Michael Thomas Rex F
Michael Thomas Rex F
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Shear Force and Bending Moment Diagram of Cantilever Beam with Point load and UDL |Example Problem
Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA
This video lecture explain
1. What is shear force?
2. What is bending moment?
3. How to draw shear force and bending moment diagrams for cantilever beam subjected to point loads and UDL?
4. How to determine sign convention of shear force and bending moment?
Problem description:
A cantilever of 14 m span carries loads of 6 kN, 4 kN, 6kN and 4 kN at 2 m, 4 m, 7 m, and 14 m respectively from the fixed end. It also has a uniformly distributed load of 2 kN/m run for the length between 4 m and 10 m from the fixed end. Draw the shear force and bending moment diagrams.
มุมมอง: 841

วีดีโอ

Shear Force and Bending Moment Diagram of Cantilever Beam with Point loads | Example Problem
มุมมอง 6565 หลายเดือนก่อน
Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains: 1. What is shear force? 2. What is bending moment? 3. How to draw shear force and bending moment diagrams for cantilever beam subjected to point loads? 4. How to determine sign convention of shear force and bending moment? Problem Description: A cantilever of 10 m span carries loads ...
Engineering Mechanics | How to find Centroid of Irregular Shape |Tutorial
มุมมอง 2Kปีที่แล้ว
Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA In this video lecture we will find the centroid of a Composite shape/irregular shape #engineering mechanics #applied mechanics #Symmetrical shapes #what is symmetry #Gate Engineering mechanics #fundamentals of mechanical engineering #what is centroid? #centroid #centroid of composite planes
ANSYS WORKBENCH TUTORIAL | Buckling analysis of column | Buckling Load | Theoretical Vs ANSYS
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA
Engineering Mechanics | Motion under Acceleration due to Gravity | Polar Bear problem | GATE
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains 1. How to apply the concepts of motion due to gravity? 2. How to understand acceleration due to gravity? 3. How to determine the color of the bear?
How to identify angles relationship between transversal and parallel lines | Corresponding Angle
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explain how to to identify angles formed by a transversal when intersecting two parallel lines which include: corresponding angles, alternate interior angles and alternate exterior angles. This video lecture also explain how to to identify angles formed by the intersection of two lines and the...
Engineering Mechanics | How to apply Lami's Theorem | How to draw Free Body Diagram | GATE
มุมมอง 465ปีที่แล้ว
Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains 1. How to draw Free Body Diagram? 2. How to apply Lami's Theorem? 3. Determining Reaction forces at Hinged Joint/ Pin Joint.
Tool Design | Centre of Pressure | Blanking Force | Irregular Shaped Blank | Tutorial
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains 1. How to determine Centre of Pressure for irregular shaped blank? 2. How to determine the blanking force?
Tool Design | Blanking Die Design | Centre of Pressure | Basics
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Strength of Materials Lecture | Euler's Crippling Load | Euler's Buckling Load | Columns | Struts
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains 1. How to determine Crippling/Buckling Load 2. How to apply Euler's Theory
What is Stress Strain Curve? | Elastic Limit | Yield Stress | Ultimate Stress
มุมมอง 2.3K2 ปีที่แล้ว
Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains 1. How to draw stress strain curve? 2. How to interpret stress strain curve? 3. What is elastic limit? 4. What is yield strength/Stress? 5. What is ultimate strength/Stess?
Mechanics of materials Lecture | Stress Strain Diagram Problem | Tensile test Problem
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains 1. How to determine Young's Modulus? 2. How to determine Stress at Elastic limit? 3. How to determine Ultimate tensile stress? 4. How to determine the Elongation percentage? 5.. How to determine the percentage reduction in cross sectional area?
Mechanics of Materials Lecture | Hooke's Law Problem | Poisson's Ratio Problem
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains how to determine change in dimension of a axially load member by applying Hooke's Law and Poisson's ratio.
Lami's Theorem Problem in Engineering Mechanics | Strength of Materials |Normal stresses Problem
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Dr. Michael Thomas Rex, National Engineering College, Kovilpatti, Tamil Nadu, INDIA This video lecture explains 1.How to draw Free body diagram? 2. How to apply Lami's Theorem? 3. How to determine Normal Stresses?
End Milling Simulation | Ansys Workbench | Explicit Dynamics
มุมมอง 9222 ปีที่แล้ว
End Milling operation simulation suing Ansys Workbench Explicit Dynamics
Deflection of Beams Problem | Macaulay's Method | simply supported beam | GATE
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Deflection of Beams Problem | Macaulay's Method | simply supported beam | GATE
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ความคิดเห็น

