Matlab Tutorial - 52 - Solving Systems of Algebraic Equations Symbolically

[@SebasTian-xx6yc]

for everyone who are getting the errors, we dont need to put the apostrophes anymore so instead of solve('eqn',x) its solve(eqn,x)
hope this helps

[@andrewmelean8259]

Thanks buddy :)

[@NURULISLAM-bq7br]

I watched almost all the videos of this playlist. It helped me a lot. Thanks a lot sir

[@jaroslavgrigorin7597]

If you want to get result with constant c, just define it as a variable (syms x y c) but solve only for x and y.

[@mrx3449]

I have an issue with matlab 2018 line 226 and line 418. Do you know what's wrong?

[@ryanward8117]

with the new version the correct way would be the expression
[x y] = solve(3*x-y == 2 , x + y== 1 , x , y)
th quotes are removed and it has to be told what it is solving for

[@yangchengzhang7188]

@@ryanward8117 it helped, thank you very much!

[@demisbooo743]

Great! Thanks a lot!

[@aurangzeb7848]

@all, I am facing error while solving system of quadratic equations symbolically. Following the example in this video, I tried this one
>> [x,y,z]=solve('c*x-2y=1','2*y-cz=2','c*z-x+y=3')
But I got the Error message like,
??? Error using ==> solve at 77
' c*x-2y=1 ' is not a valid expression or equation.
I want to know what is wrong with this...
Thank you in advance.

[@renanlarrieu]

I believe the command "pretty" just does not do what it should...

[@zynxajeaesthetics6067]

thanks alot bro

[@able5857]

Thanks man!!

[@JagjitSingh-vz7hj]

what about z value

[@rahmaniyousra2291]

Both below solutions are not working. Can someone help please:
solution=(3*x-y==2,x+y==1)
solution=(3*x-y==2,x+y==1,x,y)