Khan Academy and Michael Carrigan did a better job The minus sign of centripetal acceleration applies to the "position vector" and NOT to omega squared. The position vector is more accurately called Radial direction as opposed to Radial magnitude. The latter is given by the Pythagorean parametric equation and is a constant hence not differentiable
I've been looking to an answer to a question I have from my physics book for almost two hours and I finally found it here. Thank you so much.
lol
yay cheating xD
learned this right before my engineering midterm you're an actual god thank you
Bro you don't know for how long I was looking for this, UNSW Phys textbooks don't have the working out, god bless you
Same man they just write something like dtheta/dt and idk what that was so i am here
Why didn't we write 'alpha symbol' for W(because dW/dt= 'alpha symbol') when when we performed differentiation of acceleration ?
arent we supposed to differentiate r(t) on the right side too? because its dependent on t to? what am i missing
The differentiation of the r vector is v and the v vector is a
You missed out on a key way of comparing two vectors to see if they are perpendicular, the dot product.
Noice 😎
Nice
omg that's croizy. My teacher never explained this!!!!!!!!!!!!!!!!!!!!!!!!!
Khan Academy and Michael Carrigan did a better job
The minus sign of centripetal acceleration applies to the "position vector" and NOT to omega squared.
The position vector is more accurately called Radial direction as opposed to Radial magnitude. The latter is given by the Pythagorean parametric equation and is a constant hence not differentiable