So for this question at 12:17 , I wrote the second part differently but the results was the same as yours I put ; = x (11x + 7 ). 2 ( 11x+2) and got = (11x + 7) (x+2) I got the end result correct but was the way I wrote and went about things in the second and first step ok?
@@mauleenahjlouis7589 Yes you always have a couple of ways because you can write 22x + 7x or 7x + 22x for the middle two terms since the order of addition does not matter :) Does that answer your question?
@@guerillagardener2237 Missing terms reduces the work. Example with no constant term: 2x^2+4x -> just common factor 2x out 2x(x+2). Example with no linear term: 2x^2 +5 --> nothing factors here. Example with no linear term: 2x^2+4 --> just factor a 2 out 2(x^2+2). Thats all
First convert to the form a(x^2 +bx +c) then solve (b/2)^2 - m^2 = c for m. Then the factored form is a(x + b/2 - m)(x + b/2 + m). This makes the entire factoring process nearly mechanical.
Forgot to mention that this video is part of a playlist where grouping is the second video, so I use the decomposition/grouping process to leverage and reinforce that skill. The funny part beyond your great explanation (which I like a lot), is that you can just guess and check if the numbers are fairly small without too many factors. I think you'd love my explanation of how to factor something like: x^2+192x+8687 without a calculator on paper in approx a minute (depending how fast your hand arithmetic is) Best wishes -- John
You are the best!!!
Haha! You're a factoring machine
So for this question at 12:17 , I wrote the second part differently but the results was the same as yours I put ; = x (11x + 7 ). 2 ( 11x+2) and got = (11x + 7) (x+2) I got the end result correct but was the way I wrote and went about things in the second and first step ok?
Because in the first step I put 11x squared + 7 + 22+14
@@mauleenahjlouis7589 Yes you always have a couple of ways because you can write 22x + 7x or 7x + 22x for the middle two terms since the order of addition does not matter :) Does that answer your question?
Your a good teacher.
Thank you :)
At the moment I'm still trying to fathom quadratic equations with linear and no constants, constants with no linear.
@@guerillagardener2237 Missing terms reduces the work. Example with no constant term: 2x^2+4x -> just common factor 2x out 2x(x+2). Example with no linear term: 2x^2 +5 --> nothing factors here. Example with no linear term: 2x^2+4 --> just factor a 2 out 2(x^2+2). Thats all
@@drgatsis It's the one where you have to square both sides that is confusing me. Dealing with irrational numbers and things like that.
@@guerillagardener2237 Solve by completing the square? If that's the one, I dont have a video on it. But there are lots of videos in google search
I understand how to factor now!
Awesome!!!
First convert to the form a(x^2 +bx +c) then solve (b/2)^2 - m^2 = c for m. Then the factored form is a(x + b/2 - m)(x + b/2 + m). This makes the entire factoring process nearly mechanical.
Excellent
Forgot to mention that this video is part of a playlist where grouping is the second video, so I use the decomposition/grouping process to leverage and reinforce that skill. The funny part beyond your great explanation (which I like a lot), is that you can just guess and check if the numbers are fairly small without too many factors. I think you'd love my explanation of how to factor something like: x^2+192x+8687 without a calculator on paper in approx a minute (depending how fast your hand arithmetic is) Best wishes -- John