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Many thanks.

Brilliant! Thanks for the comment and especially for Subscribing too.

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That's great. Many thanks for your comment, much appreciated.

If only I published it sooner 😆

Really depends how you want the Switch to operate your device. In Bi-stable mode you typically utilise two momentary push button switches; one to latch a HI output and the other to latch LO. The behaviour is therefore quite different to a single push operation.

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Thanks. A dedicated Schmitt IC is the better option, although I suspect many hobbyists have 555s in their home collection but not necessarily Schmitt triggers.

@ I see. Actually I also have a bunch of 555. And I like the idea of hysteresis configuration. Btw, are you planning to describe a different variations of 555 maybe? For example speedy ones: Lmc555(up to 3MHz) or Tlc555 (over 2Mhz) I have no idea where I could use such a speedy species of this family. For the radio devices construction, maybe?

Welcome!

It's a bit confusing because the Output pin can both "Source" and "Sink" current. So when it's HI, it provides a positive voltage. When it's LO, it's like connecting to ground. Does this help?

@paulpkae yes thank you. You also explain this in the following video with the simplified version

Excel is incredibly powerful and useful tool.

Well spotted, you are the only person so far to mention that. I can see now that my calc is incorrect and your result is indeed right! My apologies for the confusion. I have been trying to work out how I inadvertently arrived at 0.0165 but can see no obvious reason. It must have been a mad moment or a cut and paste boo boo from something else. I will add a correction note in the comments. Thanks for this.

No, its exactly as shown. 1 over 2 x PI x Freq (in Hz) x Capacitance (in Farads). Make sure you multiply the bottom line first, i.e. 6.283x1000x0.0000022 = 0.0138226. Then take the reciprocal (or one over) of this result and you get 72.345......

@@paulpkae Ah I missed a step thank you

Thanks for the comment. For those interested in the Schmitt Trigger IC alternative see my previous video here:- th-cam.com/video/JrCIgBUPhro/w-d-xo.htmlsi=zdwQePjjZ9tjILGp

Great question thank you. When the circuit is in the ON state, the capacitor provides sufficient delay, for when the switch is pressed again, to allow the MOSFET to turn off. Without it, then when the BJTs turn off, the right-hand side of the switch is immediately pulled high (via the 660K and middle 100K resistor) and subsequently the BJTs turn back on before the MOSFET had a chance to turn OFF.

⁠@@paulpkae Thank you!

Reactance ☺️

Thanks so much!

@@michaelrtreat many thanks.

@@alanturner1184 that's great! Thanks for your comment. Your grandchild will probably remember that presious time for years to come.

@@paulpkae Keeps me on my toes if you asked me what a breadboard was just over a year ago for cutting bread would of been reply Cheers again

@@sadeghmollaii9873 thank you.

Video coming for Monostable operation. 😁

There 's no guarantee that the contacts will break cleanly. If they bounce as they open the monostable may trigger again.

The problem with using a 555 in monostable state for denouncing is that the 555 won't hold the delay while the trigger is triggered. Say you have the 555 delay for 100mS, and you hold the switch down for 1S, the 555 will still reset at least briefly after 100mS.

@@danman32 actually a good point. I have to check if there is possibility to avoid this. If no, well - In this case I think usage of comparator will be more reliable…

@@CybisterBug there is if you're not particular about the timing. Use a transistor to hold the capacitor discharged whenever and during the time the trigger is asserted. Timing will then start once the trigger remains deasserted The problem with 555's, especially in monostable mode is that there's a timing difference between right after power up when capacitor is completely discharged, to during normal operation where capacitor would be at 1/3 VCC at idle.

Hi. Yes they all adopt the same architecture but with varying characteristics such as maximum current, rise/fall times, CMOS/TTL, BJT/FETs.... etc

Glad you enjoyed it

Thanks for the comment. I think once you've truly learnt something you never really forget; you just need a little reminder. :)

Thanks.

Yes you are correct, but you are missing the "Power" bit. Power factor is the ratio of real power (the actual power consumed) to apparent power (the combination of real and reactive power, where reactive power is the unused portion), indicating how effectively electrical power is being used in a circuit. Capacitors are added to temporarily store the reactive energy generated by inductive loads during the AC cycle, helping to improve the power factor by reducing the overall reactive power demand. I will be doing a follow up video on Power Factor pretty soon.....

Thanks Electronzap, and hi to a fellow Tuber. I have watched some of your channel previously.

@@paulpkae That's awesome :)

There's a link at the bottom of this Short video to the main video with full explanation. This is the first Short I have tried out BTW. Or use this link:- th-cam.com/video/4HDrjWHvqjI/w-d-xo.htmlsi=qggWJUkDeMSisndC

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Thanks for watching and your info. If anyone is interested about Impedance Matching, I did do a follow up video in response to another viewer's request some time ago. See link below:- th-cam.com/video/5p0v7ZU0WcA/w-d-xo.html

@@paulpkae oh excellent, that's my tea-time sorted

Glad it was helpful, and thanks for the comment.

Glad it was helpful!

That's great! Thanks for Subscribing.

Brilliant! Enjoy playing around with your circuits and do let us know how you get on.

@@paulpkae Will do cheers

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Many thanks, that's a great comment to receive, much appreciated.

Glad it was helpful!

@@halb1282 great! Thanks for your comment. Much appreciated.

@@irpiyaprach9555 thanks for the comment. Glad you liked it. Although it's free, you can help by Subscribing and Liking. It makes all the difference, thanks.