Much appreciated Sir 😊 MOSFET drain feedback bias One minute A: Id=k(vd-vt)^2 15-vd/15=0.25(vd-1.5)^2 Too lazy to solve the value of ax2+bx+c=0 vd gm=2k(vgs-vt)^2=2k*(id/k)^1/2=2*(k*id)^1/2 (Id/k)^1/2=vgs-vt B: vo=-u*vi*(rl'/ro+rl') vo/vi=41.2*(3.75/(68.75+3.75))=154.5/71.5=-21.6v/v C: Rin=rg/(1-A)=10/22.6=3.164M ohm Ro=ro//rd//RL//(rg/(1-1/av))=~
Va is the Early voltage. Analyzing the ID and VDE characteristic graph, the point of intersection from all the relationship curves correspond to some Early trans-conductance which is ID/VA where VA is the value of VDE at the point of intersection.
Great video, cheers!
Thank you, I was confused on what to do when there was a self biasing resistor.
Wow! Thanks for this 🙏
Much appreciated Sir 😊
MOSFET drain feedback bias
One minute
A:
Id=k(vd-vt)^2
15-vd/15=0.25(vd-1.5)^2
Too lazy to solve the value of ax2+bx+c=0 vd
gm=2k(vgs-vt)^2=2k*(id/k)^1/2=2*(k*id)^1/2
(Id/k)^1/2=vgs-vt
B:
vo=-u*vi*(rl'/ro+rl')
vo/vi=41.2*(3.75/(68.75+3.75))=154.5/71.5=-21.6v/v
C:
Rin=rg/(1-A)=10/22.6=3.164M ohm
Ro=ro//rd//RL//(rg/(1-1/av))=~
Is it not the capacitors treated as open circuit in small signal model?
Thanks 😊👍🙏💯
What really is the Va? I dont see where that is or what it means 😢
I think it's like lambda = 0.02?
inverse of lamda@@Emma-dd1fc
@@Emma-dd1fc Va = 1/lambda
Va is the Early voltage. Analyzing the ID and VDE characteristic graph, the point of intersection from all the relationship curves correspond to some Early trans-conductance which is ID/VA where VA is the value of VDE at the point of intersection.