wow i dont know why but you always explain lessons very clearly. Ive been confused with these lesson for months now. I wish you're my strength of materials professor
Been watching these videos since basic mechanics. Coming back after 4 years and hearing you say extensometer was a refresher LOL. Keep it simple and keep up the great work man! Good luck
THANK YOU !!!!!!!!!! THANK YOU!!!! seriously you should teach the teachers, I appreciate you and all that you do!!! Like really please keep doing this, so many people need you!!!!!!
Ohhh that is what i need an energetic explanations rather than boring slow-motion low volume Smashed like just after the energetic intro and subscribed after the informatic video
I just came across your videos. Seriously, I never had a lecturer who teaches like you do. It was so easy to grasp the concept. And you definitely made the learning process fun especially with your great enthusiasm and good sense of humor. The shoe joke "ohhhh yeah very flexible .." was hillarioussss. Just subscribed to your channel. Really appreciate your effort in making the video.
An explanation of the significance of mechanical properties in engineering design and identifying significant characteristics for a typical stress strain curve.
5cr3am1ng3agl3 okey! i am not a pro here! just saw ur comment ! so trying to help! Strength is the ability to withstand load without failure. say higher the strength, higher is the ultimate stress point. Hardness is the resistance to scratch or cutting or abrasion or penetration, Stiffness is the ability to resist deformation under load. say an Al bar sags when load is hung at its one end but a steel bar doesn't for the same load. Toughness is the the ability to withstand both plastic and elastic deformation before fracture. u can term it as the amount of energy a material can absorb before failure. Ductility is the ability to withstand basically tensile load without fracture, better understand it as the ability of a material to be turned into a wire, Hope it helped! Cheers! :)
May Almighty God reward you for your biggest help for all students. I wish I were your student. The way you teach is so understandable and clear that even a high school student can grasp. I wish I could rated this video as liked for more than million times. Those who disliked your videos might be either very jealous or very dumb ppl Lol!
+786Hosai thank you for the encouragement and the kind words. It makes working on the videos worthwhile and it makes it easy to focus on the positives....Ballas gonna ball, haters gonna hate...
hi there, thank you for your time in making the video. It is clear and direct to the point about mechanical properties. energy in the voiceover makes it engaging! would like to point out on the sound quality as it is very sharp... a little difficult to listen to. i can advise using a software to tweak the eq. that would provide overall nicer sound quality!
that was really good brief description, but it would better without making unnecessary word . i wish from you next video think about the viewers who are not native english speaking people. like me. appreciate you for your good description.
It would really help if you could do a video where you solve a problem about this! For example: For a 0.031 in diameter wire that breaks with a fracture stress of 36000 psi and reaches a percent reduction in area (%RA) of 75%. Determine true stress and true strain in the moment of fracture. Thank you so much for this!
I have two questions here Sir! 1. What happens at microscopic level at upper and lower yield points and further more stress is required to produce deformation in strain hardening? 2.After ultimate strength why the curve downgrading up to fracture?
for the second question, answer is because this graph is based on the original area from the beginning, this graph can be called engineering stress-strain diagram. >>there is a True stress-Strain Diagram which is based on the actual area corresponding to force applied where you can see the stress is going up all the way till it fractures. hope that was clear enough mate.
Dope video man! really explained what I was looking for! How would you model stress and strain for materials like wood which I hear have non-linear elasticity? Also, when you're editing your videos it might be good to shoot for the semi-universal -12Db peak volume mark for uploading online to avoid blasting folks, and watch out for your mic's gain being too hot and clipping your voice. :)
Could you do a video on how to find permanent set after a structure is unloaded? I know young's modulus E is involved but I'm not sure after that. Thanks!
I feel like I should understand this given that no one else ever seems to ask this question, but can you please explain why the stress decreases after the yield point and the UTS? Doesnt the machine continue to apply the same force or increasing force? How does this result in decreased stress, especially if the cross sectional area is decreasing in the necking region.
as a quick response...the material weakens and it requires less force to deform it. the stress is decreasing in the necking region since we are using the original area to calculate the engineering stress.
I have a small doubt Sir. In the yeilding zone , it is said in the video that loading is constant and a large deformation in experienced by the specimen. but I the strain controlled tensile test the specimen is loaded from zero to ultimate load,that means load acting on specimen is increasing continuously ,so how a constant load acts in the yielding zone? shouldn't it increase ? or is it like the instant the loading generates the yield stress that huge amount of yielding happens in the yield zone ?
