use google or watch my 8.02 lectures A moving charge produces a magnetic field because when an electric charge is in motion, it creates a disturbance in the surrounding space, which manifests as a magnetic field; essentially, the movement of the charge generates a current, and a current-carrying wire is known to produce a magnetic field around it.
Thanks for the forecast! Could you help me with something unrelated: I have a SafePal wallet with USDT, and I have the seed phrase. (alarm fetch churn bridge exercise tape speak race clerk couch crater letter). What's the best way to send them to Binance?
Sir, Pr Walter Lewin. Hello and delighted, dear Professor. I would like to kindly ask you a question about the physics of the fall of the human body and the hypothesis of its renewal: Imagine that an individual falls standing from his own height, without gaining momentum or acceleration. We might think it will fall at a constant rate. However, instead of impacting a solid surface, he slipped and managed to straighten his posture back to his original position. But the surface remains slippery, leading to another fall. So what is happening in physics? It is certain that gravitational potential energy is transformed into kinetic energy during the fall. However, the movement continues with acceleration, leading to another fall. The question then arises: does the acceleration due to sliding add up to the gravitational potential energy of the following fall? To answer this, it would be interesting to explore whether the system can retain some of the mechanical energy of sliding, thus allowing an increase in speed during the next fall. This analysis could offer insights into the interplay between gravity, motion and friction, thereby enriching our understanding of the dynamics at play. I am interested in your theoretical expertise opinion, I would like to illustrate the experience of a performance, thank you for your kind support, here is the LinkedIn video link. Cordialy.DreamJacques lnkd.in/d7n_BdbJ
*Imagine that an individual falls standing from his own height, without gaining momentum or acceleration.* that is not possible. The simple fact of falling implies that momentum increases. Ask your school teacher. This is my last msg.
sir we want you to make a video on how to create your own works like a physicist like how to become a physicist many of us love it but are not good in working on it
@@lecturesbywalterlewin.they9259 Ah my bad. I forgot that we'll put r=r1 in the expression. My question was stupid. (Sorry, I'm always hasty in everything.)
that would be insane. Place a charge anywhere you want to, the E-field goes down with 1/r^2. Thus the Eield at infinity is zero. The gravitational PE is also ZERO at infinity for obvious reasons. Watch my 8.01 lectures. The Grav PE is therefore negative at any distance from Earth. The PE of a mass m at a distance D=100,000 km from the center of the Earth is -mMG/10^8 (-mMG/r) Joules, here M is the mass of the Earth. I discuss this in great detail in 1 of my 8.01 lectures.
@@lecturesbywalterlewin.they9259 Why insane? The physical work done if you travel from a huuuuge distance to that huuuge distance r plus a small distance delta r would be zero for that small distance, whatever the value of the potential at infinity is. Work = Q*( V(r+delta r) - V(r) ) = 0 if r goes to infinity. I googled it, the consensus is V(r)=0 at infinity indeed, but it's a convention: If V(r) with V(infinity)=0 satisfies E(r)=-grad V(r), so does V'(r)= V(r) + c, c is a constant value. Proof: grad(c)=0. I see why V(r) = 0 at infinity is a reasonable convention, but why is V(infinity) = c insane or even wrong? The work would still be zero: Work = Q*( V(r+delta r) + c- ( V(r) + c) = still 0.
Well, I forgot to go back to the beginning statement that r2 = 2r1, so my solution had the general case of r2 and r1 independent of each other. (AFTER correcting two mistakes in my first try!). Thanks for knocking some rust off my physics calculations!
A moving charge produces a magnetic field because when an electric charge is in motion, it creates a disturbance in the surrounding space, which manifests as a magnetic field; essentially, the movement of the charge generates a current, and a current-carrying wire is known to produce a magnetic field around it.
Sir, which is better for learning physics?? 60% theory 40% problem solving 60% problem solving 40% theory 80% problem solving 20% theory 80% theory 20% problem solving by theory I mean watching lectures, or reading textbooks or learning derivations/formulas
@lecturesbywalterlewin.they9259 IS IT A JOKE ? HONOURABLE SCIENTISTS AND A GREAT TEACHER ,I WANT TO REALLY KNOW ABOUT THAT BECAUSE MY BROTHER ASKED TO ME ,WHEN HE STARTED TRIGO . MY BROTHER IS LEARNING THIS STUFF AT 8 SO ,I ASKED TO MY Favourite TEACHER
Hello sir. I don't know if it's the right place to ask this but still. I am from India currently in class 11th preparing for JEE. I love physics a lot. I am not quite enjoying my preparation except for the physics part. I will however do my best for JEE and after that, I want to pursue further studies in cosmology. Please guide me.
