Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!!
What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on TH-cam) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 Physics Chapter 03 : KINEMATICS : Motion in a Straight Line 01: Introduction || Average Speed th-cam.com/video/XIJAZM5G5Fg/w-d-xo.html Class 11 Chapter 3 Kinematics: Differentiation || Calculus part 01 || Mathematical Tool th-cam.com/video/UiVYFFRs_BE/w-d-xo.html Class 11 Physics Chapter 03 : KINEMATICS :Motion in a Straight Line 02 || Instantaneous Velocity || || IIT/ NEET th-cam.com/video/9nBWFM7XTEw/w-d-xo.html Class 11 Chap 3: KINEMATICS || INTEGRATION || ||Calculus Part 02 || Mathematical Tools || th-cam.com/video/_dmHLxqbXYU/w-d-xo.html Class 11 Physics Chapter 03 : KINEMATICS : Motion in a Straight Line 03 || Answer Batao Salute Pao #Physicswallah || th-cam.com/video/-PKUJCIJSfc/w-d-xo.html Class 11 Physics Chapter 03 : KINEMATICS : Motion in a Straight Line 04 ||Derivation Of Equations Of Motion Using Integration|| th-cam.com/video/AxhkozLNDO4/w-d-xo.html Difference Between Diaplacement and Distance || IIT JEE MAINS AND ADVANCE CONCEPT || th-cam.com/video/4IkIGhuhuxo/w-d-xo.html 11 chap 03 : Kinematics 05 | Displacement time Graph -Velocity time Graph - Acceleration time Graph th-cam.com/video/4OgPa7MKjRA/w-d-xo.html NEET Best Questions 01 || Motion in a Sraight Line 1 || KINEMATICS NEET || Motion in One Dimension th-cam.com/video/oq-TjVH-sXc/w-d-xo.html 11 Chap 03 :Kinematics 06 || Motion Under Gravity || Motion in a Straight Line || Class 11 / JEE || th-cam.com/video/G0ooGZA_gyc/w-d-xo.html Relative Velocity || Kinematics|| Motion in a Straight Line 08 || Class 11 Chapter 4 || JEE MAINS th-cam.com/video/3sLGCWGm610/w-d-xo.html Best Method For Rain Man Problems | Relative Velocity | Motion in a Plane | Kinematics JEE NEET th-cam.com/video/tEltpY8vBPM/w-d-xo.html River Boat Problem || Relative Velocity in 2D || River Man Problem || Motion in a Plane || JEE NEET th-cam.com/video/2QFRRL50-ds/w-d-xo.html Projectile Motion 01 || Class 11 chap 4 || Motion in a Plane|| Motion in 2-D || th-cam.com/video/iUi1M7YkDe4/w-d-xo.html Projectile Motion 02 || Class 11 chap 4 || Motion in a Plane || Projectile from a Height || th-cam.com/video/dEqKhmTTXJk/w-d-xo.html Projectile Motion 03|| Equation Of Trajectory || Derivation Of Equation Of trajectory|| Range Form th-cam.com/video/js_G3G02AkU/w-d-xo.html Mock Test 01 | Kinematics Best Questions for IIT JEE NEET | IIT JEE Questions Kinematics th-cam.com/video/jYLGziSgI-Y/w-d-xo.html 11 Chap 4 || Circular Motion 01 || Angular Velocity and Angular Displacement || IIT JEE /NEET th-cam.com/video/JxttUGnNuCU/w-d-xo.html 11 Chap 4 | Circular Motion 02 | Centripetal and Tangential Acceleration | Angular Acceleration | th-cam.com/video/pOvYwchAvCA/w-d-xo.html Circular Motion 03| Centripetal and Centrifugal Force IIT JEE/ NEET | Conical Pendulum |Death Well | th-cam.com/video/Wt9_bvjCFf0/w-d-xo.html 11 chap 4 | Circular Motion 04 | Derivation of Centripetal Acceleration or Centripetal Force | th-cam.com/video/QYbyobdXlrg/w-d-xo.html 11 chap 4 | Circular Motion 05 | Banking Of Road IIT JEE NEET | Banking of Road with Friction | th-cam.com/video/C0uVC700EIA/w-d-xo.html 11 chap 4 || Circular Motion 06 || Motion in a Vertical Circle IIT JEE / NEET || Critical Velocity th-cam.com/video/e0Tty0V1q2U/w-d-xo.html 11 chap 4 || Circular Motion 07 || Motion in a Vertical Circle On a Bowl || IIT JEE MAINS / NEET th-cam.com/video/_WMTtzIZQR8/w-d-xo.html
Sir neet mein #180 question krne h 3 hours m toh ek question ko 1 min sirf.....toh itna lmba solve krnge toh time nhi hoga na... Koi #short #tricks bta do...!!😟
(For the last question) For time : u = -20 m/s; a = 0 m/s²; s = -40 m. Therefore, s = ut + (1/2)at² -40 = (-20)t + (1/2)(0)t² -40 = -20t t = 40/20 = 2 s For position : 1) With respect to particle B u = 24 m/s; a = -g = -10 m/s²; t = 2s. Therefore, s = ut + (1/2)at² s = (24)(2) + (1/2)(-10)(2)² s = 48 - 5×4 = 48 - 20 s = 28m 2) With respect to particle A u = 4m/s; a = -10m/s²; t = 2s. Therefore, s = ut + (1/2)at² s = (4)(2) + (1/2)(-10)(2)² s = 8 - 5×4 = 8 - 20 s = -12m
Answer for the question in the end... They will meet in t= 2seconds and at A = 28m and B = -12m (-ve since displacement is downwards from initial position.) Thank you so much Alakh Sir for explaining all the concepts amazingly and helping all of us JEE & NEET aspirants!
