Rolle's Theorem

[@sifrael]

2 for the price of 1. Teaching's outstanding, quotes uplifting. Who could ask for more?

[@ayushmaandev9437]

thank you sir...due to this online classes situation...most of my doubts were left unclear...your video was a life saver

[@sifrael]

@CrimsonGuard1992
On the unit circle, the cosine of an angle = 0 at pi/2 or 90 degrees and 3pi/2 or 270 degrees.

[@AyukiAkiba]

What kind of tablet are you using?

[@dorikanellos2586]

Great job as ALWAYS. I love the Differential equations lessons, that’s a vivid example for the sorry examples floating around. D🦅

[@Mathispower4u]

Thank you. I appreciate your support!

[@akanshaparmar7114]

Good explanation .. sir can you pls tell how you solve last ques... Why we will take pi/2 ??

[@CrimsonGuard1992]

I don't get the art where he gets pi / 2. Where did that come from?

[@gaithlame9041]

thank you . can your explain some examples about generalized Rolle's theorem.

[@CIAmpi1211]

You're a great teacher!! For the fact that I'm learning calculus on my own and I haven't found out yet, how and why is the f '(x) at 4:45 the derivative of f(x)=(x^2 - 2x)e^x. There must be some rule or theorem behind so if someone could tell me it :)

[@jimyleaks]

the cosine of an angle at 3pi/2 or 270 degrees will be also 0..

[@yeab1998]

dont you have to use chain rule on function f at 4:08?

[@Mathispower4u]

The function f = x^2 - 2x is not raised to a power, so we don't need the chain rule here.

[@yeab1998]

Mathispower4u OK makes sense. thanks. also, how do you determine if the function is continuous at [a, b] & differentiable at (a, b). I'm kinda confused about that part

[@ritobrataghosh1462]

Hi, thank you and I want to know what are the software you are using to make this video (everything including the graphing, writing, slides and video recording).

[@ThoraxetheImp]

Are the two intervals always 0? Or do they just have to be the same?

[@studytimebyarif7290]

if a function is combined with trigonometry and exponetial term like
e*x cosx how to solve?

[@gokutilapa]

This has helped me a lot!

[@SquarePupilIndustr]

I prefer you to Khan. Minimal and complete.

[@Mathispower4u]

Christianpatrickgalles Galles Thank you for the comment.

[@AnkitJainCreations]

Can i ask you how f '(x) = 2x - 3 ?

[@dr.alokagrawal9390]

no

[@thomastran9953]

Thank you for the clear explanation.

[@ThuyNguyen-bu9ge]

But on the interval of pi/6 to pi/3, there is no pi/2. Pi/2 is beyond pi/3, thus it's not in the interval [pi/6, pi/3].

[@Mathispower4u]

Tiffastic Nguyen Right, but we are looking for a x value. 2x = pi/2 so x = pi/4 as shown which is in the interval.

[@quriositysquared1028]

Simply awesome. Thank you

[@christopherepperly3675]

isn;t sin pi/3 1/2?

[@arenics]

not only at the slopes the derivative = 0, you forgot about the inflexion points.

[@murrayivan]

Thank you posting this.

[@MotherBra1n]

that was really useful, thanks

[@MiserableGamingHub]

i wish my teachers made it this easy

[@FelixMogaka]

Good teacher

[@joeyofblades]

Very helpful thank you!

[@nfsking2000]

If f is discontinuous at that interval.

[@jesseokeya]

Thanks A lot Was Very Helpful

[@rahulkr1515]

great job👍

[@mohanparanathala320]

wow ty very much simple and easy

[@shreymantu]

just same

[@froopi2]

Thanks!

[@salutaldegrandfan6171]

thx from morocco

[@mahirasgarov9227]

thank you

[@kermz100]

f(1) = -4 and f(2)= -4....u must add before u substract

[@kennethcastro7108]

WTF

[@kermz100]

i still understand tho thanks alot

[@jhoannagonzalez4107]

Oh my gosh it finally clicked

[@saiteja2126]

tanx a lot

[@abdullahiahmedmohamed3925]

half decent