  • @prajwalgowda9773
    @prajwalgowda9773 5 หลายเดือนก่อน

    Sir You take minimum to maximum..... maximum to minimum 🤔🤔🤔

  • @prajwalgowda9773
    @prajwalgowda9773 5 หลายเดือนก่อน

    Sir minimum energy is 270 . but you take 295 ? how sir posible

  • @resueltoalma4773
    @resueltoalma4773 7 หลายเดือนก่อน

    thank you❤

  • @nsulwachugambuli7001
    @nsulwachugambuli7001 7 หลายเดือนก่อน

    What about to draw a failure envelope and estimate the coefficient of friction for the failure

  • @nsulwachugambuli7001
    @nsulwachugambuli7001 7 หลายเดือนก่อน

    Your the great thank you

    • @michaelthomasrex
      @michaelthomasrex 7 หลายเดือนก่อน

      Thanks for the compliment

  • @richbob5
    @richbob5 7 หลายเดือนก่อน

    For the radius: R=87.32 For the Max shear stress: τmax=87.32MPa For principal stresses: σmin=82.32MPa and σmax=92.32MPa For the angle at which we have to rotate to get to get the point A&B at in the horizontal plane is: 2θp=66.37° And the orientation of the principal plane is: θp=33.19° Can someone confirm these answers for me?

    • @michaelthomasrex
      @michaelthomasrex 7 หลายเดือนก่อน

      The answer is available in the description of the video

  • @manikandaprabhug4471
    @manikandaprabhug4471 7 หลายเดือนก่อน

    Thankyou Sir

  • @abhishekdhabarde8214
    @abhishekdhabarde8214 7 หลายเดือนก่อน

    Thank you so much sir 🙏 Nice explanation 👍

  • @edn8624
    @edn8624 7 หลายเดือนก่อน

    Thank you so much

  • @sadhvikbutti.sadhvik2987
    @sadhvikbutti.sadhvik2987 7 หลายเดือนก่อน

    Sir Ra+Rb=48+45=93 But u consider 48+40=88

    • @michaelthomasrex
      @michaelthomasrex 6 หลายเดือนก่อน

      "There's a typo in the question; please consider replacing '45' with '40'."

  • @bugrahangul3740
    @bugrahangul3740 7 หลายเดือนก่อน

    How can ı reach you?

    • @michaelthomasrex
      @michaelthomasrex 7 หลายเดือนก่อน

      Mail me at michealrex20@gmail.com

  • @romansheik6527
    @romansheik6527 7 หลายเดือนก่อน

    Solution : drive.google.com/file/d/1MO7O5Bd06reEJLVu0cGAnfS6ku3_5qqA/view?usp=drivesdk

  • @ernestmaisela1211
    @ernestmaisela1211 8 หลายเดือนก่อน

    I like the video and I I want to know where to find more videos for different exercises

  • @abdulsamad-tr1jw
    @abdulsamad-tr1jw 8 หลายเดือนก่อน

    Why the Mohor circle the y components of central of circle is taken is zero And why the x component is not taken is zero

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      When considering the Mohr circle for stress analysis, it's essential to understand the coordinate system used. Typically, the x-axis represents the normal stress, and the y-axis represents the shear stress. In the center of mohr's circle, shear stress is zero because it represents the stress state where the maximum and minimum principal stresses act on the same plane

  • @HassanIftikhar-q6d
    @HassanIftikhar-q6d 9 หลายเดือนก่อน

    Man you make a mistake as in mohr circle y axis in 3 or 4 block must be +ve while -ve in 1 and 2 block

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      There is no thumb rule in selecting positive and negative axes, so it is not a mistake. You can choose as you wish. However, the x-axis represents normal stress, and the y-axis represents shear stress

  • @imanayt_j
    @imanayt_j 9 หลายเดือนก่อน

    You have my heart ❤️ Thank you so so much

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      Thanks for watching. Kindly subscribe to the channel.

  • @Firas.7
    @Firas.7 9 หลายเดือนก่อน

    Perfect ❤

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      Thanks for watching. Kindly subscribe to the channel.

    • @Firas.7
      @Firas.7 8 หลายเดือนก่อน

      @@michaelthomasrex ok

  • @farismashaqbah5791
    @farismashaqbah5791 10 หลายเดือนก่อน

    👍🇯🇴

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      Thanks for watching. Kindly subscribe to the channel.