I'm from Bhutan and I could get admission in engineering college after 12th grade by watching your videos. Now I'm in my dream college yet I'm still borrowing your knowledge,sir. Thank you for everything, Alak sir.
The last thing u said "agar vdo pasand aya ho to padhai acche se kijiyega OR KUCH bhi mat kariyega" that hit me hard. Sir you're really brilliant teacher. To be very honest I would never ever loose hope and show neglection to my studies becoz if the teacher is so honest and sincere then why can't students.ill be studying really hard . Hats off to you🙏
@@souvikbhattacharyya3399 wtf....then u probably need to do smart work than hard work...u are just wasting Ur time man...u can study for 4 hours a day with proper focus and your syllabus + extra studies can be completed
41:05 In this question UBG = 20ms ABG = -1 ms² SBG = 150 m S=ut + ½at² 150 = 20t + ½ -t² Multipky both sides by 2 300 = 40t - t² t² - 40t +300=0 t² -30t -10t + 300 = 0 t(t-30) -10(t-30 ) = 0 (t-30) (t-10) = 0 t=30 t=10 Put both values in the formula the distance will be same so boy catches girl at 10 and 30 seconds
30:12 he somehow always knows , when we dont get it . people in my school keep proceeding even after we say we've got doubts .they be like ' practice karo ho Jayega ' . ❤❤❤
Most relevant lecture required for this topic....17:23 mein 13 aayega sir...waise toh aapko correct karna mere jaise student ke liye is no less than a sin as it's just a calculation error and you are such great teacher
Time does not depend on frame of reference is not always true.Only true according to Newton but according to Einstein's Special theory of relativity, time is not absolute.
51:00 Time =2s The point where they meet is From body (speed 24m/s)=28m above From body (speed +4m/s)=-12m (means downwards)and if we sum the total length it will equal the relative distance b/w them
Ans of last question is: U(ab)-u(a)-u(b):20 a(acceleration) :0 S:40 T:s/u:40/20 T:2sec Position : A:25m/s S:24(2)+0.5(-10)(2 square) 48-20:+28m B:4m/s S:4(2)+0.5(-10)(2square) 8-20 -12m
13:11 " Tum log humesha mera naam puchte rehte ho My name is ALAKH PANDEY " aaj sabko inka naam pta hai....sir ko btane k zaroorat nhi...... This is called GROWTH 🥺💗✨
@@bullymaguire827 bhaiii sir is best for jee mains and neet physics and chem but not for jee adv........future me shayad sir jee adv ke bhi karaye but abhi tak to nahi karya isleya jee adv ka nahi bol skate
@@bullymaguire827 bhaiii me ye bol raha tha...sir neet phy and chem ke liya more than enough haiii....and maine bas tujhe reply diya maine ye kab bola tu bol raha tha 😎😎😎😎
Homework qs ....solution ....time A ND B MEETS= 2 SEC position they meet...accrding to A IT MEETS B whn it goes down to 12m Accrding to body B .WHN IT GOES UP TO 28m. It meets. Body A. Hence overal total dist given is 40m tht is 12m + 28m..= 40m Thank you alakh sir ...old never goes old... forever blessed❤❤
i am in 3rd year of college now,watching it again and feeling nostalgic. So happy to see what alakh sir has achieved now. Epitome of dedication, perseverence and hard work.Proud to be a PWian ❣❣
when teachers were teaching in institute and not understanding the concept. others -- "yar ab kya hoga " Me -- smiling and thinking , ab alakh sir se samjhunga and kal sabke samne hushyari marunga... 😜😜😜😂😂🤣
I'm in 11th right now. Everything is new to me. Since 2 weeks I've been struggling with this topic. I always wanted to have a clear cut understanding of the topic. Finally I understood it completely and all thanks to you sir. You are that kind of teacher who everyone desires. Thank you sir, i don't have words to explain how your video helped me.
Brothers i am also present 11 and struggle it... Such a difficult chapter as we haven't study class 9 due to lockdown 😂😂... The hero of lockdown was pubg for us 😂😂😂
Good evening sir! Homework sum: Time = 2s Position: 28m from below 12m from above Thank You so much Sir, you simplified the topic to halwa! Thank you!!
शाबाश, बेटे ! ईश्वर तुम्हें स्वस्थ, प्रसन्न व आबाद रखें। आदर्श कार्य कर रहे हो। अपनी इस यात्रा को पवित्र बनाए रखना, क्योंकि तुम अवश्य ही एक मील का पत्थर स्थापित करने की ओर अग्रसर हो ! God bless u!
Those who are very clear with the concepts should definitely watch our videos and solve TYPICAL ADVANCED level questions. Even concepts are told in our channel by experienced faculties of Narayana. For Example: th-cam.com/video/8AM-2ao1LpI/w-d-xo.html
Ans. of homework question.👈🏻 (1) time = 2 seconds (2) acceleration = 0 (3) relative velocity = - 20 m/s (4) position where both meet is 28 metres with respect to lower end and 12 metre from upper ends....👍🏻👍🏼
@@Abhishek-bhardwaj789 bhai pehle relative velocity nikal lena Vab=Va-Vb fir accelaration nikal lena same formula se bas v ki jagah a lena toh woh zero aayega fir t=distance /speed rakh kar time nikal lena aur usko fir s=ut+1/2at2 me rakh katr kisi ek end se nikal lena bro plz bas iske badle subscribe kar dena
Sir a trolley moving front side with a speed 10 M per second, A man moving backward to 3 M per second, P person who is in the car moving forward 20 m per second (Answer = -13 meter per second)
Time is 2s when they will meet and position is 12m from top and 28m from down..it was same as previous question which alakh sir gave .. Relative velocity 1D concepts cleared ..amazing video ..🙂🙂🙂
I still don't understand how? Vab will come out to be -20 as Va=4m/s and Vb=24m/s so subtracting Vb from Va would give -20 and thus time would come out to be -2s which cann't be possible (although the magnitudes are same as answers as well if negative sign is not considered) . please explain. Edit: Proper answer can be calculated when Vba, Aba and Sba are considered. without neglecting the negative signs above the correct answers couldn't be brought up. please explain.
