Challenging World's Most Selective University with Coding Question!
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- เผยแพร่เมื่อ 30 ก.ย. 2024
- Challenging Stanford Students to code in 5 mins with a problem asked in IIT & MIT exams!!
Edited by Chaitanya khachane
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Everytime I watch his video, I start doing leetcode for a week and then stop. 😂
Relatable😂
@@rohanIVYhow do you decide on the list of problems?
@@boy0607boy no. Of likes on the problem
Me tooo
Let me take your mock interview if you are still alive!😊😂
honestly, I really enjoy such content harnoor, please continue doing such type of vids. I really appreciate your effort man
Their names were Sanjay,Sahil & saurav and they were not from India🙃.even foreigners give Indians name to their children.
They are from Indian origin not Indian their parents are probably 2nd Gen Immigrants
@@sxmeersharma Sahil from Bangladesh
@@mrkiba1781 it’s a common name in both countries he could be even Pakistani
I guess they are OCI's
@@sxmeersharma he is my relative, don't claim anyone Indian origin
Good to see people appreciating difficulty at IITs ....
Tho tu kyu khush ho raha
@@rohanIVY INKO IIT ME NAUKRI LAGA HAI. JANITOR KA
@@rohanIVY dikhai nahi deta woh professor hai !!🙂🥲
@@rohanIVY Because I was at one point involved in studying for these institutes. I understand how hard it is to get in.
@@akashpaul4143 Bhai phir toh muje kal paaka asli Willi smith ne comments meh gaali di
14:03 best part 😂
देखते हैं🇮🇳🇮🇳 इस तिरंगे को कितने लाइक मिलते हैं
The way SHE told that why she was able to solve the 'leetcode' questions, shows us the harsh reality of being poor. Kudos woman.👍🏿👍🏿
bro that string question is cake walk level 😂
Stanford Universities not all students r as briliant as iitians
As 40-50% goes to iit due to their social activities in international level
bhai indians hi indians dikh rahe sab jagh..hahah..its like u r in dilli sarijini nagar..so happy seeing indian roots at all places !!
I’m loving this series of asking questions to top College students❤
you go to USA and find Indians there
IIT--jalba h hamara 🤣
BCA student here ❤️
x=int(input(enter the no;))
y=x/2
if y==x//2 :
print("is a power of 2")
maybe the second question cqn be solved like this
why bother doing that? just use bitwise to solve it
public static void main(String[] args){
int x = [INPUT];
int ct = 0;
while(x > 0){
if(x & 1 == 1){
ct ++;
x >>= 1;
}
if(ct == 1) System.out.println("is a power of 2");
else System.otu.println("not a power of 2");
}
very easy
@@Sanyu-Tumusiime that seems more hard though 😅😅🤣🤣
Hey yours will be wrong as for ex of we take 12 it will return 6 and 12//2 also returns 6 even though they are same we know that 12 is not a power of 2
@@Vvarsha007 you're right. it will be wrong. use my solution
@@Vvarsha007 you are absolutely correct ma'am and i agree as now I can see I am purely wrong there btw I started to learn programming 3 months ago so no hardships 😁
Let's see what this world has to offer for me 😌
My son is doing CS from UTS in sydney and Its my dream to see him get his masters from MIT.
We want this type of content More and More and Most
Aryender is doing such an amazing job as Harnoor's new partner! Also giving away 100 or 50 USD to these students who can afford leetcode premium doesn't makes much sense! Why don't you give your Indian subscribers a question who can't afford leetcode premium?
Please make more videos like this 🥹 really enjoy watching them. Very insightful
um with u
14:00 "IIT" be like Raula hai hamra , kabhi kabhi to lgta hai apun hicch bhagwan hai.
Still not in top 50 in global list where as MIT and Staford are in top 3
Honestly i enjoy the series It's great to know the foreign students how they study in college and what apporch they think 💬. And sir one request is there , can you make a video for Bca students . How they can start to do coding and after doing bca they should do masters for multinational companies . And for multinational companies only coding is important or any more thing we have to study. Because we are learning basic things of coding . And one more thing i am noob in coding so how can i start coding can you explain in video or reply here . And for coding you can prefer any book .
