Mam if we check the number of moles it is decreasing in case of CO to CO2 which means it is negative, so randomness decreases, so entropy also decreases. Acc. To the thermodynamic eqn, change in Gibbs energy is positive even for low or high temp. But if you take in case of C to CO change in Gibbs energy is negative at low and even in high temp. So coke is the best reducing agent. In CO the rule number 2 that u gave for priority is ruled out!!!!!
Your doubt is that C->CO ....{1}. stands below FeO line than CO->CO2.....{2}. then why the answer is CO. But {1} stands below FeO line at higher temperature & {2} stands below FeO line at lower temperature Point is to give priority to lower temperature.CO->CO2 is better as :- *It is at lower temperature (since low temperature is favourable) *It's 🔺G value is negative at lower temperature. Hence {2} is better R.A. 🙏
yeah, it is increasing among the three but it is still below 0 so, at temperature below t co is the best reducing agent and above temp t c is the best reducing agent . GOT IT!
I'm confused , doesn't point 2 say that lower Gibbs energy is preferred and yet why do we choose co which is showing a non spontaneous reaction. Please help me.
hai maam in this vedio u said that co is gud reducing agent but maam it is having positive g value.......right? then how thatz possible maam!! plz give me an answer!!!
But Mam in previous video you told change in G is + for slope upwards... And - for slope going down ......and in this you chose the one which has a positive value of change in G
Bro, delta G is +ve when compared to the three carbon and oxygen reaction but actually deltaG=0 lies above all the three reactions .therefore , all the three reactions comes under spontaneous reactions only [please refer ellingham diagram in ncert] . now, solve the question as per the mam trick
Mam as u said deltaG is increases it is. Positive so it is non spontaneous but in the given example u have taken deltaG as spontaneous hw mam cpuld u explain plzz..?
Zinc is costlier metal know,so commercial always we have to go for the one which is easily available at cheaper rate.so we are preferring CO and coke as a reducing agent
Acc to the 2nd point that you gave in the last vedio.....in the graph with reaction G^o=-ve should be considered as reducing agent!! And here c gives co has negative slope hence it has negative G°. Why c is not the answer ???
Bro, that is when compared to the three carbon and oxygen reaction but actually deltaG=0 lies above all the three reactions .therefore , all the three reactions comes under spontaneous reactions only [please refer ellingham diagram in ncert] . now, solve the question as per the mam trick
I think co is best redusing agent below temperature T but coke is better redusing agent after temperature T.
But we should consider lower temperature only so CO is best
Coke only I guess
if you want to save money you need low temperature thats why CO
@@sathvikmalgikar2842 1 st video dialogue , 😁😁😁
Topperr 🙄
Mam if we check the number of moles it is decreasing in case of CO to CO2 which means it is negative, so randomness decreases, so entropy also decreases. Acc. To the thermodynamic eqn, change in Gibbs energy is positive even for low or high temp. But if you take in case of C to CO change in Gibbs energy is negative at low and even in high temp. So coke is the best reducing agent. In CO the rule number 2 that u gave for priority is ruled out!!!!!
Your doubt is that C->CO ....{1}. stands below FeO line than CO->CO2.....{2}. then why the answer is CO.
But {1} stands below FeO line at higher temperature & {2} stands below FeO line at lower temperature
Point is to give priority to lower temperature.CO->CO2 is better as :-
*It is at lower temperature (since low temperature is favourable)
*It's 🔺G value is negative at lower temperature.
Hence {2} is better R.A. 🙏
S bro same doubt with me
Did u get the answer
Can u plzz tell ultimate answer plzz
Thanks bro I owe you
Thanks vro,after lots of confusion, I get it🙏🏻
Mam how can we determine at intersection point
Ma'am I just discovered today .
The best explanation ma'am.
Thank you so much
Mam u r very nyc person we need ppl like u in our society .....at some point u create doctors n engineers n wat nt
good explanation
Mam but in this case the Gibbs free energy is increasing of CO so how can we say that it is the best reducing agent?? Plz explain mam..
yeah, it is increasing among the three but it is still below 0 so, at temperature below t co is the best reducing agent and above temp t c is the best reducing agent . GOT IT!
I guess coke Is best reducing agent as Gibbs energy is less than 0
Don't confuse trick with actual theory
Friends only use trick one becuz trick two fails here as all of them has same intersecting temperature on graph
Mam i am studying 12th at now ur vedio is helped me to understand the concept can you please upload more on my 12th syllabus
I'm confused , doesn't point 2 say that lower Gibbs energy is preferred and yet why do we choose co which is showing a non spontaneous reaction. Please help me.
Check the intersept given in the diagram come is below the feo hence it is best reducing agent
mam but C has more -∆G as the graph is downward
Thanks mam it will be more help ful if u present objective section more thanks a lot mam
OK mam I just got confused 😅😅
PLEASE REFER ELLINGHAM DIAGRAM IN NCERT.
Mam change in gibbs energy is + ve for CO then how can it be a good reducing agent
hai maam in this vedio u said that co is gud reducing agent but maam it is having positive g value.......right? then how thatz possible maam!! plz give me an answer!!!
Thank you mam it's very easy to understand
Mam at higher temperature C has negative Gibbs free energy.therefore it can act as best reducing agent at higher temperature
Mam but CO is having postivie value of gibbs energy so how can it be a good reducing agent as compared to C. Plzz explain mam....
but when it reverse it becomes more negative and ...it can be used as the best reducing agent .....in my understanding......
