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Mentally combining these equations yields the simple answers a = b = c = 0 or ±√2 Look, a + (a + b + c) = b + (a + b + c) = c + (a + b + c) = 2abc 2abc - a = 2abc - b = 2abc - c yields a = b = c If a = b then 2a = a^3 or a^2 = 2, which yields a = b = c = ±√2
Beautifully done , and delightfully simple innovative method of solving.
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Good. Exactly if you divide 1 by 2, 1 by 3 and 2 by 3.
Отличное упражнение, симпатичное решение,но a+b=b+c=c+a сразу даёт a=b=c.
a + b = b + c => a = c
b + c = c + a => b = a
so a = b = c and 2a = a ^3
2 = a^2, a = b = c = ✓2 or -✓2
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Mentally combining these equations yields the simple answers a = b = c = 0 or ±√2
Look, a + (a + b + c) = b + (a + b + c) = c + (a + b + c) = 2abc
2abc - a = 2abc - b = 2abc - c yields a = b = c
If a = b then 2a = a^3 or a^2 = 2, which yields a = b = c = ±√2
It is a nice solution
Thank you very much!!!