Sir i have a doubt..Hookes law states that stress is proportional to strain within elastic limit..But in actual diagram we see that the line is straight only till the proportional limit and not elastic limit..which also means that slope can be taken only till the proportional limit right?..
Sir please i need your help on my project which is going to be due by the end of this week. here it is. A BARBELL STAND SUPPORTING THE WEIGHT OF A BARBELL AS SHOWN IN FIGURE. CHOOSE A MATERIAL FROM APPENDIX AND DETERMINE THE MISSING DIMENSION FOR SAFETY FACTORS OF 1.5, 3, 3.5 AND 5. CHOOSE A SAFETY FACTOR AND WRITE A PARAGRAPH DETAILING WHY YOU CHOSE THE SIZE STAND THAT YOU DID. THANKS SIR
thank you for this video , I have question . While applying load on materials , the stress must increasing and that we can see in curve , but between proportional limit and yield the stress. Here the question , why the stress decreasing ? I know that is engineering stress sigma=F/Ao , so the only change is load . How become
Jitu M depends on the material and standards that you are using when conducting the test. the 0.2% offset is a popular method that is used to identify yield points.
I tried calculating true stress using the relation between true stress and engineering stress,but i am getting a huge difference between true stress and engineering stres value ......I have used the formula true stress=engineering stress x ln (1+eng strain).....Even you try it calculating, assuming some value of engineering stress and engineering strain.... Please help, may be i have made some silly mistake
I wish my professors were as passionate as you are...
You've just earned yourself another subscriber mate! :D
+BlopMangoHerpDerpLOL wooo hooo!
You are very passionate and energetic .... Usually professor are so boring but you are fabulous ...
In 2020, I am working in Construction Industry and I am still watching it.
From 2012, before my Chemistry exam.
You are really a good teacher.
wow i dont know why but you always explain lessons very clearly. Ive been confused with these lesson for months now. I wish you're my strength of materials professor
Thank you for the kind words! I wish I was my strength of materials professor too. :)
you are amazing.. unbelievably clear and to the point explanations. better than any prof, TA or tutor I've ever had. +1 subscriber !!
man watching you its like watching a person who is playing a ps game!! you make the lessons a fun things to watch .. thnx very much mate .
Been watching these videos since basic mechanics. Coming back after 4 years and hearing you say extensometer was a refresher LOL. Keep it simple and keep up the great work man! Good luck
me and my students really do appreciate your enthusiasm towards physics, thanks for the vid
Going to take my final EM324 EXAM tommorrow. Thanks so much everything was better after watching ur videos :)
THANK YOU !!!!!!!!!! THANK YOU!!!! seriously you should teach the teachers, I appreciate you and all that you do!!! Like really please keep doing this, so many people need you!!!!!!
+Ashlie R You are welcome! I appreciate the words of support and inspiration. Ahhhh snappp, structurefree forever!
Just found this channel, time to prepare for the journey ahead...I was looking for engineering channels just like this! Thank you
wow! u made it look so easy.All of the videos in this material mechanics series are awesome. Thank u sir.god bless u.
No questions it is very clear .thx so much.i wish you were my material teacher :)
holy man ! I find your video again. you already saved me two course. hopefully this is the third one!
Ohhh that is what i need an energetic explanations rather than boring slow-motion low volume
Smashed like just after the energetic intro and subscribed after the informatic video
Thank you for subscribing. I appreciate your support.
I just came across your videos. Seriously, I never had a lecturer who teaches like you do. It was so easy to grasp the concept. And you definitely made the learning process fun especially with your great enthusiasm and good sense of humor. The shoe joke "ohhhh yeah very flexible .." was hillarioussss. Just subscribed to your channel. Really appreciate your effort in making the video.
Thank you for subscribing...I used to dream of being a shoe salesman then the internet happened.
your way of teaching is just superb.....! thankyou sir,
An explanation of the significance of mechanical properties in engineering design and identifying significant characteristics for a typical stress strain curve.
Good video, can you please explain me the difference between Strenght, Hardness, Toughness, Stiffness and Ductility properties of materials ?
5cr3am1ng3agl3 okey! i am not a pro here! just saw ur comment ! so trying to help!
Strength is the ability to withstand load without failure. say higher the strength, higher is the ultimate stress point.
Hardness is the resistance to scratch or cutting or abrasion or penetration,
Stiffness is the ability to resist deformation under load. say an Al bar sags when load is hung at its one end but a steel bar doesn't for the same load.
