Series of (1-1/n)^(n^2), root test

[@Kayy_SS]

dang, im going to take Cal II final exam tomorrow and i just now know about the fact (1+1/n)^n = e. thanks a lot, blackpenredpen, at least I am not too late

[@blackpenredpen]

Best of luck Son K.

[@yunalee7231]

can you also show how to do the one where you have to e^ln[f(x)]^g(x)??? pleaseeee

[@faboleo1]

broo deserves a nobel prize

[@aayushinauhwar6643]

thank you for saving my life

[@zack_120]

Concise which is the heart of math !

[@20PercentMilk]

Converges to about 0.1046!

[@nanotw2089]

So the row (1-1/n)^n² diverges cuz it isnt a 0 row?

[@bernardlemaitre4701]

For the first element of the serie (n=1) we have 0 exp 1? = exp 1 x ln 0 !

[@Laskar_king]

Love from India 🇮🇳

[@osmanalbayrak5946]

Güzel 👍

[@ObsidianWings]

Con VERGEEES

[@ahmedhmz16]

T quiero un banda