Same
This students are quite intellegent .
Bhai won Stanford hai
Wahan to honge hi
Ivy league kids are literally out of this world
Facts
For the power of 2 one you can just do log(number)/log(2) and if its an int then you know the number has a base of 2. However, I may have also misunderstood the question lol.
Man I just saw this video to make me realize how dumb I am.
Hey bro I need more videos like mit students solving iit question paper and iit students as same as mit question paper. Need from you
Whole Budget Of This Video:- $300 =₹24,501.14 😄
and revenue just 5 times of the investment
Keep posting such videos. They are very inspiring.
What is Lewis Hamilton doing in Stanford??🤔
For powers of 2 Idk
bool is_power_of_two(int number) {
return number > 0 && (number & (number - 1)) == 0;
}
Could someone check please 10:31 10:32 10:35
# Adding 2 Binary Strings:-
#include
using namespace std;
string bin(string &s1,string &s2)
{
int i = s1.size() - 1;
int j = s2.size() - 1;
int carry = 0;
string res = "";
while(i >= 0 || j >= 0 || carry)
{
int n1 = (i >= 0) ? s1[i] - '0' : 0;
int n2 = (j >= 0) ? s2[j] - '0' : 0;
int sum = n1 + n2 + carry;
carry = sum / 2;
res.insert(res.begin(),(sum % 2) + '0');
i--;
j--;
}
return res;
}
int main()
{
string s1 = "101";
string s2 = "0010";
cout
For 2 to the power n, can’t we just take base 2 log of the number. If we get an integer back. Then it’s true else it’s false. That would also be constant time. Assuming log2 function has constant time.
Where can you get that log function from ? Not every lang is python.
@@spiderop2125 exactly...That is what I was thinking
Yeah it can be possible in Java and CPP both they have log functions
They’re basically asking them to code the log function from scratch. In the most efficient way possible
MIT admissions process pa ek video banaow bahi
The O(1) solution is limited by the address space of the registers in the CPU and ALU. So for very large powers of two, like above 2^64 it may not be as efficient. Depends on how many bits the registers can store. Disclaimer: This is just thought aloud. Might need more verification.
yeah but the input itself is stored in int/long format so this solution would work
int range 2^31-1
I would have gone for;
int a ;
if (2 modulus a == 2) {cout
No...
I thought MIT < Stanford. Anyways bro you got to get a dedicated mic since the device is picking up sounds of the background as well
lmao why , MIT is #1
All of these videos are so good, especially at Stanford and with the Meta guy!!
Mai bba ka student hu pr Mai ek code developer bna cahta hu to kya Mai bn skta hu agr bnta hu to bhi kya mujhe achi job milegi jaise ki btech walo ko milte hai
i am from pakistan i don`t no what an diffecult level(mean at logically level not craming ) iit take off the test but an incridble change in india education really appricated ....
He never stop to motivate people 🥺
Why indian names look peps from another country
Because of lot meat consumption and environment our genetics are strong but not get proper nutrition
Bro my brain 🧠 is hanged after watching match . Any mathematic solution for this?
kuch samjah nehi aya but sunke achaa lagaa :)
Super video Bro Nice Intro
Wow awesome 👌
Appreciating for Last girl 👧
You can visit mission college to contest code in 5 minutes
Video seems to be lagging. Anyways harnoor great content.
This is just a pure understanding of how binary operations work…. Nothing too technical on algorithm.
Admission in IIT is much tougher than MIT, People like you who not able to clear JEE moved to US/UK for further degree course.
Please make video on MIT VS STANFORD
just stupid idea bro
And me thinking the optimal solution for power of 2 => (ceil(log2(n)) == floor(log2(n)))
For the second problem I'm actually surprised the first guy didn't have a clue of the most efficient way. I'm a CS Junior and one of my first class last semester was about assembly. It helped me so much with the understanding of problems like these.
