should the splitting of the proton be triplate as per your structure instead of the singlet? please confirm. Your explaination actually really helps in understanding the 1H NMR. Thank you.
Thanks for the video, however, for the proton highlighted in blue, isn't it having no neighbors because it's a singlet other than the reason you gave? this is for the final example
In the C9H10O example, the second CH2 (connected to the Aldehyde) only has 3 peaks indicating two neighbors. Why isn't the H attached to the carbonyl carbon also considered its neighbor? Wouldn't it have 3 neighbors? 2 from the other CH2 and 1 from the Aldehyde?
For the first one, what about the functionality range of 3-4 for a C-H bond connected to a O. It accounts for one of the two peaks at 3ppm, but doesn't account for the other one. Shouldn't one of the peaks be located at 0-1ppm because the first C-H2 bond of the benzene ring is not connected to a oxygen.
For the last problem, even though, according to the IHD, it says there is no ring or double bonds, why is there a peak between 1.5 and 2.5 meaning there is a double bond carbon?
Can someone please explain me how can I determine the number of H atoms per peak? In the 1st and 2nd video he determines it with the chemical shift and some sort of integration (?!) but it's confusing to me. Is there any way of knowing the number of H atoms on every peak without these integrations (don't even know if I got that part right :( ) Otherwise, videos are supercool! Whenever I have something that confuses me I search on your channel, thank you a dozen
Either, the number of protons will be given to you, or in some cases, the area under the integration will be given as was the case in video 1 and video 2, and then you divide that by the smallest peak. In other cases, there will be a line given to you that indicates the area under the integration. when that curly kind of line is given, you measure the height with your ruler, and then divide everything by the smallest number you get. Hope it helps!
although my exam is way more complicated than these , I learned a LOT. Thank you!
These are way too easy compared to the ones on my college exam. :(
the best tutorials that I've ever watched
my instructor BUTCHERED this topic--absolute gibberish--but you guys made it all ok!! thanks so much.
Thanks so much!!! exam on Tuesday. hope I can do it well:)
SAME HERE
You teach ways is very good to learning NMR , thank you.
The best ...
should the splitting of the proton be triplate as per your structure instead of the singlet? please confirm. Your explaination actually really helps in understanding the 1H NMR. Thank you.
Million Thanks, You are amazing!
you made my life easier with NMR
My first comment on TH-cam.This work is amazing!
It is the best lecture I’ve ever seen thank you very much
Thanks for the video, however, for the proton highlighted in blue, isn't it having no neighbors because it's a singlet other than the reason you gave? this is for the final example
Hi, please teach 2D NMR analysis.thank you so much
thanku so much it was the way worth it!!!!!!!
Thx a lot...it's useful, however, if the NMR spectroscopy isn't pure enough, the situation will be more complex than what u taught us..
Bro do the same for mass spectroscopy
Thank you so much!!!!
THANKS YOU somuchhh !!! It's very useful for me to study about H-NMR.From Viet Nam
thanks a lot ^_^
these video make me understand NMR
Very helpful
Thank you very much
thank you for the explanation
Thanks!
You love those neighbors.
thank you! good job! (y)
In the C9H10O example, the second CH2 (connected to the Aldehyde) only has 3 peaks indicating two neighbors. Why isn't the H attached to the carbonyl carbon also considered its neighbor? Wouldn't it have 3 neighbors? 2 from the other CH2 and 1 from the Aldehyde?
For the first one, what about the functionality range of 3-4 for a C-H bond connected to a O. It accounts for one of the two peaks at 3ppm, but doesn't account for the other one. Shouldn't one of the peaks be located at 0-1ppm because the first C-H2 bond of the benzene ring is not connected to a oxygen.
thank u
Very good
thank u bro
For the last problem, even though, according to the IHD, it says there is no ring or double bonds, why is there a peak between 1.5 and 2.5 meaning there is a double bond carbon?
how do u find that the carbon is bonded to an electronegative atom by using the chemical shift
Bruh thanks a lot
but the number of problem is not given in our course book... how do we knw that it has this certain number of protons??
Can someone please explain me how can I determine the number of H atoms per peak? In the 1st and 2nd video he determines it with the chemical shift and some sort of integration (?!) but it's confusing to me. Is there any way of knowing the number of H atoms on every peak without these integrations (don't even know if I got that part right :( )
Otherwise, videos are supercool! Whenever I have something that confuses me I search on your channel, thank you a dozen
Either, the number of protons will be given to you, or in some cases, the area under the integration will be given as was the case in video 1 and video 2, and then you divide that by the smallest peak. In other cases, there will be a line given to you that indicates the area under the integration. when that curly kind of line is given, you measure the height with your ruler, and then divide everything by the smallest number you get. Hope it helps!
Being For thank you so so much! I wasn't sure if I can measure it with the ruler and get the right ratio. thanks a lot :)
quick question
why is OH absorption so broad?
thank you
Is it in IR spectroscopy
How to calculate HOI
HDI = 5 but have only 4 pi ?????
rings