83~9.11
√129~11.36
√105~10.25
√171~13.076
Thank You So Much Sir ☺️☺️
Aapka 105 ka root wrong aaya hai root 105 ka answer 10.24 aayega
10.25 aayega
@@Dghbkjfg Oh 😳, Yes Galti Ho Gaya
It's ok ☺
When I was in school vedic maths was an extra subject in our syllabus. Ya it's a very convenient and easy learning process of maths. It should be a part of presents syllabus of primary class children.
100 % श्रद्धा👌
Yes ✅👍
Bhai kuch bhi ye vedic maths nai hai... Ye class 12 ka approximation chapter ka hai jiska isne bas ek formula bana ke rakh diya hai...
If you are in class 12 you can realise that you can find cube root or any nth root of any number with this method....
Aur please ye vedic maths mat karo... Jo method easiest hai usko follow kro
@@omdave1008 wo aya kaha se? Roots to ye hi hai na bro...
Sir this is a amazing formula
It will help us all
Thanks for teaching this trick🙏
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
Thanks Mr Parekh
Custom me aa 1 vs 1 freefire
Sir Jabra Fan Atishay Jain
Aapki ine Vedic maths tricks ki vajah se meri calculations itni fast ho gai hai ki class mein sab log mere ko calculator bulate Hain thank u veri Mach...
❤️
I also have a book of vedic mathematics. In that the method is~
Lets take example √19.
nearest perfect square 4 and divide 19 by 4. The 2 numbers you got are 4 and 4.75, and then you just get average of two numbers which is 4.375
Bhai kaisa chodu method hai yeh? Divide krke average nikalne baitha na itne mein toh saamne waala game Baja daalega apun ka.
@@rameshsuresh6409 upto you bro, I am just trying to tell what I read in a book.
@@abhishekagarwal1899 Oh ok i am sorry. ❤️
हमारे भारतीय संस्कृति कुछ कम नहीं है ❤️🇮🇳
Please forgive me if any grammatical mistakes🙏
Or same can also be derived via differential calculus.
Take y = x^1/2
dy/dx = 1/(2 x^1/2) = ∆y/∆x
Say for (19)^1/2
=( 16+3)^1/2
Say x=16 and ∆x =3
( Remember ∆x
only a jee aspirant can apriciate this , and i appreciate this
Yes it does not work for finding root of 3
@@mohitmehla6375 yes this trick gives 1.75 for root 3 approx but not accurate
Thankyou sir.............
Approximation!?
Its not a precise method but still for fast calculations especially in numericals it will be so useful🔥
@Babulal but you can't use it in exams 🙄
Precise method?
Nobody writes the complete square root with all decimals in exam
@Babulal yo i know but you don't need to write the precise values in exams😉
@Babulal bruh i got 91% in this year only 😁
@Babulal ok bro thnx it will be a honour for me 😂
आपके द्वारा प्रेषित विडियो मेरे लिए बहुत लाभदायक है ,मै कल ही अपने विद्यालय में अपने छात्र छात्राओं को अवश्य बताऊंगा और सिखाऊंगा भी
उम्मीद है आप भविष्य में भी ऐसी ही ज्ञानवर्धक विडियो बनाकर हमारा मार्गदर्शन करते रहेंगे
धन्यवाद
We are so proud on our ancestors and rishimuni 🙏🏼🙏🏼🙏🏼 to produce Vedic math
We are already advance in our civilization
Personal👆 number lene ke liye WhatsApp karo👆......
√83=9.1
√105=10.2
√171=13.07
√129=11.3
Well done!
th-cam.com/video/I8Uvzu0RShI/w-d-xo.html
Abe nehi hua √83 ka kese kiya
Google guru ha 🧠🧠😀😀😂
83 ka 9.1 kaise aaya
Ok if try to find anything square root , cube root
Then use...
f(x+∆x)=f(x)+∆x.f'(x)
Where f'(x)=Differentiation of f(x)
If u find out sq.root of 19 then
f(x)=√x. f'(x)=1/2√x
x=16. ∆x=19-16=3
Then put all in
f(x+∆x)=f(x)+∆x.f'(x)
If u find out the cube root of 9
Then
f(x)=x^⅓. f'(x)=1/3x^⅔
X=8 and ∆x=1
And u also find out log and many other functions too...
I.e. only for small ∆x
N to bhari error ki sambhavna hai😂
@@satyamev_jayatey_ 👍
Is this numerical formula ok?
@@mathsrelated this formula is in ncert 12th science course
Ok... I'm from bsc mathematics course😀
Under root of 83= 9.11
Under root of 129= 11.36
Under root of 105= 10.25
Under root of 171= 13.076
Bhai solution batao na 😭😭😭
How sqrt of 129is 11.36 , i am getting wrong answer . By the rule its 11+(8/88 ie 0.0909090...) so my soln is 11.09090... how you are getting .36
How to find √404.41?
