When rotating my hand over the axis I am demonstrating Torque cross product. The thumb on my right hand is effectively pointing out of the board if I were to grip the axis. All that means is that as I curl my fingers around it shows the direction in which the object will rotate, in this instance that would be in a positive counter clockwise direction, indicated by the positive symbol showing a force in that direction. If you know anything about the cross product for calculating Torque, you will understand my fingers would effectively be in the direction of the first vector which is R, and then as they close they cross or sweep into F, and my thumb pointing in the direction of the resultant. I will do another video on the cross product for calculating Torque which may have helped to understand my thought process while ranting. Anyway, thank you for watching. Keith.
Interesting mate, it's a complex topic for sure, not sure on the door example as the torque measured (at the axis = hinge) at the moment that the door opened would be the same in both examples, just force required (effort) would be different based on hand position on the door (lever length). Regarding the use of gearing, this only applies for increasing torque at the drive wheel without increasing effort. My simple explanation is that lever length (conrod) determines how much torque a given/static effort would produce on a rotational axis. Great vid mate, enjoyed it 👍
A greater force is required as you get closer to the axis, shorter lever. I was trying to say that theoretically, producing torque at high rpm is better than producing torque low rpm, as at high rpm you can use gearing. As you know a powerful engine is useful because it can then be geared down - like I don't want the rear wheel of my bike doing 8000rpm! So gearing down reduces the speed at the rear wheel with a corresponding increase in torque. Obviously this does not affect the power of the engine, well apart from frictional losses due to heat and all that nonsense. Cheers for watching mate. As always.
@@ShedTorque46 We're saying the same thing basically, we both understand what torque is, just you are covering the science bit lol 😉 Yeah increasing torque at higher rpm increases work done, naturally slipping into the bhp and torque relationship
@@rhydtuned It was a half hearted effort mate. I was actually just fed up of people calling it a force, but I went off on a tangent and didn't really cover the whole picture. I am going to do an in depth torque as a vector video that will surely bore us both to death. In the meantime I need to get back to my project bike as I need to rebuild it and get my forks re-chromed. That and get the tank sprayed that I fabricated. Work gets in the way of everything 😂⚙️🔧
When rotating my hand over the axis I am demonstrating Torque cross product. The thumb on my right hand is effectively pointing out of the board if I were to grip the axis. All that means is that as I curl my fingers around it shows the direction in which the object will rotate, in this instance that would be in a positive counter clockwise direction, indicated by the positive symbol showing a force in that direction. If you know anything about the cross product for calculating Torque, you will understand my fingers would effectively be in the direction of the first vector which is R, and then as they close they cross or sweep into F, and my thumb pointing in the direction of the resultant. I will do another video on the cross product for calculating Torque which may have helped to understand my thought process while ranting. Anyway, thank you for watching.
Keith.
Thanks for sharing knowledge
No problem, thanks for watching ⚙️🔧
Interesting mate, it's a complex topic for sure, not sure on the door example as the torque measured (at the axis = hinge) at the moment that the door opened would be the same in both examples, just force required (effort) would be different based on hand position on the door (lever length). Regarding the use of gearing, this only applies for increasing torque at the drive wheel without increasing effort. My simple explanation is that lever length (conrod) determines how much torque a given/static effort would produce on a rotational axis. Great vid mate, enjoyed it 👍
A greater force is required as you get closer to the axis, shorter lever.
I was trying to say that theoretically, producing torque at high rpm is better than producing torque low rpm, as at high rpm you can use gearing. As you know a powerful engine is useful because it can then be geared down - like I don't want the rear wheel of my bike doing 8000rpm! So gearing down reduces the speed at the rear wheel with a corresponding increase in torque. Obviously this does not affect the power of the engine, well apart from frictional losses due to heat and all that nonsense. Cheers for watching mate. As always.
@@ShedTorque46 We're saying the same thing basically, we both understand what torque is, just you are covering the science bit lol 😉 Yeah increasing torque at higher rpm increases work done, naturally slipping into the bhp and torque relationship
@@rhydtuned It was a half hearted effort mate. I was actually just fed up of people calling it a force, but I went off on a tangent and didn't really cover the whole picture. I am going to do an in depth torque as a vector video that will surely bore us both to death. In the meantime I need to get back to my project bike as I need to rebuild it and get my forks re-chromed. That and get the tank sprayed that I fabricated. Work gets in the way of everything 😂⚙️🔧
@@ShedTorque46 Tell me about it (work!) Yeah, torque is not a force... Muppets lol
Just remember...American v-8s mighty...😏...all others..puny...except for those wizardry rolls merlins...😒😬😝and diesels with compound turbos..🤓