Calculating a Cumulative Distribution Function (CDF)
ฝัง
- เผยแพร่เมื่อ 23 ก.ย. 2024
- MIT 6.041SC Probabilistic Systems Analysis and Applied Probability, Fall 2013
View the complete course: ocw.mit.edu/6-0...
Instructor: Jimmy Li
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu
Clearly articulated, great voice to listen to and explained every step along the way. Tutorials don't get better than this
Oh my god that was an amazing explanation and example. Thanks a bunch, really helped me understand all of it. I hope you make more intermediate statsistics videos.
This really helped me, clear voice and explanation and I was able to solve my homework problem.
3:06 - 3:49
This moment is key. Watch it and watch it again until you understand what he means to understand CDF's.
still struggling to understand it:( would you explain why when x>8, F(x)= 1 and not just 0? Thanksss
@@confusion3146 did you figured it out cause I’m wondering the same thing?
It's 2021 and I'm using this as a source of knowledge
Super concise and well articulated, good refresher for my 700 level class. Thanks.
exam in 12 hours
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Mock exam in 1 hour :x
exam in 2 hours
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You literally just saved my arse. I wrote my C.A test without knowing this but I found this video just in time before exam. Now I'm 3x more confident!
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Try looking up, I think the joke flew over your head
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why is it 1 at z>1?
It's z > 1 at 1 because the CDF is accumulating the probabilities between 0 and 1. Once you reach the point 1, the total area under the curve is 1. Therefore, when you continue beyond 1, the cumulative probability is still 1 since probability is between 0 and 1.
Onur hahahahaha
13stat..thanx a lot.
@@13statistician13 that was really helpful buddy...you just made me understand the whole topic in a paragraph
@@shashankdixit92 anytime. Glad I could help.
Brilliant!
Super clear. Watching this as a refresher, and you totally nailed it. Great video.
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Well done! Finally someone who knows their stuff! (From CS 70 at UC Berkeley)
Finally a good video on how to obtain cfg from pdf
شكراً ساعدتني كثيراً 💎💙 thank you 🌟
He is the best TA of the MIT
what about when we have more intervals in the PDF?
I love you for this. I’m currently doing my test and this is help 🤣😂
Awesome, you've scored yourself a subscriber!
Greeting! I m not be too smart to understand when you started doing 'b' part, specifically when you said taking everything on the left side, could you share bit more highlight between Z and z and intrgration of fz(y)dy.
Good explanation Mr.Lee I finally understood it💜
thank you!! really helpful and you offered very clear explanation!
I wish you were my professor, honestly. Couldn't be clearer.
I think CDF does not contained closed limits from both sides in every cases(Discrete and continuous both) explain it.
how were you able to turn -2
Sam Flatau I think it's from the fact that for a continuous random variable Z, -2
ty this is neat and clear even in 2021
very clear and concise explanation. Thanks!
your voice is so clear i understand everything. thank you it was helpfull.
He has an amazing voice
How about moving the z=1 situation to the third case? i.e.: 0, if z
Thank you!!
That really helped
pooja what is this behaivour?
Nice voice , It matches the professor personality ,good ,Started to love stastics
good explanation thanks
you are the best❤️
Why you said at the end that if Z>1 the CDF = 1 ??
awesome explanation
There must be -2 ≤ z < -1 and 1 ≤ z
in place of 1
Thanks for excellent video.
I have one question. If we are given CDF and we are asked to find mean and median. Than what we should do. we should convert into pdf to find mean median formula or is there any way to find directly from CDF it self.Thanks
You are a very good teach, you speak very well in your video. Thanks a lot!!
Hello Sir i request you to repeat on how you are coming up with those limits on the final answer ,kindly
yeh idk either help, and also why is the F(x)= 1 when x>8? why isn't it 0 too?
Very Clear Explanation, Thank You
Note that gamma is a scalar constant, not a function. Math notation can be ambiguous.
the gamma function is represented with a capital gamma, at the beginning of the video I thought it was the number gamma 0.577....
Thank you!
a teacher i never had
Helped me a lot.
Thank you for the video.
how CDF in 3 ranges moreover z>1 how it become 1, please anyone make my doubt clear. thanks
CDF stands for "cumulative distribution function". Therefore, at z = 1 it has reached 100%.
Thanks.. very much sir,... Complex phenomena in simple way......
In the pdf, the interval is -2 < x < 1 and in the cdf it becomes -2 ≤ x ≤ 1. Could you please explain how that happened? So far I know, in a continuous random variable, P(a ≤ X ≤ b) = P ( a < X < b) = P (a < X ≤ b) = P (a ≤ X < b). So if I write -2 < x < 1 in the cdf, would my answer be wrong?
Hey, three years passed before your question, did you find the answer somwhere? Thanks in advance
@@kr1sel448 Hello. I found a property-
If X is continuous, then the probability that it will take any particular value is zero.
So, P(a ≤ X ≤ b) = P ( a < X < b) = P (a < X ≤ b) = P (a ≤ X < b)
So the answer I found is - it doesn't matter how I write it 'cause it means the same thing. I should write what is there in the question.
@@thekingprajna Thanks a lot
great video
thanksss its very helpful
why is cdf=1 for z>1 ?
Thank you so much, you were amazing, you've helped me a lot!!
Thank you so much for this video.Great voice,clear concept. thanks once again. :)
Extremely helpful. Thanks so much!
Very helpful and easy to understand!
Nice, Thanks it was very clear to understand !
THAN YOUUUU VERY MUCH
Great video sir. Thank you!
I would pay you double my tuition to replace my teacher who can't even speak english.
Why CDF is 1 when Z > 1 @7.33 ?
You are a good teacher
That was really awesome!!!
Thank you very, very much!!
ps: loooove your voice☺️
excellent video, thank you
where did that 1/3 come from? it got me confuse. please explain in details.
The anti derivative of y^2 is y^3/3...he just pulled the fraction out and made it 1/3 y^3
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is that worth an exam???
thanks sir, great teaching.
It helps me a lot, THANK U!!!
If there are three interval??
I can’t see what you’ve written
helps heaps thanks man
Thank you sir,I just got it
Love that guy
Thanks
Thank you very much
Excellent !!!
Perrrrfect! Thank you!
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THANKS A LOT BRO
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So helpful!
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Thanks!
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Thanks so much!!!!
isnt it 0 if z is greater than 1
No because this is not the PDF, this is the CDF (Cumulative Distribution Function) meaning as it goes along, it accumulates the probability. So anything at 1 or after 1 is going to be a probability of 1.
thanks........... nice work
Very helpful thanks
Thank you so much! Saved me ! :D
very clear ，thx😀