copy pasting my answer from another comment. It is a concept called similar triangles. BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D) BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point) we know that angle B is common to both of the triangles. by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar. It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
Given: In △ABC,D and E are midpoints of AB and AC respectively, i.e., AD=DB and AE=EC To Prove: DE∥BC Proof: Since, AD=DB ∴ DB AD =1............(1) Also, AE=EC ∴ EC AE =1............(2) From (1) and (2), DB AD = EC AE =1 i.e., DB AD = EC AE
∴ By converse of Basic Proportionality theorem, DE∥BC
It is a concept called similar triangles. BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D) BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point) we know that angle B is common to both of the triangles. by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar. It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
Sir, I have doubt in question number 3, actually pythogorous formula is AC² = AB²+BC² but in 3rd quetion you have used AC²= AB²-BC².So Can you please explain why to use that formula.
It is a concept called similar triangles. BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D) BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point) we know that angle B is common to both of the triangles. by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar. It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
Given: In △ABC,D and E are midpoints of AB and AC respectively, i.e., AD=DB and AE=EC To Prove: DE∥BC Proof: Since, AD=DB ∴ DB AD =1............(1) Also, AE=EC ∴ EC AE =1............(2) From (1) and (2), DB AD = EC AE =1 i.e., DB AD = EC AE
∴ By converse of Basic Proportionality theorem, DE∥BC
It is a concept called similar triangles. BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D) BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point) we know that angle B is common to both of the triangles. by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar. It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
It is a concept called similar triangles. BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D) BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point) we know that angle B is common to both of the triangles. by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar. It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
In last question how AE=2(OD) sir can you explain......
BD/DE=BO/OA.
That means D and O are mid points of BE and BA.
Then there is a theorem in class 10th(triangles) that proves that AE=2(OD)
@@Gaurav_9339 , Good bro
copy pasting my answer from another comment.
It is a concept called similar triangles.
BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D)
BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point)
we know that angle B is common to both of the triangles.
by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar.
It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD
similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
Last problem was superb sir ....👍👍👍👍❤️
I’m glad you like it madam, thank you.
Thank you so much sir ❤
i have doubt on 5 question how is AE value you took as double of OD value i want answer from u sir
Given: In △ABC,D and E are midpoints of AB and AC respectively,
i.e., AD=DB and AE=EC
To Prove: DE∥BC
Proof:
Since, AD=DB
∴
DB
AD
=1............(1)
Also,
AE=EC
∴
EC
AE
=1............(2)
From (1) and (2),
DB
AD
=
EC
AE
=1
i.e.,
DB
AD
=
EC
AE
∴ By converse of Basic Proportionality theorem,
DE∥BC
It is a concept called similar triangles.
BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D)
BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point)
we know that angle B is common to both of the triangles.
by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar.
It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD
similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
Thank you so much sir u are the best teacher
Sir in the last sun,how can you take AE as 16 cm?pls clear the doubt
Same question bro?? How??
Tqq so much for ur classes sirrrrr🙏
You’re most welcome sir.
Please do more video in base of coordinate geometry
May God bless you with happy married life.
I am more than just grateful for your blessings and well wishes sir.
@@FeelFreetoLearn happy married life Annan♥️♥️♥️
sir.....you are looking like chiranjeevi ( Telugu Movie megastar )
😂
The main target informing a triangle
Sir, I have doubt in question number 3, actually pythogorous formula is AC² = AB²+BC² but in 3rd quetion you have used AC²= AB²-BC².So Can you please explain why to use that formula.
Look at angle D, that is 90° so the line opposite to 90°(perpendicular) is the hypotenuse so 13 OB is the hypotenuse
^-^
sir
How. U wrote AE=16
Sir do Geometry triangles videos
Thank you sir.
You’re most welcome sir.
I did👍
how you know AE is perpendicular to EB?
It is a concept called similar triangles.
BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D)
BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point)
we know that angle B is common to both of the triangles.
by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar.
It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD
similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
Sir please make meansuration sir
in the last qus why OD = 1/2 AE? plz sir i need the explanation.
Given: In △ABC,D and E are midpoints of AB and AC respectively,
i.e., AD=DB and AE=EC
To Prove: DE∥BC
Proof:
Since, AD=DB
∴
DB
AD
=1............(1)
Also,
AE=EC
∴
EC
AE
=1............(2)
From (1) and (2),
DB
AD
=
EC
AE
=1
i.e.,
DB
AD
=
EC
AE
∴ By converse of Basic Proportionality theorem,
DE∥BC
It is a concept called similar triangles.
BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D)
BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point)
we know that angle B is common to both of the triangles.
by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar.
It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD
similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
in the last question how did ED became root 10 cm
I could not find the tangent vedios
Sir in 4 th question OD is 8 cm is given in question.. How we double in AE is 16 cm.. Could you expalin plz?
Same doubt
Teaching is good sir daily live ki randi sir👌👌🤝
Hi sir
26.33 min, AE 16 cm how is that.. What is that rule
Anyone knows means pls..
Plz explain how did u confirmed like a double the OD
Mid point theorm....
Concept of similar triangle
It is a concept called similar triangles.
BE is a chord being bisected by OD. so, we know that BE = 2 * BD (as BE is split into two equal parts at D)
BA is a chord being bisected at O. so, we know that BA = 2 * BO (as BA is the diameter and O is the center point)
we know that angle B is common to both of the triangles.
by laws of similar triangles Side Angle Side (two sides are proportional and the angle is same between both sides), we can say that both triangles are similar.
It means that the other angles must be equal (hence angle AEB is right angle as it matches angle ODB) and the remaining side AE must be proportional. AE = 2 * OD
similar triangles are based on rules like AAA (all matching angles equal in both triangles), SAS (two sides proportional to matching sides of other triangle and the matching angle between them should be equal), SSS (all sides must be proportional), ASA (two matching angles being equal and the side between them should be proportional). high school math.
How AE became 16 directly?