Only this teacher does not focus on teaching all the concepts but gives a feel in the concepts and relates in real life. bhaiya, yeh Alakh Pandey sir hai. Shiksha ki Alakh jagah hai, thay aur rahenge.
5yrs old video gives me that knowledge that I can't get it from new videos with smart board ... Kuch to baat hai iss purane video me yuhi nhi ham bachhe fida huye alakh sir pe 😅
really how he teaches........CHALO BACCHO TUMHE FEEL DILATE H..... the concepts he thinks are hard he repeat almost ten time we students are so proud that we have a teacher like you.............................. thank you so much sir O SIRJI TUSSI GREST HO.............
Those who are very clear with the concepts should definitely watch our videos and solve TYPICAL ADVANCED level questions. Even concepts are told in our channel by experienced faculties of Narayana. For Example: th-cam.com/video/8AM-2ao1LpI/w-d-xo.html
![TEEDEE TADA - DIAMOND NARAKORN X LEGO LYKN [Special Dance Performance]](http://i.ytimg.com/vi/QgtZedFeumA/mqdefault.jpg)
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LAKSHYA Batch(2020-21)
Join the Batch on Physicswallah App bit.ly/2SHIPW6
Registration Open!!!!
What will you get in the Lakshya Batch?
1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.
2)Live Classes and recorded Video Lectures (New, different from those on TH-cam)
3)PDF Notes of each class.
4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.
5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.
6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
8)You can view the videos any number of times.
9)Each chapter will be discussed in detail with all concepts and numericals
10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.
Class 11 Physics Chapter 03 : KINEMATICS : Motion in a Straight Line 01: Introduction || Average Speed
th-cam.com/video/XIJAZM5G5Fg/w-d-xo.html
Class 11 Chapter 3 Kinematics: Differentiation || Calculus part 01 || Mathematical Tool
th-cam.com/video/UiVYFFRs_BE/w-d-xo.html
Class 11 Physics Chapter 03 : KINEMATICS :Motion in a Straight Line 02 || Instantaneous Velocity || || IIT/ NEET
th-cam.com/video/9nBWFM7XTEw/w-d-xo.html
Class 11 Chap 3: KINEMATICS || INTEGRATION || ||Calculus Part 02 || Mathematical Tools ||
th-cam.com/video/_dmHLxqbXYU/w-d-xo.html
Class 11 Physics Chapter 03 : KINEMATICS : Motion in a Straight Line 03 || Answer Batao Salute Pao #Physicswallah ||
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Class 11 Physics Chapter 03 : KINEMATICS : Motion in a Straight Line 04 ||Derivation Of Equations Of Motion Using Integration||
th-cam.com/video/AxhkozLNDO4/w-d-xo.html
Difference Between Diaplacement and Distance || IIT JEE MAINS AND ADVANCE CONCEPT ||
th-cam.com/video/4IkIGhuhuxo/w-d-xo.html
11 chap 03 : Kinematics 05 | Displacement time Graph -Velocity time Graph - Acceleration time Graph
th-cam.com/video/4OgPa7MKjRA/w-d-xo.html
NEET Best Questions 01 || Motion in a Sraight Line 1 || KINEMATICS NEET || Motion in One Dimension
th-cam.com/video/oq-TjVH-sXc/w-d-xo.html
11 Chap 03 :Kinematics 06 || Motion Under Gravity || Motion in a Straight Line || Class 11 / JEE ||
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Relative Velocity || Kinematics|| Motion in a Straight Line 08 || Class 11 Chapter 4 || JEE MAINS
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Best Method For Rain Man Problems | Relative Velocity | Motion in a Plane | Kinematics JEE NEET
th-cam.com/video/tEltpY8vBPM/w-d-xo.html
River Boat Problem || Relative Velocity in 2D || River Man Problem || Motion in a Plane || JEE NEET
th-cam.com/video/2QFRRL50-ds/w-d-xo.html
Projectile Motion 01 || Class 11 chap 4 || Motion in a Plane|| Motion in 2-D ||
th-cam.com/video/iUi1M7YkDe4/w-d-xo.html
Projectile Motion 02 || Class 11 chap 4 || Motion in a Plane || Projectile from a Height ||
th-cam.com/video/dEqKhmTTXJk/w-d-xo.html
Projectile Motion 03|| Equation Of Trajectory || Derivation Of Equation Of trajectory|| Range Form
th-cam.com/video/js_G3G02AkU/w-d-xo.html
Mock Test 01 | Kinematics Best Questions for IIT JEE NEET | IIT JEE Questions Kinematics
th-cam.com/video/jYLGziSgI-Y/w-d-xo.html
11 Chap 4 || Circular Motion 01 || Angular Velocity and Angular Displacement || IIT JEE /NEET
th-cam.com/video/JxttUGnNuCU/w-d-xo.html
11 Chap 4 | Circular Motion 02 | Centripetal and Tangential Acceleration | Angular Acceleration |
th-cam.com/video/pOvYwchAvCA/w-d-xo.html
Circular Motion 03| Centripetal and Centrifugal Force IIT JEE/ NEET | Conical Pendulum |Death Well |
th-cam.com/video/Wt9_bvjCFf0/w-d-xo.html
11 chap 4 | Circular Motion 04 | Derivation of Centripetal Acceleration or Centripetal Force |
th-cam.com/video/QYbyobdXlrg/w-d-xo.html
11 chap 4 | Circular Motion 05 | Banking Of Road IIT JEE NEET | Banking of Road with Friction |
th-cam.com/video/C0uVC700EIA/w-d-xo.html
11 chap 4 || Circular Motion 06 || Motion in a Vertical Circle IIT JEE / NEET || Critical Velocity
th-cam.com/video/e0Tty0V1q2U/w-d-xo.html
11 chap 4 || Circular Motion 07 || Motion in a Vertical Circle On a Bowl || IIT JEE MAINS / NEET
th-cam.com/video/_WMTtzIZQR8/w-d-xo.html
Physics Wallah - Alakh Pandey sir you are the best Jo kahin samajh nahi aata would aapse samajh aata hai
They will meet after 2 sec and at 28 m above the ground
Sir neet mein #180 question krne h 3 hours m toh ek question ko 1 min sirf.....toh itna lmba solve krnge toh time nhi hoga na...
