6 years after this was made, and it was still taught better than my orgo professor did. Thank you so much, you have no idea what a relief it is to finally understand this.
You teach far better than my Organic Chemistry I professor. I am glad you posted this video. You are making the lives of students like me easier. Please post on a regular basis. You'll be helping a lot of students. Thank you and God Bless you for helping me and other students.
you are God sent (cries in organic chemistry tears). I finally understand thank you, and God bless you. AMEN. This was made 8years ago and it's still very helpful.
Hello I'm French speaking, I've been searching this stuff on French vidéos for almost a whole week because I did not get a shit of what was said in class, and finally few hours before my test I find answers to my questions, this...this is a message from God ohhhh thanks
You are the best chemistry teacher on TH-cam. You have a God's gift to teach. Please post videos regularly. You can post videos for AP Chemistry or Gen Chemistry 1 and 2.
Sorry to be off topic but does anyone know a way to log back into an instagram account..? I stupidly forgot the login password. I would love any help you can give me.
@Ian Jadiel thanks so much for your reply. I got to the site thru google and Im trying it out now. Takes quite some time so I will reply here later when my account password hopefully is recovered.
You're absolutely right! The size of a group and length of the bond connecting it to the ring play key roles in determining how stable it is in an axial vs equatorial position. If two bonded groups are the same distance away from the ring, then the larger one will be more stable in the equatorial position than the smaller one.
That's correct for IUPAC nomenclature. The numbering used in the video is for tracking carbon positions only and does not need to relate to the official numbers that would be used for IUPAC nomenclature.
It can be drawn axially. After a ring flip, it will switch to an equatorial position anyways. So no matter how you draw it (axially/equatorially) in real life you will find it in both positions since both chair conformations rapidly interconvert at r.t.
You can know that the C-Br bond is longer than a C-C bond (at 3:55) by comparing the sizes of carbon vs bromine atoms. On the periodic table, C is in the 2nd period (row) while Br is in the 4th period. That is, Br has two extra shells of electrons compared to carbon, and it holds its outermost valence electrons much further away than carbon does. Since atoms form bonds with their valence electrons, Br forms longer bonds (valence electrons further from the nucleus) than C does (valence electrons closer to the nucleus).
Are you perhaps thinking of bond strength? You're right that there is a trend that longer bonds tend to be weaker (which may be what you're referring to here as less stable?). This could lead us to predict, for example, that it would be easier to break the C-Br bond than the C-CH3 bond (other factors are also at play here in addition to bond length). However, at 4:20 we weren't comparing bond strengths, we were comparing the relative stability of the two possible conformations of the cyclohexane. Both cyclohexanes have the same bonds, so we can't use bond strength to compare their relative stabilities.
6 years after this was made, and it was still taught better than my orgo professor did. Thank you so much, you have no idea what a relief it is to finally understand this.
You teach far better than my Organic Chemistry I professor. I am glad you posted this video. You are making the lives of students like me easier. Please post on a regular basis. You'll be helping a lot of students. Thank you and God Bless you for helping me and other students.
Best explanation.... Had a doubt but now I am an expert in this.....
Dear stranger, you saved me from sleepless nights and probably a lot of tears . Thank you ❤
Thank you so much, I literally was able to solve all my doubt questions with just the help of this video, thanks a lot.
you are God sent (cries in organic chemistry tears). I finally understand thank you, and God bless you. AMEN. This was made 8years ago and it's still very helpful.
Thank you so much, I'm so glad that i have finally figured it out thanks to you
Hello I'm French speaking, I've been searching this stuff on French vidéos for almost a whole week because I did not get a shit of what was said in class, and finally few hours before my test I find answers to my questions, this...this is a message from God ohhhh thanks
Taking an ochem exam in 4 hours, you just saved me. Many thanks, if you’re still seeing these notifications 🙏
Good video, everything is simplified,I'm grateful, thanks.keep doing your good work 🎉❤
You are the best chemistry teacher on TH-cam. You have a God's gift to teach. Please post videos regularly. You can post videos for AP Chemistry or Gen Chemistry 1 and 2.
amazing video with tons of great exaxmples and great explanation! thank you very much
Wouldn't Br be on Carbon 1 on the ring because it is lower in the alphabet?