Yeah but after 3 months you’ll forget it 😂
First'
# One of the better ways to find if the number is a power of 2:-
#include
using namespace std;
bool f(int n)
{
if(n == 0)
{
return false;
}
int count = 0;
while((n & 1) == 0) // when the lsb is set the loop stops.
{
count++;
n >>= 1;
}
if(n == 1)
{
return true;
}
return false;
}
int main()
{
int n = 16;
cout
Is everyone knows about iit in stanford
IIT Bombay CS students be like bruh that is most basic question u gonna get...
12:00 *That's why I'm at Stanford not MIT*
As if Stanford is the LPU of USA.
I have a question for all of you.
Q1. Given the root of a binary tree where every node contains a natural number, return the maximum path sum from node to leaf.
recursion
Lots of Indian names like Sanjay , sahil etc love to see Indians doing great
Theyre from Indian parents so their descent is indian but their nationality is ig american so i don’t really think we should address them as indians
@@xPhilosophyy i know that they are American citizen
just because someone looks Indian with indian names, does not mean that person is actually an Indian
I need this kind of videos more ...
the power of 2 soln is brian kernighan algorithm , just fyi
Did anyone tell you that your style of talking is like ranveer singh... A
Can I know which programming language are they using?
10:55 he has a kalawa on his wrist! Indian origin
Can't you tell by the face?
I have seen that purple t-shirt guy with glasses in one of your other video
Question: im bad at math but i want walk in technology path, should i learn math first or codding(Frontend) but i havent decide what i want to focus with is it website or the other.
I suggest sticking to your passion, if you love technology then pursue that, allow everything else to follow suit. I shall give you an example, a strategy game like Yu-Gi-Oh requires a lot of reading, however reading is not a necessity, if one has a passion in Yu-Gi-Oh, they simply need to play the game, memorising the cards they need to know, eventually memorising what words relate to what meaning, after decades of playing Yu-Gi-Oh, do you not think he would have grasped basic reading, enough to play Yu-Gi-Oh effectively? Analogous to you grasping maths, enough to be effective in the path of tech
Easy question 🇮🇳
Why i am feeling so dumb
Your better off building solutions to problems instead of leet code.
Software Engineer-II advice to Indian CS students: th-cam.com/video/YDUtUSnwbvI/w-d-xo.html
Lagta hai bhai ko bhi startup karne ka hai.
Please visit LAC too
In my college out of 100 almost 99 can't solve these problems. Here almost every one have knowledge
Jalwa hai .
harnoor? please tell me,, are you on your OPT right now or what? in what status are you there right now? you had got F1 again in dropbox from delhi,, so you are doing masters?
good job , keep it up.
CS or SE?? now adays
This is good content bro but please post the selected question or any question to solve for the viewers ✌
Got it 43 seconds
First comment
From banglore
bhai jan. Full stack web developer kha be scope ha canada ma
plz reply
4:44 this guy looks so much like my crush damn
sir it's good to go
Wait! Harnoor actually Rick Rolled us! That's why I have trust issues...
thanks for everything!
They are telling their places where their boy's hostels are
Non Indians wouldn't know about IIT -- some are just being polite and picking IIT as the host is Indian.
no , they're picking IIT coz they wouldn't wanna deal with MIT's question. I would do the same if i was in their place.
why not popcount(x)==1 to find pow of two.
imagine how selectvie stanford would be if it was in washington
Mit: if(log2(x) - round(llog2(x))==0): return True
wrong
First
Bhai isse software kaise banta hai 😭😭😭
please share the result such as valid answers of all questions at the end
i like your content Harnoor. Keep visiting the college
shouldnt N & (N-1) be O(log2N) and not O(1)
Everybody is scared of MIT question 😅
BTW all these solutions are actually correct... The full adder circuit is itself O(number of bits) so subtracting 1 takes O(number of bits which is same as number of digits)
mm not really , it's more efficient because it's a native thing for the processor.
@@ziedbrahmi4812 but it is still under the assumption that number fits in the circuits
Ayender is genius!!!!
Is our collage IIT such difficult?😂
where can I get those IIT exams pdf am studying computer science.
from students at iit