Koi #short #tricks bta do...!!😟
#sir_relative_velocity_toh_imp_topic_h_na..!
Sir i want to follow your official Insta account ..please give me link to follow you on insta
(For the last question)
For time :
u = -20 m/s;
a = 0 m/s²;
s = -40 m.
Therefore,
s = ut + (1/2)at²
-40 = (-20)t + (1/2)(0)t²
-40 = -20t
t = 40/20 = 2 s
For position :
1) With respect to particle B
u = 24 m/s;
a = -g = -10 m/s²;
t = 2s.
Therefore, s = ut + (1/2)at²
s = (24)(2) + (1/2)(-10)(2)²
s = 48 - 5×4 = 48 - 20
s = 28m
2) With respect to particle A
u = 4m/s;
a = -10m/s²;
t = 2s.
Therefore, s = ut + (1/2)at²
s = (4)(2) + (1/2)(-10)(2)²
s = 8 - 5×4 = 8 - 20
s = -12m
Prajwal Sonone ...same here
U are correct same here
Nalle....
Sahi
Relative velocity se karna tha general se nahi
51:41 instead of asking like or subscribe
He said padhai achhe se kijiega or kuch bhi nhi. What a personality 🥰
Bhai ise video ka notes kaisa banaya please bataoo
@@akashpattnayak9056 jo padha rhe h usse chapp lo
@@akashpattnayak9056 kaha se aate hain ye log😤😂
I have completed your 500 likes😂😍
@@darakhshayasmeen I have completed ur 1 like... 😁
Answer for the question in the end...
They will meet in t= 2seconds
and at A = 28m and B = -12m (-ve since displacement is downwards from initial position.)
Thank you so much Alakh Sir for explaining all the concepts amazingly and helping all of us JEE & NEET aspirants!
Yes. That’s correct. Even I got the same answer. But where will they exactly meet ?
@@aaminatabassum2813 28 m above the ground
👍
They will meet 12 metre downward position from B and 28 metre upward position from A
It's 2023 till students are watching this evergreen teaching of legend wow just amazing❤❤❤
Are you living vizag?
Yes bro
Iam in 2024 broo😢😢
Mai bhi bro@@Notspidyy744
@@Notspidyy744 Same bhai
I'm from Bhutan and I could get admission in engineering college after 12th grade by watching your videos. Now I'm in my dream college yet I'm still borrowing your knowledge,sir. Thank you for everything, Alak sir.
Can you understand sir language hindi
Hmmm?
@@chrisrogers9462 as a southindian i can understand his teaching
Congo❤️👍
@@okbie943 same
The last thing u said "agar vdo pasand aya ho to padhai acche se kijiyega OR KUCH bhi mat kariyega" that hit me hard. Sir you're really brilliant teacher. To be very honest I would never ever loose hope and show neglection to my studies becoz if the teacher is so honest and sincere then why can't students.ill be studying really hard . Hats off to you🙏
prochondo sotti kotha
@Angelo Wilson jitna pardna mere sarir ki liye thik hai
@Angelo Wilson 10 hours
@@souvikbhattacharyya3399 wtf....then u probably need to do smart work than hard work...u are just wasting Ur time man...u can study for 4 hours a day with proper focus and your syllabus + extra studies can be completed
@@souvikbhattacharyya3399 bro Aapke 10th me kitne aae?
They will meet in 2s , and position from ground where they meet is 28m and -12 from top
and -12 also bro from a
-12 also yaar
Correct
correct bro . i also got ans as t=2 seconds and position is -12m and 28m respectively
Yes correct ❤️
41:05
In this question UBG = 20ms
ABG = -1 ms²
SBG = 150 m
S=ut + ½at²
150 = 20t + ½ -t²
Multipky both sides by 2
300 = 40t - t²
t² - 40t +300=0
t² -30t -10t + 300 = 0
t(t-30) -10(t-30 ) = 0
(t-30) (t-10) = 0
t=30
t=10
Put both values in the formula the distance will be same so boy catches girl at 10 and 30 seconds
What would be the value of closest distance however I think it may be 3
Thanks
@@selfish-rg3pf there won't be closet distance since the boy will catch the girl
But by formula of root b²-4ac/2a it is coming t=40 s ot t=0
"Main thaira raha, zameen chalne lagi" ~ Relative Motion in a Nutshell.
Lol 😂😂😂😂
Right😄😄
No
Oh Bhai maro muze maro👌👌👌👍👍👍
😁😂
it's now 2022
but The old lecture of alakh sir is still diamond ( precious) for us..!
,🙏🙏🔥
still the hope to complete backlog in the darkest hours
2023 vai
old is gold true for alakh sir
@@g.e.mwithkaustubh411dropped?