  • @galibshaikh3632
    @galibshaikh3632 11 หลายเดือนก่อน

    Subscribing because of your this wonderful explanation!!! Thanks sir🫂

  • @ArifinIndaka
    @ArifinIndaka 11 หลายเดือนก่อน

    Tutor?

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      I will update it soon. Kindly subscribe to the channel.

  • @rakshithkumarrakshithkumar-h6f
    @rakshithkumarrakshithkumar-h6f 11 หลายเดือนก่อน

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      Thanks for watching. Kindly subscribe to the channel.

  • @sundaresanmurali7949
    @sundaresanmurali7949 11 หลายเดือนก่อน

    Thanks to my guru.

    • @michaelthomasrex
      @michaelthomasrex 11 หลายเดือนก่อน

      Thanks for the comments. Kindly subscribe to the channel.

  • @AbhishekKumar-vf5ep
    @AbhishekKumar-vf5ep 11 หลายเดือนก่อน

    Sir kindly help..how to give proper constraints in case of both end fixed??

    • @michaelthomasrex
      @michaelthomasrex 8 หลายเดือนก่อน

      I will post the video soon. Kindly subscribe to the channel.

  • @reinahadassa
    @reinahadassa 11 หลายเดือนก่อน

    Sir, I think the sign convention for Normal Stress is wrong. The tension should be negative and compression is positive.

    • @michaelthomasrex
      @michaelthomasrex 11 หลายเดือนก่อน

      Any Sign convention is correct. However, you have to maintain it throughout the problem. The answer will not change.

  • @TroyAlfred-li6rf
    @TroyAlfred-li6rf 11 หลายเดือนก่อน

    This video was so helpful. However i just wanna confirm my answers. For the radius: R=83.82 For the Max shear stress: τmax=83.82MPa For principal stresses: σmin=78.82MPa and σmax=88.82MPa For the angle at which we have to rotate to get to get the point A&B at in the horizontal plane is: 2θp=72.64° And the orientation of the principal plane is: θp=36.32° Can someone confirm these answers for me?.

    • @michaelthomasrex
      @michaelthomasrex 11 หลายเดือนก่อน

      Thanks for watching. The answers are correct.

    • @LebogangMnisi-v2j
      @LebogangMnisi-v2j 8 หลายเดือนก่อน

      Help I'm getting 87,32 as my R 😭

  • @raoneialves1138
    @raoneialves1138 11 หลายเดือนก่อน

    Excellent..

    • @michaelthomasrex
      @michaelthomasrex 11 หลายเดือนก่อน

      Keep watching! Kindly subscribe to the channel.

  • @Gokhulkumarkashyap01
    @Gokhulkumarkashyap01 ปีที่แล้ว

    Thank you sir

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Keep watching. Kindly subscribe to the channel 🙂

  • @chelluboinasaivamsi1757
    @chelluboinasaivamsi1757 ปีที่แล้ว

    Nice explanation sir

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Keep watching. Kindly subscribe to the channel 🙂

  • @md.alimalrabby2713
    @md.alimalrabby2713 ปีที่แล้ว

    mind blowing teaching

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Keep watching. Kindly subscribe to the channel

  • @shukurullomeliboyev2004
    @shukurullomeliboyev2004 ปีที่แล้ว

    thank you a lot, you made it very easy and understandable, thanks again😊👌🇺🇿

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      You are welcome! Kindly subscribe to the channel.

  • @zirotube123
    @zirotube123 ปีที่แล้ว

    isnt it counterclockwise positive and clockwise negetive???

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      The clockwise rotation created by the shear forces at any face is always positive. Similarly, the counter clockwise rotation created by the shear forces at any face is always negative.

  • @PereraArunodha
    @PereraArunodha ปีที่แล้ว

    Perfect sir😊❤

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Keep watching. Kindly subscribe to the channel.

  • @DerrickTenkorang
    @DerrickTenkorang ปีที่แล้ว

    Can i compare answers for the 2nd question

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      The principal stresses: 88.8 Mpa & 78.8 Mpa Position of Principal Plane :36.3 degree (CCW)

  • @talha9276
    @talha9276 ปีที่แล้ว

    Nice video to watch before exam

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Thanks for watching. Kindly subscribe to the channel.

  • @godwinayamga9156
    @godwinayamga9156 ปีที่แล้ว

    Please how can I find the magnitude and direction of principal stresses?

