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This is definitely the most elegant derivation of the sigmoid function that I have seen! I am extremely grateful to MIT for giving me free access to such amazing lectures
this helps me gain insight for logistic regression analysis, beautiful
Beautiful.
wow isnt it sigmoid function?
Could anyone tell me why e^-2y is not e^2y? I calculated it {e^-1/2[(y-1)^2]}/{e^-1/2[(y+1)^2}= e^-2y but I didn't get the right answer. Thank u
k=1 corresponds to e^-1/2[(y-1)^2]. (leaving out steps) the denominator becomes 1 + {e^-1/2[(y+1)^2]}/{e^-1/2[(y-1)^2} = 1 + e^-2y
well explained!
Add more examples would be better
This is definitely the most elegant derivation of the sigmoid function that I have seen! I am extremely grateful to MIT for giving me free access to such amazing lectures
this helps me gain insight for logistic regression analysis, beautiful
Beautiful.
wow isnt it sigmoid function?
Could anyone tell me why e^-2y is not e^2y? I calculated it {e^-1/2[(y-1)^2]}/{e^-1/2[(y+1)^2}= e^-2y but I didn't get the right answer. Thank u
k=1 corresponds to e^-1/2[(y-1)^2]. (leaving out steps) the denominator becomes 1 + {e^-1/2[(y+1)^2]}/{e^-1/2[(y-1)^2} = 1 + e^-2y
well explained!
Add more examples would be better