EE213 - 15 - Commutation in a simple four loop DC machine

[@ratuldas2295]

Why do we get 2e for a very short period of time?
All in all very detailed and accurate video on the topic which is very rare. Thank you

[@MAFarooqi]

There is a brief time during which only two conductors (out of 4) are under pole faces. During this time voltage is 2e.

[@tabinzargar]

Thanks a lot sir, finally I understood the process of commutation (as explained in Chapman).
Love from Kashmir.

[@MAFarooqi]

You are most welcome

[@atpTUBE]

17:43 why polarities are from - to + , it goes over it, shouldn't it be from + to - from high potential to low sir?

[@MAFarooqi]

Voltages are induced in the coils, making them function as voltage sources, and in a voltage source, the direction of current is from - to +

[@atpTUBE]

@@MAFarooqi Yes sir I got it thanks a lot...

[@paaploo6400]

The best explanation ever sir. I am from Sukkur IBA university and thanks to you that this topic is clear to me as it really irritated me a lot.

[@MAFarooqi]

Thanks.

[@renangonzaga4265]

awesome explanation, thanks very much.
The only part that wasn't clear for me was at the point 22:11 concerning the different paths of the voltage induced in the total voltage. In your explanation you chose the path 2'-2-1'-1, my question is: could it be 2'-2 only? Meaning that the induced voltage goes from the part c of the commutator to the part b of it.

[@MAFarooqi]

Thanks for linking.
You are right, you can also move from one brush to the other by moving through the path segment_c - coils 2'-2 - segment_b. Again, you see that the total voltage between the two brushes is 2e.

[@renangonzaga4265]

@@MAFarooqi Ok. Thank you for your great work!

[@Abbas-BaşMühendis]

Thank you sir !

[@mohammadrakibulislamrakib3891]

Masha-Allah.... Jazakallahu khair....

[@MAFarooqi]

Thanks.

[@peersyedsalmanhassan1468]

Nice explanation Sir.

[@MAFarooqi]

Thanks.

[@waseemirfan6349]

found this video Fruitful