Toughness is the the ability to withstand both plastic and elastic deformation before fracture. u can term it as the amount of energy a material can absorb before failure.
Ductility is the ability to withstand basically tensile load without fracture, better understand it as the ability of a material to be turned into a wire,
Hope it helped! Cheers! :)
+Neptanol Congrats man you nailed it!
i wish teachers in my engineering college could teach like you!!!! keep up this good work!!
Thank you.
yea me too
love the liveliness in explanation,very lucid.
+MIHAEL TIZA thanks!
this guy made me realize my passion for engineering
If I could give this a million thumbs up I would, fantastic video and great commentary
Man!!! you made this video much easier and understanding. wish you were my professor.And thats awesome :)
Why this dude is not teaching my class of Material Science ? He would be the coolest teacher in my whole University.
Less talking,more action ! thank you for the very nice comment, you are too kind....
May Almighty God reward you for your biggest help for all students. I wish I were your student. The way you teach is so understandable and clear that even a high school student can grasp. I wish I could rated this video as liked for more than million times. Those who disliked your videos might be either very jealous or very dumb ppl Lol!
+786Hosai thank you for the encouragement and the kind words. It makes working on the videos worthwhile and it makes it easy to focus on the positives....Ballas gonna ball, haters gonna hate...
Thank you so much man! I missed my lecture and was lost until I saw your video.
Subbed
hey your teaching style is so cool otherwise most of the time I found boring lectures loves your style.
+Prashant Lalwani Thank you!
this is so good!!!! understood it perfectly, thank you!
Excellent presentation! Thanks for posting it.
hi there, thank you for your time in making the video. It is clear and direct to the point about mechanical properties. energy in the voiceover makes it engaging!
would like to point out on the sound quality as it is very sharp... a little difficult to listen to.
i can advise using a software to tweak the eq. that would provide overall nicer sound quality!
thanku... ur teaching style is awsm
You're so easy going sir, that made it easier. Thanks 💝🤣
rip my ears but you're pretty crazy, love it!
Great videos for exam reviews!
Extremely helpful, keep it up sir!
well explained ,I am very grateful for the work n effort
a great help from this video,synopsis-ed,well explained.Thank you.
Thanks a lot, this video made it easy for me to understand
that was really good brief description, but it would better without making unnecessary word . i wish from you next video think about the viewers who are not native english speaking people. like me. appreciate you for your good description.
Hey such a good video.. even better that how i was explained in university!!
AWESOME. Perfect for my High School PLTW course
the intro tho, haha very passionate. love it!
IMPLY AWESOME ! keep the good work going
It would really help if you could do a video where you solve a problem about this!
For example: For a 0.031 in diameter wire that breaks with a fracture stress of 36000 psi and reaches a percent reduction in area (%RA) of 75%. Determine true stress and true strain in the moment of fracture.
Thank you so much for this!
very good explanation, thanks
Loved the explanation
Video bahut accha tha...Thanks👍
Translation? :)
+structurefree Translation: "The video was good"
And it really was. Thank you!
This is great! Do you have any videos over unloading/loading stress strain curves?
thx for making a matsci lecture not boring. hard to find those now lmaooo
Great and simple video, thank you so much!
Wow this helped me so much!
I love this guy yay to Engineering
Best explanation
Amazing 😍
I have two questions here Sir!
1. What happens at microscopic level at upper and lower yield points and further more stress is required to produce deformation in strain hardening?
2.After ultimate strength why the curve downgrading up to fracture?
+Bibhu Arya the second question is exactly what im looking for, if you found the answer please reply
+Omar Alomoush
sure I'll.
for the second question, answer is because this graph is based on the original area from the beginning, this graph can be called engineering stress-strain diagram.
>>there is a True stress-Strain Diagram which is based on the actual area corresponding to force applied where you can see the stress is going up all the way till it fractures.
hope that was clear enough mate.
Dope video man! really explained what I was looking for! How would you model stress and strain for materials like wood which I hear have non-linear elasticity?
Also, when you're editing your videos it might be good to shoot for the semi-universal -12Db peak volume mark for uploading online to avoid blasting folks, and watch out for your mic's gain being too hot and clipping your voice. :)
Could you do a video on how to find permanent set after a structure is unloaded? I know young's modulus E is involved but I'm not sure after that. Thanks!
