Well done sir. Pls can you tell me why my readings on the ammeter is higher than your? When my l=20 ammeter reading was 3.5A. I did the connections correctly
Thanks for teaching. It was helpful but in the second scenario, you omitted the cross sectional area when çalculating the intercept, also you did not explain how the cross sectional area could be obtained. Thanks
Thank you for your feedback. At 14:50 , there was a slight error in the formula for the y-intercept. It should be c = -R0A/ρ. instead of c = -R0/ρ. The cross-sectional area is usually calculated using a micrometer screw gauge to measure the diameter of the potentiometer wire. Given the diameter, d, of the wire, A = πd²/4. This area could be given as a constant. If the area is not given, you could be asked to determine the resistance per unit length given the slope or y-intercept. Resistance per unit length = ρ/A = E/slope or -R0/c in the second scenario.
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Which of the scenarios came in the wassce practical?
You are a Scholar, well done.
In the physics lab is there a simulation for each one of the scenarios you stated or only for the one you decided to perform.
Well done sir. Pls can you tell me why my readings on the ammeter is higher than your? When my l=20 ammeter reading was 3.5A. I did the connections correctly
Thanks for teaching. It was helpful but in the second scenario, you omitted the cross sectional area when çalculating the intercept, also you did not explain how the cross sectional area could be obtained. Thanks
Thank you for your feedback. At 14:50 , there was a slight error in the formula for the y-intercept. It should be c = -R0A/ρ. instead of c = -R0/ρ. The cross-sectional area is usually calculated using a micrometer screw gauge to measure the diameter of the potentiometer wire. Given the diameter, d, of the wire, A = πd²/4. This area could be given as a constant. If the area is not given, you could be asked to determine the resistance per unit length given the slope or y-intercept. Resistance per unit length = ρ/A = E/slope or -R0/c in the second scenario.
The problem is what’s the resistivity and Area of the Constantine wire