4.1 Dead Load [DL] & Super-Imposed Dead Load [SIDL] Manual Calculations as per IS 875 (Part-1): 1987
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- เผยแพร่เมื่อ 6 ก.ย. 2024
- Lecture: 4.1 Dead Load [DL] and Super Imposed Dead Load [SIDL] Calculations as per IS 875 (Part-1): 1987
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[Load Calculations and Considerations as per IS 875 and 1893 Part-1 2016] drive.google.c...
[Free] Course: Complete Design of G+3 Storey RCC Building as per IS Codes by ETABS
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Course Description: In this course, you will learn how to plan structure with respect to architectural planning and as per codal provisions of Indian Standard codes then you will learn how to use IS Codes to calculate the loads on the structure and modelling and analysis of building structure in computer software ETABS, and most importantly you will go through the design procedure of each type of structural element manually as well as with the help of MS Excel Sheets and at last how to detail your structural sections and preparation of drawings for Construction-Site Execution purpose.
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_If you complete the course, then I'd be happy If you give me the feedback of this course by just filling this google form_ _forms.gle/Q7gUW4untqbBszfs8_
I appreciate your work .. And the way of your Explanation on Each things in detail and Clear way keep it up Sir
Thank You... Happy Learning!
really appreciate for ur hard work thanks god bless u
Sujan, Thanks for the Feedback ...
Appreciate your hard work sir
thanks...
EXCELLENT EXPLANATION...........
Thanks ....
@@AkshayThakur really good......keep going ......really helpful information.....thank you......heartful thanks...... tomorrow onwards.....I will start this course......if I have any doubts......I will ask you......once again Thank you...!!!
Thank you for the excellent lessons
welcome dear!
For the unit weight of floor finish how is 23.5 calculated . From is code floor finish clay floor tiles unit wt is 0.1 to 0.2 pliz explain
IS code gives is for tiles is for kn/m2
here in formula we have to put value in kn/m3
as this i have taken referance with NPTEL Course by Prof. Dhang of IIT-KGP
do check out his lecture of staircase design you'll sort out of this doubt
Keep on bro....
Superb explanation, love to watch the video.
Really glad😁😁
Happy Learning!
Sir,there is small doubt in calculating super dead load . Can u explain how 50mm thick mortar is 1.05 kn/m2 ?if 10mm is 0.21. ? Actually 50*.21=10.5
for 10 mm it is 0.21 kN/m2 right
so for 50 mm
it is 10×5=50 :: 0.21×5=1.05
hence for 50 mm it is 1.05 kN/m2
sir please can you tell me from where you have taken the values for density of floor finish as 23.5 KN/cum and density of water proofing course as 22 KN/cum?
it depends on what materials you are using.. I have just use values which are approximate for standard materials...
Water proofing is 125 mm so you should take 0.125 why you have 0.0125 can you plz explain
it was only writing mistake, if you see considered value is 2.75 kN/m2 which is 0.125×22=2.75 kN/m2
@@AkshayThakur ok sir
I think there is some kind of confusion with waterproofing thickness and its load calculation. the thickness of waterproofing is 0.125 m but you took it as 0.0125 m.
Yes, In the report by mistake it is 0.0125 but Calculation is correct i.e, 0.125*22=2.75 kN/m^2
It was a writing mistake but there is also note to that, 125 mm Thickness for Waterproofing
@@AkshayThakur Thank you😃
In waterproofing course you are calculating mass of waterproofing course which you have written as load intensity ri8 ??? If that is the case we know density =mass/volume, we have the density ,but how have you taken the depth of waterproofing as volume ??? I don't get it ,mass = density × volume but instead you multiplied density with depth ,can you explain this ??
sorry, it was writing mistake... so i mistakenly tell that it is density...
• 22 kN/m3 is not density it is unit weight of waterproofing course
• 125 mm = 0.125m
so, 0.125×22 = 2.75 kN/m3
● by-the-way, calcution is right in the load calculation report
GREAT JOB SIR THANK U
Welcome ...
Could you please explain, how ceiling plaster is calculated ?
I consider average standard wt. for unit wt. of 10mm plaster which is 0.21 kN/m2 and then for 6mm Ceiling Plaster Wt.
0.21 × 0.6 gives ceiling plaster wt./m2
@@AkshayThakur 0.6 ?
@@tanzinwangchu9888 0.21 is for 10mm thick plaster and so for 6mm plaster it is need to multiply with 0.6
Sir how u find the formula of dead load of stair is it mentions in is code ?
its not formula by IS code... this formula is followed by Prof. of IIT-KGP who taught that in their NPTEL course... DRCS
Thanks so we follow this formula for design of stairs too
I suggest firstly if possible go through that as well... it was a very nice course which clears basics for Design of Structural Members.... NPTEL Course: Design of Concrete Structure: IIT-KGP by Prof. Dhang Sir...
how come tread length come out to be 0.29111
watch the video 3.1 in which all the calculations for stairs are made.... & my suggestion is, do watch videos in-a-line from start to end through playlist so that you will won't miss anything....
Very nice
thank you dear...
Hello sir
Sir i wanted to ask we don't use factor of safety for loads in etabs as we add factor of safety manual
you have to enter working loads while assiging them in ETABS.... not factored loads,
by the way whatever factor for load you want, that you can do it by load combination....
but do apply loads as working loads while using ETABS so you can check the structure for serviceability criteria within same model....
for Factor of Safety for Materials you have option to change them under view/revise preferences under design ribbon
Hello sir
How you got the unit weight of waterproofing that is 22kn/M3,?
i take the rought value...
Thank you for the reply sir
Actually I didn't get in 875 book sir
I like the way of your teaching it's excellent..if possible please do on slab also sir
initially 2 videos as like for other members are uploaded but there was one mistake in it so i delete those videos...
see for any matetials, if you can't find the value in code then refer other international code or just google the value for required material from some websites take the rough value and use that one....
Sir load combination explain me manual and automatic what difference?
Sir confuse for load combination how to make own load combination?
And automatic both?
See, Auto Design Load Combinations are only Design Load Combinations as per selected Design Code for Load Patterns you Define...
Where in Manual here, see I define Design as well as Serviceability Load Combinations in which we can specifically used Serviceability Load Combinations for Analysis Checks and Design Load Combinations to Strength of Structural Members...
In ETABS for Indian Standards there are no pre-auto define option for serviceability load combinations so in the course I manually define load combinations as per Indian Standard codal provisions...
But sir how to make load combination in manually? I see code 456:2000 but confused for load combination?
@@juhilsuthar3035 see the table, follow rows and columns, read the bottom notes of the table...
👍🏼👍🏼👍🏼
thanks....