Median of a Discrete Random Variable - How to find it

[@beastevic]

brilliant, thank u v much

[@RadfordMathematics]

Thanks Aleksandar!
Really glad it helped 😊
Should you want more practice with practice exercises, worksheets and tutorials you’ll find some on the site (that’s still being built but already there) :
www.radfordmathematics.com/probabilities-and-statistics/discrete-probability-distributions-discrete-random-variables/parameters-discrete-random-variables.html
See you soon
✌️

[@QuOUseTERSEa]

The median(m) of r.v. is defined as p(r.v. >= m ) >= 0.5, p(r.v. = 0.5. Hence, m = 4 where p(r.v. >= 4 ) = 0.6 and p(r.v.

[@chumbucket3170]

Shouldn't the median be 4?

[@amitava1973]

Thank you, Sir. This helps a lot. Please upload the video to find out the mean and standard deviation as well.

[@RadfordMathematics]

Dear Amitava,
Thank you for your message, I'm very glad it helps.
For the mean and standard deviation you'll find everything (tutorials and worked examples) you need on my site:
www.radfordmathematics.com/probabilities-and-statistics/discrete-probability-distributions-discrete-random-variables/parameters-discrete-random-variables.html
Hope it helps :)
John Radford.

[@Sagadiniz]

Since the only values you can get are Natural numbers [1,5] shouldn't the median be 4?

[@edoardobonel5845]

Extremely helpful! Thanks a lot! :)

[@RadfordMathematics]

Really glad it helped 😊

[@xiangnanzhou9605]

The method is wrong, median is 4.

[@hamzahalayed9761]

Thank you with all my heart ❤️

[@RadfordMathematics]

Truly glad it helped 😊 you may find my notes and other tutorials on parameters of discrete random variables useful as well: www.radfordmathematics.com/probabilities-and-statistics/discrete-probability-distributions-discrete-random-variables/parameters-discrete-random-variables.html

[@hamzahalayed9761]

@@RadfordMathematics
Thank you so much. ❤️

[@Vexinal]

is this patched yet????

[@manojpaul4377]

thanks for the video!!

[@RadfordMathematics]

Thanks for your comment!
Really glad this video helped 😊

[@juiroy9420]

It's very helpful..

[@RadfordMathematics]

Thanks for taking the time to comment Jui! I really appreciate it 😊
You may find my online notes (and tutorials) useful as well:
www.radfordmathematics.com/probabilities-and-statistics/discrete-probability-distributions-discrete-random-variables/parameters-discrete-random-variables.html
In any case take good care ✌️

[@saicharant6571]

The median lies between 3 and 4, we cannot guarantee that the median is 3.5

[@RadfordMathematics]

You’re right: we cannot guarantee that it’s 3.5.
In fact since it lies between two of the data values: technically there is no median value BUT the median (as such) serves as an upper bound to the lower half of the data as well as a lower bound to the upper half of the data.
As such 3.5 definitely serves that purpose in the sense that we can correctly make the statements:
- 50% of the data is less than 3.5
- 50% of the data is greater than 3.5
Taking the mid-value between 3 and 4 is the most reasonable value to choose to serve those two purposes (lower bound and upper bound).
Interesting Comment 😊!
Take good care!

[@jimmyjonestodd2556]

This is wrong. P(X less/equal1 ) = 0, P(X less/equal 2) =.2, P(X less/equal 3) =.3, P(X less/equal 4) =.4, P(X less/equal 5) =.7, P(X great/equal 5) =1, therefore the median is 4.5

[@maevaschizua8977]

Thank you so much

[@RadfordMathematics]

Thanks for your comment Maeva! Really glad it helped 😊

[@bhanusinghal1918]

Great, keep going

[@RadfordMathematics]

Thanks for your kind words Bhanu!
I’m really glad it helped :)
You may find the webpage that goes with that tutorial useful as well: www.radfordmathematics.com/probabilities-and-statistics/discrete-probability-distributions-discrete-random-variables/parameters-discrete-random-variables.html
Take care :)

[@norsyazwaniezulkifly5473]

i think this concept is wrong since this is discrete so there is no in between. it’s either one or another

[@RadfordMathematics]

I see what you mean. But go back to your middle school stats: what’s the median of (for example) 3,4,5,6 ?
You should find it’s 4.5.
The principle you see in this video is the same 😊.
Hope that helps.

[@Kevin-ch1xj]

@@RadfordMathematics true, but the median in the video example is definitely 4...
say u have a sample of 10. the outcomes would be distributed accordingly:
1 1 2 3 4 4 4 5 5 5
clearly the middle value (median) is 4. because (4+4)/2 = 4, not 3.5.

[@geeh5080]

Thannnkk uuuuuu so much

[@RadfordMathematics]

Gee Khaleed Hi :) I’m so glad to hear it helps :)
I made that tutorial to go with my notes on discrete probability distributions, that you’ll find at the link below.
Some exercises for you to practice with :
www.radfordmathematics.com/probabilities-and-statistics/discrete-probability-distributions-discrete-random-variables/parameters-discrete-random-variables.html
Hope it helps as well :)

[@isaiahmrman6564]

nice

[@RadfordMathematics]

Thanks Isaiah :)
I’m really glad it helped!!
You may find more on this topic (more tutorials, notes, questions and answers) on my site:
www.radfordmathematics.com/probabilities-and-statistics/discrete-probability-distributions-discrete-random-variables/parameters-discrete-random-variables.html
Wishing you all the best!
John Radford

[@nguyenlucas6359]

Wrong!!!