July 2024
Ultra legend watching this to complete there backlog
Yes me 😂
Mee too
Yep me too
😂 😂 😂 Yeppp
Haha, me 😢😂😢
time of meet = 2s
position from A = 28m
postion form B = -12m
same bro
Same here..
Right bro
How dude???
Bhai solution ki vedio de do na please 🙏
-12 m from top and at 28 m
The time is 2 seconds they meet after 2 seconds.
Hy
Correct
Ya ! Even I got the same
Bhai mera bhi yahi aaya hai
Mee tooo same utar
Me: My reaction when I see ncert problem - 🤯🤯🤯
Physics wallah: ye to halwa hai halwa 😂😂
🤭🤭🤭🤭
@@anjanthakur3357 yes and after watching his whole videos even IIT questions be like halwa🤣😂
@@Nityartist right
Sahi kaha halwaa maava sab khane me aasan kr dete hai sir🤤🤤🤤😂😅
@SHY ERROR vo to paper hone ke baad hi pata chalega LOL 🤣
The only youtuber who never asks to subscribe or like his channel.
If agreed like😝
Bhuvam bam also
th-cam.com/channels/3GsC_23R8X9dQwAQJ3uBxg.html
Bcz he is daata not yachak
THen why are you trying to attain likes.
\\
Tera comment kyu like Kare, hum to sir ki video like karenge
30:12 he somehow always knows , when we dont get it . people in my school keep proceeding even after we say we've got doubts .they be like ' practice karo ho Jayega ' . ❤❤❤
❤❤❤
Nobody has explained the RELATIVE concept with this excellence to me. Dhanyawaad shrimaan ji💗✍🏻🙏🏻
hii
Shriman Alakh ji not only shriman😁
@@abhijittiwari3130 Yes 😎
Shriman op !!
@@ramansh242
Omkar
Other teachers: I guess you didn't understand.
Physic Walla: Feel Nahi Aaya 😂😂
@Noob S. bhai lekin ye 2 saal phele ki vids h us saal me kon itna aacha feel dilata tha (:
:)
trueeeee😂😂
@@vanshikagupta2156 hnnnn(:
@Noob S. phir coaching se Sikh , Yaya kyu aya
@Supreme Chancellor wo bhi inhi se sikh kar jaate
Most relevant lecture required for this topic....17:23 mein 13 aayega sir...waise toh aapko correct karna mere jaise student ke liye is no less than a sin as it's just a calculation error and you are such great teacher
Yup
Yes bro
Shi kha
7-20=13 hota ha
@@RohitKumar-wz3re -13 hota hai
Time of meeting 2s
Dist 28m. B
From A. -12
Gazab! Teaching Skill with most convenient example!👌👌👌👌👌
Lucky
Av aap kaya kar rahe ho????
Most luckest person get liked by PW sir
Akash and Allen : Concepts get clear
Physics Wallah : Concepts get crystal clear 🤗🤗💥💥
Yes right neet ke age ke deen bhi me yeh video dekhta hu so funny 😃😃😃
Correct 👍👍👍
Concepts never get cleared in AKSAH and ALLEN
@@jigared1496 right👍
In aakash and allen bank account gets cleared🤣
51:27 time=2sec and distance=28m or -12m(Downward direction)
Yes bro❤️
could you please tell me how u did that?
@@shreyagupta5698 After finding u,a,S of B w.r.t A. Find t. Now apply this 't' with actual u,a of A and B you will get the distances.
@leothecat7115 displacement 20m hai bhai
Its 2024 still watching his videos which never gets old ❤❤
N still better than new vedios
@@medha_0 u should approach ur skol teacher or any other person.
hi bro.....thanks ......
ANS:
time ::::2secs
distance:::28meters above ground and 12 meters below the wall
From A : -12m
From B : 28m
and after 2 seconds.
Can you tell why should we take -40m as a distance..?
@@Hitakshivermaa Bcz we take relative velocity of A with respect to B. After some time ball A falling down then displacement is
“-40m"
Time does not depend on frame of reference is not always true.Only true according to Newton but according to Einstein's Special theory of relativity, time is not absolute.
Mannul Chopra
vahi vah vah
@@PhysicsWallah sir shayad wo class 12 pass kar ke baitha hua hai🤣🤣🤣
right manuul the time stops in the centre of blackhole
Accha h
Haan par utna high level nhi use hota ........Small units par .... 😂😂
lakho rupiya de diye, offline classes join bhi karliye,
end mein to yaha pe hi aa pahuche 😂
Us bro😢
Us bruhh
Riyal bro
Answer of last question
T=2 & position of meeting For A (ball of top) = -12m and For B (ground ball) = 28m
Yes I am agree with your answer 😊
Am alsooo
Evn me
I have same answer
Yes....my answer alsooo
51:00
Time =2s
The point where they meet is
From body (speed 24m/s)=28m above
From body (speed +4m/s)=-12m (means downwards)and if we sum the total length it will equal the relative distance b/w them
Totally wrong..
@@pramodkumarhibare6791 correct hai bhai wo
Bro Apka answer mere saath match kr rha hai
@@muawiyashaikh2229 are but bro 2sec me toh dono body upar jayegi toh dono positive ayega na from ground they will meet at 48m na?
@@AnshuKumar-ej3yi Woh neeche bhi toh ayega
Time of meeting- 2 seconds
Distance- 28 metres from point of B and -12 metres from point of A
Correct
haa bhai tumhara zyada sahi hai...upar wale bhai sahab ne kewal 28,2 likha tha
bro time positive me aa rha mera +2 aur distance 28 from b and -12 from a
Explain plsss
@@sohanadas6148 hii
They will meet at t=2secs
When the ball at the greater height is coming down and has covered 12m, and the lower ball going up has covered 28m
Ans of last question is:
U(ab)-u(a)-u(b):20
a(acceleration) :0
S:40
T:s/u:40/20
T:2sec
Position :
A:25m/s
S:24(2)+0.5(-10)(2 square)
48-20:+28m
B:4m/s
S:4(2)+0.5(-10)(2square)
8-20
-12m
Thanks bro
time toh negative ans me hena?