Thanks it helped a lot
I feel like I should understand this given that no one else ever seems to ask this question, but can you please explain why the stress decreases after the yield point and the UTS? Doesnt the machine continue to apply the same force or increasing force? How does this result in decreased stress, especially if the cross sectional area is decreasing in the necking region.
as a quick response...the material weakens and it requires less force to deform it. the stress is decreasing in the necking region since we are using the original area to calculate the engineering stress.
this is not true stress strain diagram
at first this seems like a joke... but it gets really good thank you sir.
nice explanation. which pen tablet r u using
Muaxx! So energetic! Tq :)
Sounds like a gamer. Digging the enthusiasm though :)
Player's gonna play.
1:10 My phone has taken plenty of "loads" in its lifetime, thanks Samsung for the durable design ; )
شكرا جزيلا ... جدا مفهوم
Thank man ..but what about if we have force VS strain ..!? Should the calculation of the yiled change ?!
AWESOME! I m paying my school fee in vain.
Good job
really helpful...thnak u :)
I have a small doubt Sir. In the yeilding zone , it is said in the video that loading is constant and a large deformation in experienced by the specimen. but I the strain controlled tensile test the specimen is loaded from zero to ultimate load,that means load acting on specimen is increasing continuously ,so how a constant load acts in the yielding zone? shouldn't it increase ? or is it like the instant the loading generates the yield stress that huge amount of yielding happens in the yield zone ?
i think you made this on ipad right, which stylus you use. can you telll plz
love this guy
LOVED YOUR EXPLANATION AND YOUR BEATBOXES AND YOU GOT ANOTHER SUB
Hi i want to know that if i want to find stress strain which method is easier compression or tension thx :)
there's a separate graph for shear stress and strain right?
Just WOW!!!. Subbed
Thank you!
LEARNING!!!!!!!!!!!!!!!!!
+sirspamsalot2 Awwww djyeah!!
Sir i have a doubt..Hookes law states that stress is proportional to strain within elastic limit..But in actual diagram we see that the line is straight only till the proportional limit and not elastic limit..which also means that slope can be taken only till the proportional limit right?..
Sir please i need your help on my project which is going to be due by the end of this week. here it is. A BARBELL STAND SUPPORTING THE WEIGHT OF A BARBELL AS SHOWN IN FIGURE. CHOOSE A MATERIAL FROM APPENDIX AND DETERMINE THE MISSING DIMENSION FOR SAFETY FACTORS OF 1.5, 3, 3.5 AND 5. CHOOSE A SAFETY FACTOR AND WRITE A PARAGRAPH DETAILING WHY YOU CHOSE THE SIZE STAND THAT YOU DID. THANKS SIR
good work ....nice explanation ....thanx a lot
is the plastic region not from yield strength to fracture?
thank you for this video , I have question . While applying load on materials , the stress must increasing and that we can see in curve , but between proportional limit and yield the stress. Here the question , why the stress decreasing ? I know that is engineering stress sigma=F/Ao , so the only change is load . How become
أيمن العتيبي it's a dip associated with steel...it's kind of like a slight break and then the grains realign.
when you're choosing a shoe: ooh yeass very flexible .. Lmao
If the problem is to take 3% of Strain hardening then how the curve look like ?
I mean, the nature or behavior of curve ?
straight up legend
How do we come to know the exact value of yield stress of a material???
Because it is difficult to find the actual point when the yielding starts???
Jitu M depends on the material and standards that you are using when conducting the test. the 0.2% offset is a popular method that is used to identify yield points.
Dr.Lee? or Dr. Estrada?
O ocoo ox very helpful ,, thank you for the food work
here is another big fan of Breaking Bad..Science Mr.White
after UTS, why the stress is get reduce...?
Subscribed... And tq
Your handwriting is kinda messy and hard to read but other than that, Thank you soooo much! This really helped! God BLESS!
thanks
thank you ....... your are great ^_^
Please, you are too kind!...uh oh ...I'm struggling...getting too heavy...can't rotate or look up...neck hurting...ugh...stuck.
I think the hardening range is to the failure point.
No explanation for lower yield point
good job!
Why stress is called as that manner instead a force as Hook Law?
I tried calculating true stress using the relation between true stress and engineering stress,but i am getting a huge difference between true stress and engineering stres value ......I have used the formula true stress=engineering stress x ln (1+eng strain).....Even you try it calculating, assuming some value of engineering stress and engineering strain....
Please help, may be i have made some silly mistake
Thank u sir