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Given if α β are zeroes of quadratic polynomial f(x)=x2−5x+k f(2)=x2-5x+k=0 =4-10+k=10 ans) 10 class aadi poli ayirunnu😍😍😍😍🥰🥰🥰 ellam manasillayi❣❣❣❣❣❣ thank youuuuu🥰🥰🥰🥰🥰
Ans : The value of k=6 Thank you so much Exam winners family for providing this type of wonderful classes which is absolutely a cure for students like me who are weak in some subjects 🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉 Thank you for being with us like an aid 🏆🏆🏆🏆🏆🏆🏆🏆🏆
Givenp(x) = x² - 5x + k2 is the zero of the polynomial. To findValue of k Since 2 is the zero of the given polynomial, therefore we have to put the value of x = 2 Hence,Value of k is 6. Good class🎉🎉 Really understood the topics❤❤
💯💯💯💯Class nice aayirunnu, confusions ellaam theernnu.Ini polynomials full mark urappu 💯💯💯💯 🔥One 0 of the polynomial x²-5x+k is 2🔥 🔥By substituting 2 in p(x),🔥 🔥P(2)= 4-10+k=0🔥 🔥-6+k=0🔥 🔥K=6🔥💯💯💯
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Given, Zero of quadratic polynomial is 2 To find the value of k P(2)= (2)²-5(2)+k=0 = 4-10+k=0 =-6+k=0 K=6 Maam your class was amazing and helpful 🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥
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Q) If one zero of the quadratic polynomial of x2-5x+k is 2, then find the value of k. Ans) x2-5x+k=0 (2)2-5(2)+k=0 4-10+k=0 -6+k=0 k=6 EXAM WINNER🔥>>>>>>
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X^2 - 5x + k is 2, then the value of 'K' is P(x)=2 i.e p(2) = 2^2 - 5×2 + k = 0 》 4 - 10 + k = 0 》 -6 + k = 0 Therefore, k = 6 Class adipolli aayirunnu misse EXAM WINNER ❤🔥❤🔥
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By substituting 2 in the place of x we get
4-10+k
=-6+k
=ie, k = 6
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Given if
α
β
are zeroes of quadratic polynomial
f(x)=x2−5x+k
f(2)=x2-5x+k=0
=4-10+k=10
ans) 10
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P(x) = x^2 - 5x + k
P(2) = 0
P(2) = 2×2 - 5×2 + k = 0
=4 - 10 + k = 0
=-6 + k =0
k = 6
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Ans : The value of k=6
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alpha +beta = -b/a
-(-5)/1= 5//
2+beta =5
beta = 5-2= 3
alpha ×beta = -c/ a
2×3=6
-k/a = 6
-k/1= 6
-K = 6
K = 6
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The value of k=6
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*K* value=6
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Givenp(x) = x² - 5x + k2 is the zero of the polynomial.
To findValue of k
Since 2 is the zero of the given polynomial, therefore we have to put the value of x = 2
Hence,Value of k is 6.
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Value K = 6
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K=6
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🔥One 0 of the polynomial x²-5x+k is 2🔥
🔥By substituting 2 in p(x),🔥
🔥P(2)= 4-10+k=0🔥
🔥-6+k=0🔥
🔥K=6🔥💯💯💯
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Given,
Zero of quadratic polynomial is 2
To find the value of k
P(2)= (2)²-5(2)+k=0
= 4-10+k=0
=-6+k=0
K=6
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The value of k is 6 🔥🔥
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X*2-5x+k
2*2-5×2+k
4-10+k
-6+k
K=6
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K=6
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Class starts 9.30
Q) If one zero of the quadratic polynomial of x2-5x+k is 2, then find the value of k.
Ans) x2-5x+k=0
(2)2-5(2)+k=0
4-10+k=0
-6+k=0
k=6
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Answer of the day 6
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2
3
6
0
K=6
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K =6
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X^2 - 5x + k is 2, then the value of 'K' is
P(x)=2
i.e p(2) = 2^2 - 5×2 + k = 0
》 4 - 10 + k = 0
》 -6 + k = 0
Therefore, k = 6
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p(x)=x²-5x+k
p(2)=0
2²-5×2+k=0
4-10+k=0
-6+k=0
k=6
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Here,
the quadratic equation is x²-5x+k
One of the zero is 2
So, p(2)=0
p(2)=2²-5(2)+k=0
=4-10+k=0
=-6+k=0
k=6
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Answer
x²-5x+k
P(2)=0
2²-5×2+k=0
4-10+k=0
-6+k=0
k=0+6
k=6
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K=6
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x²-5x+k=0
X=2
2²-(5×2)+k
4-10+k
-6+k=0
K=6
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p of x=x²-5x+k.
alpha+beta=5
. 2+beta=5 .
beta=3 .
Therefore alpha.beta =k
2.3=k
Therefore k=6
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Alpha + beta = -b/a =5
Alpha= 3
Alpha. Beta = c/a = k
= 3×2
ie, k=6
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The questions answer:
K=6
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k=6
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K=6
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K=6
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The value of k is 6 🔥🔥🔥🔥
K = 6
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2
K = 6 💯💯💯
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Value of k = 6
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Value of K= 6
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The value of K=6
1
K=6
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1
K=6
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2
K=6
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K=6
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K=6
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K=-6
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K=6
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K=6