@@ravindrapratapsingh6484 no
This man is a perfect example for changing the mindset of people about UP and Allahabad waale
they are amazing people dont have any doubt about that why would u have a negative perception about them anyways
UP waalo pe doubt kabhi nahi tha....lekin BIHAR pe hai aur rahega jab tak har saal aane waale fraud cases band na ho
@@shivampawar4450 hc verma bhi bihar se hai
@@shivampawar4450 nahi bhai bihar bhi accha mai bihar se hi hu wo alag baat hai ki kuch exceptions hai
Sharam nahi aati man to kar raha hai saaron ko ek ek laat marun aakar
17:25 Vap= -13m/s
Yes
Yes
yes
Ha sahi bola sir ne glti se -14 likh diya h
Yes no problem 👍 ☺️ we learn concep not addition subtraction 😂
17:23 , in place of -14 there will come -13..🙂
Chhota baccha
Ha
Hi
Yes sir
yesssssssssssssss!
Answer to homework question:-
They will meet after 2 seconds
From ground at a distance of 28m and from top at distance 12 m downwards (-12m)
th-cam.com/users/shortsJ9Gd5bWVvsA?feature=share
How did u get t= 2 sec, I got -2 sec. Can u plz explain ??
@@sabitadei2028 t = Sba / Vba = 40 / 20 = 2s 😊
@@sabitadei2028 distance will be - 40 in respect to upper body
@@sabitadei2028 same confusion
13:11 " Tum log humesha mera naam puchte rehte ho My name is ALAKH PANDEY " aaj sabko inka naam pta hai....sir ko btane k zaroorat nhi...... This is called GROWTH 🥺💗✨
51:31 t = 2s & they will meet at 12m from the top of the tower or 28m from the ground.
I think it should be -13m/s
At 17:46.
True
Bhai glti Ho jaati h yrrrr 🙏
Bhai galti hoti rahti hai utna to samajh jao
Hmm shi kaha calculation mistake ho gi
Haa mottu hame bhi pta hai
A best teacher...in the world Who can qualifiy JEE, NEET, and alll type of exams.. Such a great teacher...
Neet shayad nahi kyunki usme bio hai
Jee1:1:1 Subject ratio
Neet 1:1:2 Subject ratio(Bio ka max rAtio hai matlab 2)
@@bullymaguire827 bhaiii sir is best for jee mains and neet physics and chem but not for jee adv........future me shayad sir jee adv ke bhi karaye but abhi tak to nahi karya isleya jee adv ka nahi bol skate
@@anonymous-xm9qz to maine kab kaha ki jee advanced ke liye bhi.Aur sir qualify kar sakte hain uski baat ho rahi hai.Padhane ki nahi
@@bullymaguire827 bhaiii me ye bol raha tha...sir neet phy and chem ke liya more than enough haiii....and maine bas tujhe reply diya maine ye kab bola tu bol raha tha 😎😎😎😎
@@anonymous-xm9qz ok bhai
😀
no why r u.. but why u wasting ur time online?
@@palanivelgovindaswamy4747 then why are u wasting time online?
Aye tum dono chup karo n go n study 👍
Nahi toh Jake hand marao. Pls take h as g int hand
@@nangsolusingkai2732 chup
This lectures are still god gifted for us ❤❤
Like if are watching in 2024-2025
The displacement of ball from tower is - 12m
And , Displacement of ball from ground is 28 m
Good morning bro
You are partially right . The displacement of ball from tower will be - 12m because ball is coming downward towards ground.
Right bro
Time 2s
Position wrt to A -12
Position wrt to B 28
Same name
👍
Sahi aaya hai ans
Bhai 48 aayega
Sir u should publish ur own written physics book❤️...that will be too much helpful for us and future aspirants ✌🏻💫
Nice thought
@@raghavladdha7794 yeahhh (•‿•)
@@manojtiwari5196 hlww
@@manojtiwari5196 aur padhai kaisi CHL rhi hai aapki?????
@@manojtiwari5196 reply toh do????
Homework qs ....solution ....time A ND B MEETS= 2 SEC
position they meet...accrding to A IT MEETS B whn it goes down to 12m
Accrding to body B .WHN IT GOES UP TO 28m. It meets. Body A.
Hence overal total dist given is 40m tht is 12m + 28m..= 40m
Thank you alakh sir ...old never goes old... forever blessed❤❤
17:32 Dear students there is a error it should be -13 as 7-20 is -13 plz correct it
i am in 3rd year of college now,watching it again and feeling nostalgic. So happy to see what alakh sir has achieved now. Epitome of dedication, perseverence and hard work.Proud to be a PWian ❣❣
tu
tu
tu
Tu
Tu
Who are watching in 2024 july
I
Bhai abhi tak kuch nhi pada
@@SanjayVerma-bq4us bhai kal paper ha is liya padh raha hu coaching
Me 🙋🙌🙋😏😏😏
->because old is gold 🙂
Alakh sir's way of teaching is very superb . Alakh sir is a legend of physics.
th-cam.com/video/g9QQ1LmfDFs/w-d-xo.html🙏🙏.......Yes bro
Bro Legend of chemistry too....