Thank you for explaining this clearly..
Sorry to be off topic but does anyone know a way to log back into an instagram account..?
I stupidly forgot the login password. I would love any help you can give me.
@Johnny Rey instablaster :)
@Ian Jadiel thanks so much for your reply. I got to the site thru google and Im trying it out now.
Takes quite some time so I will reply here later when my account password hopefully is recovered.
@Ian Jadiel it did the trick and I finally got access to my account again. I am so happy!
Thanks so much, you saved my account :D
@Johnny Rey No problem =)
Honestly you tube videos like this make students life much more easier than their Organic teachers! ✨✨😅
Great way of explaining this! thanks!
Thank you so much for this awesome explanation !
This video helped me a lot today! Thank-you ❤
2 mins in and I understand, been trying too understand for a month 😂
your voice............is so relaxing,,///////////thnx for that
Thanks a lot 😊
Before i was struggling a lot but i think this video just crystal cleared my concept
Thanks for the video am asking my self how to know the top and the bottom
God bless u!!!!!!!
Thank you for the amazing explanation
Thank you...well explained...👌🏻👌🏻👌🏻✌️
Another explanation is that the big group are more stable in the equatorial position
You're absolutely right! The size of a group and length of the bond connecting it to the ring play key roles in determining how stable it is in an axial vs equatorial position. If two bonded groups are the same distance away from the ring, then the larger one will be more stable in the equatorial position than the smaller one.
1-bromo-2-methylcyclohexane
We Give bromine 1 position right?
That's correct for IUPAC nomenclature. The numbering used in the video is for tracking carbon positions only and does not need to relate to the official numbers that would be used for IUPAC nomenclature.
Why can't Br be drawn axially rather than equatorial...?
It can be drawn axially. After a ring flip, it will switch to an equatorial position anyways. So no matter how you draw it (axially/equatorially) in real life you will find it in both positions since both chair conformations rapidly interconvert at r.t.
Thanks a lot it's very helpful ❤
hey how do you know the C Br bond is taller.. is this something we should know?
You can know that the C-Br bond is longer than a C-C bond (at 3:55) by comparing the sizes of carbon vs bromine atoms. On the periodic table, C is in the 2nd period (row) while Br is in the 4th period. That is, Br has two extra shells of electrons compared to carbon, and it holds its outermost valence electrons much further away than carbon does. Since atoms form bonds with their valence electrons, Br forms longer bonds (valence electrons further from the nucleus) than C does (valence electrons closer to the nucleus).
oh okaay thankss. would it also be that h3c is a bigger molecule and its always better to put bigger molecules in the equatorial when you can??
Yes, you're right. It's more stable to put the sterically bulky methyl group (CH3) in the equatorial position.
This helps SOOO much!!! Thank you!!!!
thank you so much.....it finally makes sense.
Thank you very much ma'am u cleared all my doubts..😇😇
I needed that thanks !
yes!!! life saver
Great explanation! Thank you!!
Your first chair flip is wrong. The hydrogen equatorial to carbon 2 should be parallel to the bond connecting carbon 1 and 6.
Absolutely true - well spotted!
another hero.
Thank you so much for this❤️
This is amazing! Thank you :)
very good explained:)
Really helpful!!
Really helpful thnx for this
very helpful
what a legend thanks
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This video solve my problem in just 2 Min💞👍
great video thanks!
Thnx.looking forward for ur new videos.
Thank you so much
thank you for explain that
Thanks ❤
thank you so much!!
Ohhhh so you can choose any Carbon to be your number 2
Number 1 ...
Wow thanks
Thank you for explaining!
Thank-you makes sense now
God bless you
THANK YOU
Got it...thanks alot
Are you perhaps thinking of bond strength? You're right that there is a trend that longer bonds tend to be weaker (which may be what you're referring to here as less stable?). This could lead us to predict, for example, that it would be easier to break the C-Br bond than the C-CH3 bond (other factors are also at play here in addition to bond length). However, at 4:20 we weren't comparing bond strengths, we were comparing the relative stability of the two possible conformations of the cyclohexane. Both cyclohexanes have the same bonds, so we can't use bond strength to compare their relative stabilities.
i want an icon of you to pray to
Thank you