@ im aware sir, but i saw you comment on one of your 8.01 classical mechanics videos that “MIT is a very mediocre university”, i wanted to know in what regard has the mediocrity been analysed
@ i also wanted to know sir, if you’re not too busy that is, what are some books i can purchase for studying calculus in all its details, while having no preceding knowledge?
He means if you eat yogurt , you will get sleepy , so don't sleep in your weekends and work hard extra then also ,and read maths textbook. I really mean it REEEEEAAAAAADDDDDD
Beautiful principle on Gauss Law. Thank you Sir Walter Lewin.
❤ Thank you to Keith's.
Yes im glad you are still here with us ! I just found the physics video with a ball i instantly looked the channel up to check latest vid
قسم بالله انا مش مصدق انت بترد علي اساله. علي الطلب دحنا عندنا في مصر الدكتور لما ما يتكلم كلمه بيطلعه بره شكرا❤❤
I am in 11th class when my school teachers complite any chapter i come your youtube channel to feel 🔥🔥🔥 concept. Watching from india 🇮🇳 .
we also wanted to know how you started your work on physics in your high school days
Make a video on faraday's law and lenz's law
th-cam.com/video/nGQbA2jwkWI/w-d-xo.html
You are the best teaches from which I have learned Physics
use google or watch my 8.02 lectures A moving charge produces a magnetic field because when an electric charge is in motion, it creates a disturbance in the surrounding space, which manifests as a magnetic field; essentially, the movement of the charge generates a current, and a current-carrying wire is known to produce a magnetic field around it.
Thanks for the forecast! Could you help me with something unrelated: I have a SafePal wallet with USDT, and I have the seed phrase. (alarm fetch churn bridge exercise tape speak race clerk couch crater letter). What's the best way to send them to Binance?
So great Sir!!
Sir, Pr Walter Lewin.
Hello and delighted, dear Professor. I would like to kindly ask you a question about the physics of the fall of the human body and the hypothesis of its renewal: Imagine that an individual falls standing from his own height, without gaining momentum or acceleration. We might think it will fall at a constant rate. However, instead of impacting a solid surface, he slipped and managed to straighten his posture back to his original position. But the surface remains slippery, leading to another fall. So what is happening in physics? It is certain that gravitational potential energy is transformed into kinetic energy during the fall. However, the movement continues with acceleration, leading to another fall. The question then arises: does the acceleration due to sliding add up to the gravitational potential energy of the following fall? To answer this, it would be interesting to explore whether the system can retain some of the mechanical energy of sliding, thus allowing an increase in speed during the next fall. This analysis could offer insights into the interplay between gravity, motion and friction, thereby enriching our understanding of the dynamics at play. I am interested in your theoretical expertise opinion, I would like to illustrate the experience of a performance, thank you for your kind support, here is the LinkedIn video link. Cordialy.DreamJacques
lnkd.in/d7n_BdbJ
*Imagine that an individual falls standing from his own height, without gaining momentum or acceleration.* that is not possible. The simple fact of falling implies that momentum increases. Ask your school teacher. This is my last msg.
sir we want you to make a video on how to create your own works like a physicist like how to become a physicist many of us love it but are not good in working on it
I was thinking my answer was too complicated to be correct, but anyways. Although I have one thing to ask. In the solution, for the potential at r1
the electric potential is the same everywhere in the conductor.
@@lecturesbywalterlewin.they9259 Ah my bad. I forgot that we'll put r=r1 in the expression. My question was stupid. (Sorry, I'm always hasty in everything.)
what happened to MIT and Harvard
Especially MIT course 18 and president sally
It seems MIT and harvard predict everything and prepared for everything
Is it possible to assign the potential V at r=infinity a real value other than zero in SI units?
that would be insane. Place a charge anywhere you want to, the E-field goes down with 1/r^2. Thus the Eield at infinity is zero. The gravitational PE is also ZERO at infinity for obvious reasons. Watch my 8.01 lectures. The Grav PE is therefore negative at any distance from Earth. The PE of a mass m at a distance D=100,000 km from the center of the Earth is -mMG/10^8 (-mMG/r) Joules, here M is the mass of the Earth. I discuss this in great detail in 1 of my 8.01 lectures.
@@lecturesbywalterlewin.they9259
Why insane? The physical work done if you travel from a huuuuge distance to that huuuge distance r plus a small distance delta r would be zero for that small distance, whatever the value of the potential at infinity is.