Uu are absolutely right ☺️
Rip Alpha series 😢😢
see this video examination in life never give up -th-cam.com/video/k4w4pak66V0/w-d-xo.html
when teachers were teaching in institute and not understanding the concept.
others -- "yar ab kya hoga "
Me -- smiling and thinking , ab alakh sir se samjhunga and kal sabke samne hushyari marunga... 😜😜😜😂😂🤣
Oo good
alakh sir is the best teacher as a friend and a best explanation 🥰🥰🥰👍🏻👍🏻👍🏻😁
@@shahinaparvin3237 yes dear , the next face of god = alakh sir 🤟
Tere class students bhi alakh sir ki video dekh lenge to kya krega
Oh dammm 😂🤣🤣🤣
@@trisharox_2004 🤣🤣
I'm in 11th right now. Everything is new to me. Since 2 weeks I've been struggling with this topic. I always wanted to have a clear cut understanding of the topic. Finally I understood it completely and all thanks to you sir. You are that kind of teacher who everyone desires. Thank you sir, i don't have words to explain how your video helped me.
Brothers i am also present 11 and struggle it... Such a difficult chapter as we haven't study class 9 due to lockdown 😂😂... The hero of lockdown was pubg for us 😂😂😂
@@channelanonymous2457 Nah it wasn't due to pubg or anything. It was difficult in 9th. Even when i focused the concepts were not clear
@@spandana1564 arjuna jee 2024
@@tanuju3930 i did not understand what you are saying here...
But if you want me to join this .. I'm studying for Neet thanks for your suggestion
😊
I feared relative velocity but this man is a magician he made me enjoy physics
Best faculty in physics
If u agree hit like
Bhai aaj 18 april hai aur aaj albert enstein ka death day hai 😢😢😢😢😢
Abay einstein sir bhi physics doosray se physics padh raha hai😅😅😅😅😅😅
@THE PERFECTION CLASSES CONTAI ❤️
Good evening sir!
Homework sum:
Time = 2s
Position:
28m from below
12m from above
Thank You so much Sir, you simplified the topic to halwa! Thank you!!
2s negative mein aaya kya
@@debiprasad633 nahin
Vab kitna h
@@debiprasad633 kya hua be
@@meenugupta2953 are mene pucha h ki velocity of A as seen by B kitna h( V ab)
शाबाश, बेटे ! ईश्वर तुम्हें स्वस्थ, प्रसन्न व आबाद रखें। आदर्श कार्य कर रहे हो। अपनी इस यात्रा को पवित्र बनाए रखना, क्योंकि तुम अवश्य ही एक मील का पत्थर स्थापित करने की ओर अग्रसर हो ! God bless u!
**अद्भुत!!!**
Why you use A -10 plz tell me
@@priyankachauhan755 ?
Those who are very clear with the concepts should definitely watch our videos and solve TYPICAL ADVANCED level questions.
Even concepts are told in our channel by experienced faculties of Narayana.
For Example: th-cam.com/video/8AM-2ao1LpI/w-d-xo.html
For last question Time=2 and point where they meet = 28 from downward to upward and -12 from upward to downward
Besttt lecture ever...this man can do anything...can change our future brightly....thank you soo much sirr!;❤️❤️
Sir please post the videos of best questions of ch-1,2,3,4 from physics class11.
17:23 ans -13m/s ☺️☺️
Yes 😇😇😇😇 silly by sir but it's ok
Yss...by mistake
Yes
Mistake happened np
😀
Who is watching in august 2024
I’m
I AM
I am
I am
Present 😅
Time =2sec
Postion = 28m , -12m.
Thank you sir for this lovely explaination❤️
How did u get a negative length
Hiii
Bhai kaise Aya ans
mera bhi
Same answer 👍 but not sure if it's correct
For last two years,since published,the most understanding video for Relative Motion.
Ans. of homework question.👈🏻
(1) time = 2 seconds
(2) acceleration = 0
(3) relative velocity = - 20 m/s
(4) position where both meet is
28 metres with respect to
lower end and 12 metre
from upper ends....👍🏻👍🏼
formula konsa use hua h bro
@@Abhishek-bhardwaj789 bro covid batch wale ho😂😂 ??
-12 hoga
@@Abhishek-bhardwaj789 bhai pehle relative velocity nikal lena Vab=Va-Vb fir accelaration nikal lena same formula se bas v ki jagah a lena toh woh zero aayega fir t=distance /speed rakh kar time nikal lena aur usko fir s=ut+1/2at2 me rakh katr kisi ek end se nikal lena
bro plz bas iske badle subscribe kar dena
Sir bohot accha padhate ho feeling aa gaya kasam se mera sir kuch nahi kart aise !!!!
Sir a trolley moving front side with a speed 10 M per second, A man moving
backward to 3 M per second, P person who is in the car moving forward 20 m per second (Answer = -13 meter per second)
ans of last question is 28 meter above the ground
and -12 meter down from the top🤗🤗🤗🤗
Same answer yahoo!!!!
Me also
Are u 4 jee 2022???
@@softwareking7223 not I am 4 neet 2022
Time?
Time is 2s when they will meet and position is 12m from top and 28m from down..it was same as previous question which alakh sir gave ..
Relative velocity 1D concepts cleared ..amazing video ..🙂🙂🙂
Yes right ans
I still don't understand how? Vab will come out to be -20 as Va=4m/s and Vb=24m/s so subtracting Vb from Va would give -20 and thus time would come out to be -2s which cann't be possible (although the magnitudes are same as answers as well if negative sign is not considered) . please explain.
Edit: Proper answer can be calculated when Vba, Aba and Sba are considered. without neglecting the negative signs above the correct answers couldn't be brought up. please explain.
@@geeky_001 Vab means velocity of a wrt b so we take the displacement to be negative and thus time becomes positive ie t = -40/-20 = 2s
Police : why I want to chase him?.. I have a gun.
Thief : pls sir.. Don't use gun.. We use relative velocity.