But Mam in previous video you told change in G is + for slope upwards... And - for slope going down ......and in this you chose the one which has a positive value of change in G
Vijay Wadhwani give priority to low temperature
@@pradeepchaudhary6028 okk
@@pradeepchaudhary6028 but how can we determine at the intersection point ....both CO and C are reducing at the same temp
Thankyou so much mam . God bless you and your family.
Mam plz expain about inductive and mesomeric effects
mam question is incomplete. u didnt say for which temp? if temp is above T then c is best reducing agent. if it is below T then co is best one
Nice one ...🙎♂️
Really nyc
Nice maam
Superb Explanation for ellingham diagrams ❤️thank you mam
Mam we always consider 🤔💭 low temp.. Right?
Thank You
You told wrong because co is +G but you told -G for co,you told it is reducing agent how is possible it is+G know na
What is +G and - G?
@@KomaliMam +G positive Gibbs energy
-G negative Gibbs energy
Yes CO is postive G , C is negative G
Mam but co has positive gibbs energy
Mam but the intersection of graphs Coincide at temperature T also delta G is +ve for CO.....??? I'm totally confused...
Plzzz help mam
Thanks
Bro, delta G is +ve when compared to the three carbon and oxygen reaction but actually deltaG=0 lies above all the three reactions .therefore , all the three reactions comes under spontaneous reactions only [please refer ellingham diagram in ncert] . now, solve the question as per the mam trick
bro this link was not opening
Solve the question with the help of 1st trick.
Jo C------>CO2 h na vhan pe ∆G =0 h
Us line se niche jo bi line hogi uska ∆G=negative nd iske above ∆G=positive
Very nice ma'am
Mam C is best reducing agent
Self testing question answer is CO because ∆G =-ve
Helpful👍
Mam but co is higher than feo right mam
Then??
Mam as u said deltaG is increases it is. Positive so it is non spontaneous but in the given example u have taken deltaG as spontaneous hw mam cpuld u explain plzz..?
Super
Thanks a lot mam it's really helpful
Mam right side of the graph can also be considered na mam 😇😇🤔🤔not understood mam help me plss
Super mam
Bt usme to zinc oxide sbse niche tha hm to usko consider karte hen Jo usse niche ho previous problem me coke kese hua
Maam plz clear our doubt
Zinc is costlier metal know,so commercial always we have to go for the one which is easily available at cheaper rate.so we are preferring CO and coke as a reducing agent
But if what if mentioned after the temperature T1 suppose then
Thanks a lot mam
Thanks MAM 🙏🙏🙏🙏🙏
Tq mam
thanks a lot madam
Acc to the 2nd point that you gave in the last vedio.....in the graph with reaction G^o=-ve should be considered as reducing agent!!
And here c gives co has negative slope hence it has negative G°. Why c is not the answer ???
Same doubt sandhya
Did you get the answer
If u get it plzz reply
Thank you so much mam
Tnnkkkkkkkuuuuuuuuuuuuuuuuuu mammmm love uuuuu🥰🥰🥰🥰🥰🥰🥰🥰🥰
superbbb
nice work keep going
Thank you 💕
At different temperatute different reducing agent will act
Madam i doing metalurgy course if possibility is there do videos on mechanical metalurgy
Thank u mam
Ma'am can u plz make a video on organic chapter haloalkanes and haloarenes as I have my exam in 2 days and I am reliable on you. Plzzzz
next nearest atoms in FCC and ccp vedio mam??
Thanks mam...
Mam kya ap ek clip bana sakte ho suplimentry exam ke liye kuch important quation di jiye jisse pass ho sake
thank u, mam......
mam please explain cast iron in engineering
good explanation....but if uwill
CO is best reducing agent till temp T after then C is the best reducing agent........
Hope someone's doubt has been cleared......
😂😂😂😂
Do more videos on metalurgy madam
Trick is Niche wala upervale ko reduce karegaa😀😀
Bt ma'am with co the reaction will be non spontaneous...
Bro, that is when compared to the three carbon and oxygen reaction but actually deltaG=0 lies above all the three reactions .therefore , all the three reactions comes under spontaneous reactions only [please refer ellingham diagram in ncert] . now, solve the question as per the mam trick
Nice but at the point of intersection is not considered?????????????
Graph is wrong though
All of them don't meet at same point
Graph what I gave is correct. Please cross check again.
Mam plz start a crash course so u can reach 1million subscribers
PLEASE UPLOAD SOLUTION OF QUESTION ASKED IN JEE-MAIN 9TH JANUARY FROM ELINGHAM DIAGRAM, PLEASE MEM
Why are u ignoring our doubts mam😢😢😢😢😢
Hloo
In the above problem
Co is @ higher pstn than feo right
So v can't consider it
Plzz bro reply
@@Shruthi003 No, CO is below FeO line before their cross point
@@niranjannimbalkar2612 okay thnxx bro
But if u look @ the comments most of them r saying that mam answer is wrong
@@Shruthi003 mam's answer is correct but her trick is confusing
@@niranjannimbalkar2612 ohkk bro😁 tq so much 👍
Nahi Aya mam
CO
Phle apne concepts clear kro maam jaakr 😐
Sir see her previous video u ll understand better .
Thank you mam
thankyou mam