@@SAZZ3DM how are you getting it would be 8/22 you have to multiply by 2 everytime
@@kelp3474 nah in denominator , you have to multiply the remaing ie.8 in this case with the number you've done square of in this case 11
Apne bahut ache se square root nikalna btaya bs aise hi video bnate rho or aage bdte raho
Aisa pehli baar hua hai ki koi video nahin Dil chhu liya abhi math class ka
Seriously amazing trick derived by ancient Indian mathematicians.great video too 😀
OMG. 😀😀
End mei 4 questions toh chutkiyoon mei hoo gye..
Amazing broo👌👌👌👌👌👌
Pehli baar yt nei koi achi cheez recommend ki hai 😀❤️😊
This video is very helpful to me, thanks sir😊
अद्भुत, वैदिक गणित द्वारा अत्याधिक सरल, सटीक और तीव्र गति से प्रश्न हल किये जा सकते हैं।
Alhamdulillah kya mast information batayi hai...
Nice 👍👌👍
Sir,pls make videos on how to know decimal no. are the square on which no.
-( the reverse of this vdo)PLZ🙏🏻
This vdo is very helpful for us🖊️📕
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
@@serdalhocailematematik1930 th-cam.com/video/HwtmaGEI3F0/w-d-xo.html
Hey bro!! Excellent video! Just subscribed to ur channel. This will be a gem for my JEE exam now.
Just one error was there. In square root of 19, by Vedic method, it comes 4.375 which is ~ 4.4, and by calculator, it comes 4.358 which is ~ 4.4, so instead of 4.3 it would be 4.4 (method was correct, just it should be 4.4 instead,) thank you!
Significant Figures ka khel h bhai ye sab.
This method relies on binomial approximation.
The method here approximates the root by only 1+nx (where highest power of x is 1), so if you want greater approximation, you will also have to work with higher powers of x (like square, cube, etc).
So it is not really an error. It's just approximated.
Working of root19-
root19=root(16+3)
=root(16(1+3/16))
=4 x root(1+3/16)
=4 x (1+3/16)^½
=4 x (1+(1/2 x 3/16))
=4 x (1+3/32)
=4 + 3/8
~4.3
@@tanishdesai7652 nice one keep it up 🔥👍
Bhai this formula works beautifully when u r nearer to the perfect square since it is based on approximation using graphs more the difference more error is introduced but u can get it correct to first place
@@Trolex6969 if u take 25 insted of 16 then the answer will be 4.4
thx a lot for this amazing technique
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
Thanku very much kal mera quiz h or ye video dekh kar mujhe Aisha feel ho raha h ki main hi 1st laungi again thanxxxxxxxxxxxx
Bahut shandar aur saral tareeka .thank you sir
I watched this video a year ago and now i felt this was very helpful in exams and for whom who always forget square roots ! This is gonna help me in my exam . I appreciate you sir . Thanks 🙏
Good content, you provided us friend
The result obtained by this method is very approximate and differ from the actual value by less than 1 .
Keep it up.....
Personal👆 number lene ke liye WhatsApp karo👆.....
Happy New year sir
My god You are the life saver that will help me in my 10th Board exam ...
Rajiv dixit ke advise per aaya hu sir. This is very nice and helpful for each student
Thanks for providing such valuable information
this is going to help me to solve JEE questions
Mera bhi same purpose h🥰
Ary ye tu nursery ka concept hai
@@physicslover9701 hamare board me nhi padhayi jati vedik maths
@@yashubanna776 agr app jee advance ki preparation karte hona tu ye concept clear honai chahiye
@@physicslover9701 mains par h jyada focus.
Thank you sir, from the bottom of my heart ❤️❤️❤️
This technique is not ACCURATE but Very Useful For JEE and Various Competitive Exams🤟
Answer of your questions...
√47 = 9.1
√129=11.3
√105=10.2
√171=13.01
Thank you for this knowledge...
It's very useful and time save method. Thanks 👍
Really appreciating... ❤❤
😇
Satya sanatan vedic dharm ki Jai 🚩
this is basically a method which I studied in class 12
That is f(X+ delta x) = f(x) + derivative of f(x) * delta X
->Where f(x)=sqrt of X equation (1)
Here f(9)=3 &
Derivative of f(X) = 1/[2 sqrt(X)]
Then put the value of X=9 in above
We get derivative of f(9)=1/6
Put the value of Derivative of f(9) in equation (1)
Therefore of f(12)=3 + 1/6 * 3
= 3+ 0.5
=3.5 (actually it is 3.464 by using calculator)
👍
Very good 👍
@@saur202 Thanks 😊
Nice Explanation bro 👍
Aapko nai lagta ki school mai jo hai Vedic maths implement karna chahiye isse logo ki IQ aur enhance hogi.