Police : 😓
😂
Dil se salute hai yaar....
🤣🤣🤣🤣
It should be a public place
😅😅😅😅
It's end of 2023 but your lectures are evergreen..❤
Sir you are super 30 of TH-cam 😉
Tanay Patel super 30 nhi super india😊😊😊
@@nayefhoda4331 ya ! Really true
Super se upar wallah
Super 30 nhi super 1.6M
@@spidygaming9273 yaha sirf physics wallah
Only this teacher does not focus on teaching all the concepts but gives a feel in the concepts and relates in real life.
bhaiya, yeh Alakh Pandey sir hai. Shiksha ki Alakh jagah hai, thay aur rahenge.
51:27 Answer:- They will meet after T=2sec and S from ground is 28m and S from top of tower is -12
same bro
Even I got the same answer bruh!!
@@shruthiarao2612 yup
@@shruthiarao2612 nice
@@AlokMishra-og1ub Nice
5yrs old video gives me that knowledge that I can't get it from new videos with smart board ... Kuch to baat hai iss purane video me yuhi nhi ham bachhe fida huye alakh sir pe 😅
TIME 2 SEC
POSITION 28M AND -12 M THANK YOU GURUJI!
@Kalp Patel calculate the answer with respect to velocity 4ms^-1
its correct
@@kalppatel6969 u want image ??
Correct
Uab=4-24 =-20
A=0
T=d/s___distance is given -40
T=40/20=2
S=(ua)t-1/2t^2____s=4×2-1/2×10 ×4
S for ua =-12
We can apply sam eq for ub
S for ub =28
Ans of h/w quest is... t=2sec & S from B at ground =28m, S from A on building=12m. Is it correct???
No
i also think it's wrong
Hiii
Time: - 2sec
Position: - 28m above the ground!
Sahi h 👍👍👍👍
@@derangedxxo6352 😊
👍
@@sangeetagupta3435 🙂
Right answer is 27.6 m from top
Its 2024 still One of the best explanation of motion in 1-D
Sir I am very thankful to u ..my marks are improved from 30 to 88 . ..and I am sure it will be 100 after some days,..
Nikal gya iit kya bhiya?
U= -20
a= 0
S= -40
Therefore t= 2 sec
SA= -12 m
And
SB= 28 m.
Sayad, Aapka answer wrong hai bro
Vab= -28m/s
Aab= 0
Sab= -40
Answer here is
T=1.42sec. and
Sa= -5.68m and Sb= +34.08m
🙇❤❤❤
Hit like👍 if you got this answers
@@himanshu_yadav_0005 Pta Niii Yr mera answer sabse alag q aa rha hai ...mujhe kahin Galati bhi nhi mil rhi hai 😕
Bhai bata toh de konsi ball ko A mana h aur konsi ko B
Bhai u r right
Sir please upload the remaining concept of kinematics like parachute problem , rocket one and two balls at what time reach each other
Yes sir please
Last question answer,
t =2sec.
At u = 4m/,s
S=-12m
At u=24m/s
S=28m
17:30 there Should be -13
Yes, Maine bhi notice Kiya😃
Yeah u ar right
Ya....
Yes you are right but it's just a silly mistake
Yr maine 3-4 repeat karke dekha ki kahi mujhse galti na hogyi ho 😂😂😂 lekin waha par sir galat the
sir will be missing you after 2 years never met an interactive teacher like you
they'll meet after 2s.
at distance of 12m from top of tower or 28 m from bottom
Correct
Correct
T= 2s,
for A (ball of top)=-12m
and for B (ground boll)= 28m
The best physics teacher of the world u r just like God for me sir may u live long n long aur hme uhi pdhate rhe
sir,velocity of A with respect to p (car)observer is -13 m/s.
Human error
what do you mean
Yes not 14 😅
Sir time is relative as per Einstein general theory but you said that time is not relative I didn't understand only this
Watching this video in the time of Coronavirus. Hope everything will get normal soon🙏
And more then 11 following you well me too😆
What is velocity of corona virus?
@@chessfoundation7538 s*x
😂😂😂😂
In which class do you read
In last question answer for time=2sec.
Height A travel= 28 m from ground.
Height of B= -12m from it's initial position.😊
really how he teaches........CHALO BACCHO TUMHE FEEL DILATE H..... the concepts he thinks are hard he repeat almost ten time we students are so proud that we have a teacher like you.............................. thank you so much sir
O SIRJI TUSSI GREST HO.............
Exactly..the reason why he is the best
At 18:00 [7-20=-13m/s] is the answer .. 🙂
Yeah...
Negative kyu aya qki ' S ' toh upar ki taraf haina?
Same here
Yes sir ne -14 likh diya
@@blunderwoman3479 bcoz A w.r.t is moving towards P
That damn FEELING of understanding the topic gives confidence about physics...THATS ONLY IN ALAKH SIR'S CLASS...
❤💜LOve from mysuru 💜❤
t= 2s and , distance -12 from above and 28 from below
The time is 2sec and 24m/s meet at the 12m and 4m/s meet at the 28m
ulta bol diya
@@vipulbharde9648 ha ulta bol diya
For all those asking Yes this is the best lecture I have seen so far for Relative Velocity thanks Alakh sir 🙏
For last ques
time will be 2s
position with respect to A will be -12m
position with respect to B will be 28m
Those who are very clear with the concepts should definitely watch our videos and solve TYPICAL ADVANCED level questions.
Even concepts are told in our channel by experienced faculties of Narayana.
For Example: th-cam.com/video/8AM-2ao1LpI/w-d-xo.html
Who are watching in 2024 June ❤
😂me
Me, I need to learn this to complete my exam
Watching in July
😌😎
Me
Time is 2s and height from a=12m and b=28m....