Block Forced Against a Wall with Friction: Calculate the Range of Forces to Remain Stationary

[@charliegamar6860]

I love straight forward this was. Now I can finish writing my assignment.

[@INTEGRALPHYSICS]

thats what we do here.

[@vaibhavk966]

man you explained it so good youre explanation is great and thank u so much

[@INTEGRALPHYSICS]

You're very welcome!

[@Being_NITIAN]

Thanks for keeping it simple... Lots of love from 🇮🇳❤️

[@INTEGRALPHYSICS]

Thanks. this is a fun problem.

[@AbdirahmanAbdi-g9k]

thanks man , made it seem so simple

[@INTEGRALPHYSICS]

Glad it helped

[@legendaryeyad4511]

That really helped, Thanks, a lot.💜

[@INTEGRALPHYSICS]

Glad it helped!

[@kojinakazawa3009]

you are a life saver

[@INTEGRALPHYSICS]

thanks!

[@leahjolley8822]

Thanks you r rlly helpful

[@INTEGRALPHYSICS]

Thanks!

[@nemon_nori]

why is Fpush*cos?

[@sumansharma9205]

But why are we taking Limiting friction here ??

[@shaurya8555]

Because the block is not moving its in equilibrium(we consider limiting friction when a block is not moving)
We would consider kinetic friction if it was falling down...

[@bejugamjayashankar7867]

Yaa

[@SirThorp]

What about in the case of a non zero acceleration?

[@INTEGRALPHYSICS]

Then you need to apply F=ma to the y axis. The imbalance between the vertical component of the applied push force, friction and gravity will result in a net force vertically.