@@patelsetu145 yes
In class 12 this Q is easilty done by differentiation.....hatts of our indian mathematicians ❤️
Ye video itni aachi hai ki ,,isko share karne ka man hi nahi kar raha,,,competition aur badh jayega 🤣 ,,also i want to share
This method relies on binomial approximation.
The method here approximates the root by only 1+nx (where highest power of x is 1), so if you want greater approximation, you will also have to work with higher powers of x (like square, cube, etc).
So it is not really an error. It's just approximated.
Working of root19-
root19=root(16+3)
=root(16(1+3/16))
=4 x root(1+3/16)
=4 x (1+3/16)^½
=4 x (1+(1/2 x 3/16))
=4 x (1+3/32)
=4 + 3/8
~4.3
Yess bro
Your mathematics playar ok
@@yugyt2185 r u Baria?
Arey Shi pakdyy hoo.
Binomial approximation is very useful and Good approximation.
Yep
So useful Sir! Thank you so much🙏❤️. Sir can we find the root of all prime numbers this way especially single digit prime numbers?
Personal👆 number lene ke liye WhatsApp karo👆......
It's good and very cool! But the problem is the approximation is only correct upto 1 decimal place, so it's not THAT useful but it's decent.
This is the best channel I found which nicely describes vedic maths
This video is very helpful to solve sums in math
Very helpful......vedic maths should be included in the syllabus.
You saved my time in exams
This is an application of Derivatives where we use derivatives to determine square root of non perfect number
😁
Can you explain bro! Plz
Badia h aur kaam ka content.... Good recommendations by TH-cam
Stay Safe
Stay Blessed
Best vedic maths video on TH-cam.....👍😃
Thankyou
This technique is thought to us in Application of derivatives..😀
Amazing❤️❤️
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
This is called method of approximation,in
AOD chapter of class 12.
Haa bro approximation application of derivatives 👌👍
Wow ..I got answers for all ..Amazing way ...Thank you for sharing this valuable trick
Amazing sir l never saw such incredible tricks
Keep it up sir!!
👏👍👍👍
Personal👆 number lene ke liye WhatsApp karo👆.....
Sir ji its a formula, √x±y=√x ± y/2*√x.
My math question
th-cam.com/video/HAvPTV5zQP0/w-d-xo.html
Sir, I got for root105 = 10.1,
But in the calculator, root 105 = 10.2 came.
Plz , help me I'm confused for these differences.
Bro calculate it to 2 decimal places and then round it off
Ok, ThanQ, sir
Calculate again. Your calculation mistake
hey guys 😀😀
notice 1 thing in plus sums like root 19 is equal to 4 + 3 / 2 × 4 is equal to 4.3
see focus on 4 + 3 just we have to remove the plus sign and add the point sign same in case 2 in video
hope this helps .🥰🥰
love u guys 😁😁😁
Yes bro
You are a genius
But not a accurate number
@@piyushdhakad934 Thanks brother
Thank you shri jagadgur shankaracharye bharti krishan ji to give us vedic maths
Vedic mathematics subject is included in VIDHYA BHARTI school, and I proud to be a part of the AVM school
BUT HOW CAN WE CALCULATE THE SQUARE ROOT OF DECIMAL NUMBLERS LIKE 22.5,30.9 ETC...
separate them like sqrt.2250/100 for 22.5 and sqrt.3090/100 for 30.9…
Ok
😱😱😱😱😱😱😱
This is the first principal of differentiation.
f'(x) =(f(x-h) -f(x) ) /h
f(x-h) =f(x) +h×f'(x)
No doubt Vedic Maths is just awesome dear. But this what you shown here is Newton Raphson. Not everything under the sun is Vedic Maths.
Bohot jayad hi helpful video.... thank you sir 🙏
Thanks it will help in my competative exam
Thankyou for giving questions..
What a nice trick sir 👍👍👍Thank you very much sir🙏🏻🙏🏻🙏🏻🙏🏻
Sir thank u for teaching this short cut trick. Really i am happy.
I was asked question of square root in an interview and I was unable to answer the question however with this trick it is very simple to answer the question based on square roots.
Personal👆 number lene ke liye WhatsApp karo👆......
I was recommended by you tube now I'm new subscriber here 😄..very informative educational channel
Sach mein education channel
This is apllication of derivative in Calculas . Calculas is very interesting and conceptual branch of mathematics
Nice ..it is expansion of binomial theorem upto first two terms (a+b)^n = a^n *(1+ b/a)^n = a^n* (1+ n*b/a) , put n=1/2 ( ie , b*a^n/(2*a)~ b/2* sqrt(a))!... I used this in JEE times... 20 yrs back...!!
For the first time TH-cam recommend me a very useful videos 😊
Very nice trick to find square root, thanks for sharing