Proving Algebraic Inequalities (2 of 3: Using the sign)

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  • เผยแพร่เมื่อ 2 ม.ค. 2025

ความคิดเห็น • 27

  • @ifercantread
    @ifercantread 3 ปีที่แล้ว +3

    I'm not even learning this yet and have no idea what this is and yet I watched this whole video? Your teaching is so entertaining, I see why people worldwide wish you were their maths teacher lol

  • @RoniRonkoKovatch
    @RoniRonkoKovatch 3 ปีที่แล้ว

    1:47
    Still waiting for full attention.......
    we are almost there......
    *staring at some student, waiting for his acknowledgement.....*
    *student finally acknowledges*
    *eddie woo thumbs up to the student*.
    eddie woo: thank you.
    and the lesson continues...
    even "roasting" the students can be in style and educational and not provocative or humiliating or anything!

  • @meriemouaddi3993
    @meriemouaddi3993 3 ปีที่แล้ว +1

    I used to watch BLACK PEN AND RED PEN's and your videos 2 years ago.. and i want to thank you so much because today i am a CPGE student and "la majorante des maths" ❤❤

    • @aashsyed1277
      @aashsyed1277 3 ปีที่แล้ว

      same for me! i watch blakpenredpen and eddie WOO TO!

  • @explorerc607
    @explorerc607 3 ปีที่แล้ว +1

    Eddie, are there many students from Year 7-9 partipating in mathematic competition in your school? What do you think is the most important thing for IMO? Have you ever supervised students who finally represented Australia for IMO?

    • @particleonazock2246
      @particleonazock2246 3 ปีที่แล้ว

      This is a brilliant question. I want to know if Woo can do more math competition oriented videos, as they will boost our mathematical intuition.

  • @wherethereiswillthereisway7350
    @wherethereiswillthereisway7350 3 ปีที่แล้ว +1

    Omg !! Can u pls explain full calculus up to advance level....pls pls ,u teach math so simply ,and am so lucky that am learning from u ....😉thnks u tube

  • @MathZoneKH
    @MathZoneKH 3 ปีที่แล้ว +1

    Very nice sir

  • @sasismind8856
    @sasismind8856 3 ปีที่แล้ว +1

    R you working in byjus sir ??

  • @particleonazock2246
    @particleonazock2246 3 ปีที่แล้ว

    Economists: There's no such thing as a free lunch.
    Math viewers of Eddie's channel: Watch Eddie's channel, there's a wealth of mathematical videos.
    Eddie Woo: My time has come!

  • @Oldoldodldpodjdjd
    @Oldoldodldpodjdjd 3 ปีที่แล้ว

    This is amazing! Thanks a ton!

  • @realmarker
    @realmarker 3 ปีที่แล้ว

    I like to think that the camera is ontop of some kid’s afro

  • @WinThis1
    @WinThis1 3 ปีที่แล้ว

    Legend

  • @particleonazock2246
    @particleonazock2246 3 ปีที่แล้ว

    Gyoza (餃子) under attack. Wo ai jiaozi. Please save my gyoza, even tho GAZA under attack.

  • @MathZoneKH
    @MathZoneKH 3 ปีที่แล้ว +1

    😍😍👍😍👍

  • @David-km2ie
    @David-km2ie 3 ปีที่แล้ว

    Actually there was nothing wrong with the first line of tought since it are iff relations

    • @jamiewalker329
      @jamiewalker329 3 ปีที่แล้ว

      Exactly. Eddie's strength isn't logic - all he needs is bivariate implication arrows all the way down. It's very frustrating, as this is where misconceptions are born and his platform is huge. His recent videos have been littered with errors...

  • @quake4729
    @quake4729 3 ปีที่แล้ว +3

    Why tf I'm poor

  • @nerdymath89
    @nerdymath89 3 ปีที่แล้ว

    🙏🙏👍

  • @andrewsyom
    @andrewsyom 3 ปีที่แล้ว +3

  • @aashsyed1277
    @aashsyed1277 3 ปีที่แล้ว

    yuyuy

  • @Wagw
    @Wagw 3 ปีที่แล้ว +1

    Exactly. Students always messes up proving questions.

    • @michaelempeigne3519
      @michaelempeigne3519 3 ปีที่แล้ว

      This is a much better proof to show that ( 1 / 2 )*(a^2 + b^2 ) > or = [ ( a + b ) / 2 ]^2
      AM - GM inequality gives : ( 1 / 2 )*( a^2 + b^2 ) > or = sqrt ( a^2 * b^2 )
      ( 1 / 2 )* ( a^2 + b^2 ) > or = ab -- ( equation 1 )
      (a^2 + b^2 ) > or = 2ab
      a^2 + 2ab + b^2 > or = 2ab + 2ab
      a^2 + 2ab + b^2 > or = 4ab
      ( a + b )^2 > or = 4ab
      ( 1 / 4 ) ( a + b )^2 > or = ab
      [ ( a + b ) / 2 ]^2 > or = ab -- ( equation 2 )
      equation 1 - equation 2 : ( 1 / 2 )*( a^2 + b^2 ) - [ ( a + b ) / 2 ]^2 > or = 0
      ( 1 / 2 )*( a^2 + b^2 ) > or = [ ( a + b ) / 2 ]^2

  • @aashsyed1277
    @aashsyed1277 3 ปีที่แล้ว

    ygfuuuuh