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      The magnitude of the principal stresses are the distance of extreme stress values from the centre to the points where the circle intersects the horizontal axis. Please refer the video in time line 17.52 for orientation of principal plane.

  • @sj4s
    @sj4s ปีที่แล้ว

    Nice.Informative

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Thanks for the compliment. Kindly subscribe to the channel

  • @freemanfootball647
    @freemanfootball647 ปีที่แล้ว

    omega r(sintheta+ cos2theta/n)=0 why remain ncostheta+cos2theta =0, where omega r ??

  • @zohainapasandalan4324
    @zohainapasandalan4324 ปีที่แล้ว

    Thank you so much for the precise and clear explanation sir❤

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      You are most welcome. Kindly subscribe to the channel.

  • @muhdlufy6185
    @muhdlufy6185 ปีที่แล้ว

    VERYVERY GOODSIR,GOOD TO KNOW SOMEONE LIKE U EXISTED ❤

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Thanks for the comments. Kindly subscribe to the channel.

  • @Rbsk25
    @Rbsk25 ปีที่แล้ว

    Thanks Sir for this video and way of explanation

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Most welcome.kindly subscribe to the channel.

  • @NAGUMURALA
    @NAGUMURALA ปีที่แล้ว

    Sir I didn't understand why theeta is only pi/2 in tmax

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      The maximum torque is obtained at exactly middle of the power stroke. Hence the angle is pi/2. The total angle covered during the power stroke is pi.

  • @MechTechSimulations
    @MechTechSimulations ปีที่แล้ว

    Nicely explained professor!

  • @mdistaz2002
    @mdistaz2002 ปีที่แล้ว

    It is so simply way to explain a a lot of thanks sir

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      You are most welcome. Kindly subscribe to the channel.

  • @DadaAdebayo-nf9sg
    @DadaAdebayo-nf9sg ปีที่แล้ว

    I've been watching series of videos on this particular Mohr's circle and I'd say this is the best so far!!! You're a great teacher sir!❤❤❤

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      You're very welcome! Kindly subscribe to the channel and share it with your friends.

    • @Khaǔ-Kanǎn
      @Khaǔ-Kanǎn ปีที่แล้ว

      For me too.🎉🎉🎉

  • @mr__xeditorgaming7062
    @mr__xeditorgaming7062 ปีที่แล้ว

    I think I found one mistake, in 6(circle) the x distance you write 1 , while in drawing it's 10 cm , please ans me ,may be i am wrong !

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      It is mentioned as 1.0 cm in the drawing. I think, the dot may be not visible. Thanks for the comments. kindly subscribe to the channel and share the video lecture with your friends.

  • @avishkar4131
    @avishkar4131 ปีที่แล้ว

    You have not converted kg/mm2 into N/mm2 by multiplying by 9.81 Except that everything is perfect

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Thanks for the comments. Kindly subscribe to the channel and share the video lecture with your friends.

  • @axk7516
    @axk7516 ปีที่แล้ว

    Good expalination brother, easy to understand❤

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      You are welcome. Kindly subscribe to the channel and share the video lecture with your friends.

  • @Epic_multiverse
    @Epic_multiverse ปีที่แล้ว

    Nice explanation. While orientation, how did you recognised max and min force will be along y and x axis

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      In this problem, the point A denotes the X face. When is rotated to the horizontal in CCW direction, we have got principal stresses. So the intersection point is 9.66 Mpa. Hence the 9.66 Mpa is considered along X axis while orienting principal stresses. Similarly, the point B denotes the Y face. When is rotated to the horizontal in CCW direction, we have got principal stresses. So the intersection point is 13.66 Mpa. Hence the 13.66 Mpa is considered along Y axis while orienting principal stresses. Hence, the maximum and minimum just represent the numerically maximum and minimum value among principal stresses.

  • @sundaramsingh752
    @sundaramsingh752 ปีที่แล้ว

    Amazing explanation sir , thank you so much Sir for a good video.

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      You are welcome. Kindly subscribe to the channel and share the video lecture with your friends.

  • @tgshamimamelin1621
    @tgshamimamelin1621 ปีที่แล้ว

    Where can i check my ans

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      Thanks for the comment. It is now available in the description.

    • @michaelthomasrex
      @michaelthomasrex ปีที่แล้ว

      The principal stresses: 88.8 Mpa & 78.8 Mpa Position of Principal Plane :36.3 degree (CCW)