Work = Q*( V(r+delta r) - V(r) ) = 0 if r goes to infinity.
I googled it, the consensus is V(r)=0 at infinity indeed, but it's a convention: If V(r) with V(infinity)=0 satisfies E(r)=-grad V(r), so does V'(r)= V(r) + c, c is a constant value. Proof: grad(c)=0.
I see why V(r) = 0 at infinity is a reasonable convention, but why is V(infinity) = c insane or even wrong? The work would still be zero: Work = Q*( V(r+delta r) + c- ( V(r) + c) = still 0.
Well, I forgot to go back to the beginning statement that r2 = 2r1, so my solution had the general case of r2 and r1 independent of each other. (AFTER correcting two mistakes in my first try!). Thanks for knocking some rust off my physics calculations!
Sir do you have a free youtube course on astronomy, Lectures by you on astronomy??
The Early Universe by Prof Alan Guth is on my channel. In addition there is a playlist "astronomy and astrophysics" with many lecures.
Sir, I am jee aspairent , I love to watch your videos,
Sir, I just wanted to know how does a moving charge create a magnetic field?
A moving charge produces a magnetic field because when an electric charge is in motion, it creates a disturbance in the surrounding space, which manifests as a magnetic field; essentially, the movement of the charge generates a current, and a current-carrying wire is known to produce a magnetic field around it.
@@lecturesbywalterlewin.they9259 but exactly how?? what is magnetic force in depth??
Thank you for 10.0X lecture sir ..love from india
You're welcome! Keep up the hard work.
Hi sir , sir I'm a student from India preparing for JEE exams and I am facing some trouble in solving numericals of physics please help sir
eat yogurt every day but *never on Fridays* that also worked for Einstein and for me
@@lecturesbywalterlewin.they9259😂😂😂
@@lecturesbywalterlewin.they9259 haha, sir your classic dialogue I have seen this comment on every videos of your
😅@@lecturesbywalterlewin.they9259
Sir from wich book or module you are doing this question
Sir, which is better for learning physics??
60% theory 40% problem solving
60% problem solving 40% theory
80% problem solving 20% theory
80% theory 20% problem solving
by theory I mean watching lectures, or reading textbooks or learning derivations/formulas
You must learn the theory and do the problem solving. The two go hand-in-hand!
I think we should do 100% theory and 100% problem solving
Hello sir at what age u learnt to solve trigonometry?❤
I was about 4 years old
@lecturesbywalterlewin.they9259 IS IT A JOKE ?
HONOURABLE SCIENTISTS AND A GREAT TEACHER ,I WANT TO REALLY KNOW ABOUT THAT BECAUSE MY BROTHER ASKED TO ME ,WHEN HE STARTED TRIGO .
MY BROTHER IS LEARNING THIS STUFF AT 8 SO ,I ASKED TO MY Favourite TEACHER
i don't deserve you and Gil. MIT all life waiting and missing.
What should I do to make things right
eat yogurt every day but *never on Fridays*
Thanks Sir
You're welcome!
How many years you old now sir ?
I am stone age
Very funny😂😂.@@lecturesbywalterlewin.they9259
Love ❤❤❤
Hello sir. I don't know if it's the right place to ask this but still.
I am from India currently in class 11th preparing for JEE. I love physics a lot. I am not quite enjoying my preparation except for the physics part. I will however do my best for JEE and after that, I want to pursue further studies in cosmology. Please guide me.
Use Google to learn about cosmology and watch some of my lectures in playlist "astronomy and astrophysics"
Are iits better than mit?
MIT ranks among the top 8 Universities in the world - IITs rank below 200.
@ im aware sir, but i saw you comment on one of your 8.01 classical mechanics videos that “MIT is a very mediocre university”, i wanted to know in what regard has the mediocrity been analysed
@@rajeshbhardwaj6887 that was a joke
@ good lord my brain’s forsaken humour amidst the horrors of newtonian mechanics 😂
@ i also wanted to know sir, if you’re not too busy that is, what are some books i can purchase for studying calculus in all its details, while having no preceding knowledge?
Hello sir❤❤❤
Hard to conceptualize
Sir Im a class 10 student from indian i cant solve maths please help me
eat yogurt every day but *never on Fridays.* That also worked for Einstein and for me.
@lecturesbywalterlewin.they9259 sir please suggest me
He means if you eat yogurt , you will get sleepy , so don't sleep in your weekends and work hard extra then also ,and read maths textbook.
I really mean it
REEEEEAAAAAADDDDDD
22.58