I used to be so stressed out about my chemistry exam, but now with your videos I understand so much more and feel much better. I can't even express how thankful I am! Your goal of taking away the stress has definitely been reached!!
Thank you so much literally been searching for this topic since a while and i am very happy to land up here from now on I'll follow you're lectures very understandable for me atleast.once again thank you so much sir🙏🏻😌
I so much love the way you break down your teaching to the barest minimum unit❤❤❤ and makes it easier for one to grasp easily😊😊 You're so good sir... Bravo🎉🎉 🇳🇬🇳🇬🇳🇬 #UniPort #Nigeria.
Chad I gotta tell ya....you're bloody good ...in fact there are only 2 things that I would do in addition : 1) slow down 2) use a mind map at the beginning of each lesson to put into perspective a summary of what you are about to teach
You are not chad , You are a Real Gigachad sir , actually I'm from INDIA , i didn't get any vid for precipitation in youtube , i was scrolling down and down , then I saw your video... Excellent man ❤️🎉
23:12 Hi, thank you so much for these videos. I was wondering why the Hydroxide concentration is not doubled. I understand why it's squared but shouldn't it also be doubled? If we did an ice chart for this, the Mg2+ would be +x and the OH- would be +2x. So why aren't we multiplying the hydroxide concentration by 2?
Hey Aliza, the 1 Mg2+ : 2 OH- ratio from the chemical equation tells us the ratio that Mg2+ and OH- are formed when we start with one molcule of Mg(OH)2. But here our source of OH- is from NaOH so we use the concentration of NaOH only... each NaOH gives us only one OH- so we do not double it
Hey Talumba, are you referring to the dilution calculation at the 25 minute mark? Here we use M1V1 = M2V2 which is derived from the Molarity = moles/Volume formula, just a quicker method and very useful to learn :)
Hey Priyanshu, the OH- concentration is formed from the NaOH where we have the following dissociation NaOH > Na+ + OH- so [OH-] and [NaOH] are in a 1:1 ratio
Could you solve this problem please if BaSo4 was precipitated in solution contain 0.012 M NaCl and 0.002 M BaCl2 .calculate the sulfate concentration which is sufficient for saturate the solution with BaSo4 , if you now that the Ksp for BaSo4 equal to 1*10^-10 .
The second to last question just has a solution of Mg(OH)2 and we are finding out how much OH- is present based on the dissociation constant. The last question is taking two different solutions - Mg(NO3)2 and NaOH and mixing them together to see if a precipitate of Mg(OH)2 forms
I used to be so stressed out about my chemistry exam, but now with your videos I understand so much more and feel much better. I can't even express how thankful I am! Your goal of taking away the stress has definitely been reached!!
Great to hear!
You are SAVING my life with this chem exam tomorrow. Thank youuu!!
You're welcome - I hope you do well.
These videos have helped me get the highest score on midterm 1 and 2 in chem 1-b. Thank you.
Excellent - way to go!
Thank you so much literally been searching for this topic since a while and i am very happy to land up here from now on I'll follow you're lectures very understandable for me atleast.once again thank you so much sir🙏🏻😌
Glad you found us - Happy Studying!
@ChadsPrep ❤️
I so much love the way you break down your teaching to the barest minimum unit❤❤❤ and makes it easier for one to grasp easily😊😊
You're so good sir... Bravo🎉🎉
🇳🇬🇳🇬🇳🇬
#UniPort
#Nigeria.
Kind words - thank you.
I've been watching the gen chem and orgo playlists, and they've both been extremely helpful. Your efforts are greatly appreciated. Thank U!
Glad to hear it - You're welcome!
I literally stayed up all night watching this so nice and explanatory,thank u very much sir
You are welcome!
Chad
I gotta tell ya....you're bloody good ...in fact there are only 2 things that I would do in addition : 1) slow down 2) use a mind map at the beginning of each lesson to put into perspective a summary of what you are about to teach
Thanks for the feedback :) You can always slow down the video speed in your TH-cam settings
Gosh I legit cannot thank you enough, I finally get equilibrium.
Excellent!
You are not chad , You are a Real Gigachad sir , actually I'm from INDIA , i didn't get any vid for precipitation in youtube , i was scrolling down and down , then I saw your video... Excellent man ❤️🎉
Thank You!
Thank you so much. I was able to get an A in my Gen Chem 2 because of your lectures.
