Replace the loading by a force and couple moment acting at point O

[@MrPJBarney]

Hi. I am confused about why you do not have reaction forces at the support where 15kN is being applied.

[@jackcorcoran2107]

I've learned moments to have a positive direction in the opposite way. Is there any specific advantage or difference it makes in having different moment directions?

[@jerryburke7877]

you can assume anyway dif teachers have dif rules

[@bbjane254]

I couldn’t get the 5 and 9 distance

[@aamirmansuri4702]

7.5-(1.3)7.5 7.5+(1/3)4.5

[@thehobofire]

7.5/(1/3)=2.5 then 7.5-2.5=5

[@atbz6952]

im confused about where the 1/3 came from

[@ibrahimalmalki8406]

its just the center of triangle where the force is.

[@cedrickansus5428]

@@ibrahimalmalki8406 why don't use 2/3 instead of 1/3?

[@ibrahimalmalki8406]

@@cedrickansus5428 it depends what side of the triangle you start at. You can use either it doesn't matter, but your reference point changes.

[@joedavis5317]

Dax,
If your steel beam weighed 1.5kN. How and where does this force factor into the single resultant force?

[@willem9665]

i think in the middle of the beam or center of gravity as m.g or 1.5kN as you said

[@Fabiana-dl8sm]

Graciaas

[@leeterrebonne661]

good man

[@gh0stmoon1]

kingo

[@LeylanEsmail]

clockwise is negative dear

[@bobbyd7159]

The direction of positive is arbitrary. However the problem already establishes a positive 500 kN m moment in the clockwise direction, so for this problem clockwise is positive......dear.

[@josephregalario704]

I agree lailan

[@MOHAMEDABDILLAHIARABTKT]

boring

[@slowsx5135]

[@zachbowen6828]

no shit, it's statics XD