Good presentation. There may be an issue with the very last statement in the video. The superposition of the the three modes. I am assuming u(t) is the vector (u1(t), u2(t), u3(t))
Thank you sir, good experssion. At 31:00 how 0.497 remained same and 0.0108 turn into 0.00339 when we multiplied it by Fi. Isn't Fi(1) a 3x1 mode shape {1 0.686 0.314} and Fi(3) is another mode shape {0.314 -0.686 1}? Please can you explain it for me?
Good presentation. There may be an issue with the very last statement in the video. The superposition of the the three modes. I am assuming u(t) is the vector (u1(t), u2(t), u3(t))
22:45 how did you get that as your k matrix?
If we think about it in terms of k1, k2, and k3, then we have: [k1 -k1 0; -k1 k1+k2 -k2; 0 -k2 k2+k3]. Hope that helps.
@@amiraliCEE That does, thank you so much
Thank you sir, good experssion. At 31:00 how 0.497 remained same and 0.0108 turn into 0.00339 when we multiplied it by Fi. Isn't Fi(1) a 3x1 mode shape {1 0.686 0.314} and Fi(3) is another mode shape {0.314 -0.686 1}? Please can you explain it for me?
The 0.497 is multiplied by 1. And the 0.0108 is multiplied by 0.314 to get 0.00339.