EXCELLENT - way to go!!!
thank you so much I just love your videos they are so helpful !! I just have a question though, when Qsp
23:12 Hi, thank you so much for these videos. I was wondering why the Hydroxide concentration is not doubled. I understand why it's squared but shouldn't it also be doubled? If we did an ice chart for this, the Mg2+ would be +x and the OH- would be +2x. So why aren't we multiplying the hydroxide concentration by 2?
Hey Aliza, the 1 Mg2+ : 2 OH- ratio from the chemical equation tells us the ratio that Mg2+ and OH- are formed when we start with one molcule of Mg(OH)2. But here our source of OH- is from NaOH so we use the concentration of NaOH only... each NaOH gives us only one OH- so we do not double it
@@ChadsPrep Hi , but why we square it then? it means we should use just concentration of OH multiplied by concentration of Mg ? Thank you for videos
Thank you so much that was great! Keep making these videos please.
You're welcome and Thank You.
Wow it feels way easier than when I listened my teacher's lecture...
Glad you found us.
Thank you bald man 🙏🙏🙏🙏🙏🙏🙏🙏
Very welcome, person of undetermined hair quantity!
This vid is just what I needed
Excellent!
Thank you , you saved me !!
That's great!
yo ur examples are dope.
Thanks
Such a good video, thanks so much!!
You're welcome!
Hey Chad, why do you only find the mg's new molarity and ignore the oh's new molarity? Am I missing something basic?
I think its cz of the one to one ratio 😅
Perfect explain
Thanks!
I have a question why are wee not usin the formul of molarity overr volume to find the concentrations ??
Hey Talumba, are you referring to the dilution calculation at the 25 minute mark? Here we use M1V1 = M2V2 which is derived from the Molarity = moles/Volume formula, just a quicker method and very useful to learn :)
@@ChadsPrep ooooooh ok thank youu
@@TalumbaGondwe You're welcome!
I still don't understand why we used 1×10^-4 as the M of the mixture
at 19:32 when you're writing out the equation why did you ignore the nitrate given in the problem? How did you know to replace it with OH?
Common Ion effect we ignore nitrate since its not on the dissociation reaction while we use Mg and OH since they are the common ions
Great life saver
Wow!
22:40 hey chad, why is the OH concentration not doubled, like according to the balanced equation
Hey Priyanshu, the OH- concentration is formed from the NaOH where we have the following dissociation NaOH > Na+ + OH- so [OH-] and [NaOH] are in a 1:1 ratio
Life is good sir!
Great!
Could you solve this problem please if BaSo4 was precipitated in solution contain 0.012 M NaCl and 0.002 M BaCl2 .calculate the sulfate concentration which is sufficient for saturate the solution with BaSo4 , if you now that the Ksp for BaSo4 equal to 1*10^-10 .
I do not get what is the difference between last two questions? Like at the end of the day we are adding NaOH to Mg(NO3)2
The second to last question just has a solution of Mg(OH)2 and we are finding out how much OH- is present based on the dissociation constant. The last question is taking two different solutions - Mg(NO3)2 and NaOH and mixing them together to see if a precipitate of Mg(OH)2 forms
last question was tough. Saving the best for the last?
شكرا ❤
You're welcome
Also thanks these videos are really helpful!
Glad you think so!
thanks Chad.
You're welcome
@@ChadsPrep I'm here 2 weeks later to tell you that I passed my chem test. Wish I had found you earlier.
@@otsi.l Glad you did!
Thank you so muchhhhhhhh
You are very weeeeeeelcome!
thank you SO MUCH
You're welcome and Thank You!
Thank you so much!!
You're welcome :)
Sir you are saying that we have no evidence whether our reactant is present or not then how could we calculate ksp
what time in the video is this?
Sir I extremely sorry about my attitude l never ask any sort of question again l don't what happens to me
Sir sorry, sorry sorry sorry sorry
no problem if you have a question about the video just let me know what time it is and I can help
Sir 1 year ago you have released the video but I don't know whether it is of 2021 or 2022 it is about common ion effect and precipitation
how are you going to define simple ionic effect in words
24:19
Hey animeworld! Do you have a question for this part of the video? :)
❤
Great!
bless you and your bald head
Thank you to you with your unclear amount of folicle quantity. Happy Studying!
@@ChadsPrep😂 well that's a very professional comment right there
@@AbhiramKarthik-qt1xp 😁😁😁
Hi Chad! Why is it that we don't include the coefficient of OH of 2?
Question under ''Introduction to Precipitation''
Hey JJang! The 2xOH- are accounted for in the Ksp [OH-]^2
Hero
Happy Studying!
❤
👍👍👍