Dynamics: Transverse and Radial Components of Velocity and Acceleration

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  • เผยแพร่เมื่อ 12 ก.ย. 2024
  • In this video, we introduce breaking down Position, Velocity, and Acceleration into components based on the Polar coordinate system (uses r and theta rather than x and y). The two axes that we use to break these vectors into two components are called the Transverse and Radial axes.
    This coordinate system is also referred to as the "cylindrical" coordinate system if we include a "z" coordinate to measure the elevation of the target object as well. Here however, we only take a look at 2D, which means "r" and "theta" (without "z")

ความคิดเห็น • 89

  • @marc-antoinetremblay6539
    @marc-antoinetremblay6539 6 หลายเดือนก่อน +7

    I cant believe i’ve paid 500$ for this class, and this guy just broke it down in 15min, I really hope you are a teacher, might never need this again but im subscribing just to encourage you

    • @eng1048
      @eng1048  4 หลายเดือนก่อน +1

      That's very kind of you :) Best of luck

  • @AvoRothenstein
    @AvoRothenstein ปีที่แล้ว +7

    I've been having a really hard time in dynamics and didn't understand the equations or what transverse or radial acceleration and velocity were. This video gives me hope. I can't wait to watch more videos.

    • @eng1048
      @eng1048  ปีที่แล้ว +1

      Great to hear!

  • @charlesds1539
    @charlesds1539 2 ปีที่แล้ว +9

    Wow! You are very good at making things clear, thank you so so much!

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      Thank you! I enjoy explaining things and showing how even the most complicated topics can be visualized and broken down :) Especially if you give scenarios where the knowledge is actually used and applied. THat's the whole point of Engineering anyways!

  • @amalsal9559
    @amalsal9559 11 หลายเดือนก่อน

    I came from an entirely different background and this surprisingly doesn't look scary at all. My sincere thanks and gratitude.

  • @maksurdu9305
    @maksurdu9305 10 หลายเดือนก่อน

    OMG!!! I've been looking for this the whole internet!!! You're an amazing tutor.

  • @Oscar-gx2yf
    @Oscar-gx2yf 3 ปีที่แล้ว +2

    The best video I've seen on this topic. Thank you!

  • @ProfessorDingus
    @ProfessorDingus 3 ปีที่แล้ว +1

    Lifesaver. My dynamics prof didn't cover this in lecture but gave a HW problem on it as if this is just obvious?!!

    • @eng1048
      @eng1048  2 ปีที่แล้ว +1

      Profs usually suck lol

  • @marelleclejon6694
    @marelleclejon6694 2 หลายเดือนก่อน

    This is literally the best video I've ever seen!!! Good job!

    • @marelleclejon6694
      @marelleclejon6694 2 หลายเดือนก่อน

      Okay, I said that before watching the full video, but I just got to 10:10 and my mind is blown, this is better than the best

    • @marelleclejon6694
      @marelleclejon6694 2 หลายเดือนก่อน

      I'm not even sure how I got through physics 1 without knowing the fundamentals this video is instilling in me now

  • @user-iu2hd1ny9c
    @user-iu2hd1ny9c 27 วันที่ผ่านมา

    the minute i started seeing whats vtheta and theta dot i had to like the vid seems like i will be staying for the course

  • @OMARYassin1
    @OMARYassin1 4 ปีที่แล้ว +1

    Your channel is just great.. and your demonstration is very clear.. keep it up

    • @eng1048
      @eng1048  4 ปีที่แล้ว +1

      Great man I really appreciate your positive feedback! I love teaching Engineering and I want things to make sense

  • @BODYBUILDERS_AGAINST_FEMINISM
    @BODYBUILDERS_AGAINST_FEMINISM 2 ปีที่แล้ว

    The way you talk is very relaxing.

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      Glad you think so!

  • @ramyasrinivas3083
    @ramyasrinivas3083 3 ปีที่แล้ว +3

    Excellent explanation!! Thank you

    • @eng1048
      @eng1048  3 ปีที่แล้ว +1

      Glad it helped :)

  • @pratyushpathania7030
    @pratyushpathania7030 3 หลายเดือนก่อน

    Beautiful video

  • @shashwatsharma9399
    @shashwatsharma9399 3 ปีที่แล้ว +1

    You made it very easy to understand 👏 thank you

    • @eng1048
      @eng1048  3 ปีที่แล้ว

      I am glad my friend :)

  • @brunospasta
    @brunospasta หลายเดือนก่อน

    Thank you!

  • @Megha-rv2hd
    @Megha-rv2hd 3 ปีที่แล้ว +1

    Thx a lot 😇😇😇.. Very very helpful thing....

    • @eng1048
      @eng1048  3 ปีที่แล้ว

      Thanks, glad it helped! :)

  • @bokyung8322
    @bokyung8322 3 ปีที่แล้ว +1

    perfect explanation! Thank you!!

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      thanks for the positive comment!

  • @abirahmed6213
    @abirahmed6213 3 ปีที่แล้ว

    Really well explained man, appreciate it.

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      No problem!

  • @yohannesabel7681
    @yohannesabel7681 2 ปีที่แล้ว +1

    you are great bruh!

  • @valeriehawkins5358
    @valeriehawkins5358 ปีที่แล้ว

    Great explanation on transverse and radical components! It helped me out a lot. I wish you explained what you mean by "True velocity is always tangent to my path" though. In a different question (same principles) how would I determine the direction of the yellow arrow (drawn at 13:18).

    • @eng1048
      @eng1048  ปีที่แล้ว +1

      To your first question:
      Remember, speed (velocity) is an instantaneous quantity. I can have one speed at one instant, and another speed at another instant. Even if my speeds are the same at two different instances, if you are facing (imagine you are driving a car on a curved path) different directions at those 2 different instants, your velocity (which is just speed but incorporating the idea of direction) is different between those 2 instants.
      So the DIRECTION of your velocity at a specific instant is basically "which direction am i facing/travelling at that instant". Think about this a little bit and hopefully the idea that "velocity is tangent to the path" will become more digestible.
      Your second question:
      If you knew the transverse (r times theta dot) and radial (r dot) components of your velocity at that instant, you can draw a right triangle and use the inverse tangent. Keep in mind that components of a vector do that tip-to-tail vector addition thing to add up to get the resultant vector. Thats why you can draw that right triangle between the radial and transverse component and the true resultant velocity vector. Once you drawn that right triangle, you can use the inverse tangent to get an angle for the actual velocity vector.

  • @brentlackey8316
    @brentlackey8316 2 ปีที่แล้ว

    00:00
    The object is the satelite, not the dish or antennae which tracks it.

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      I'll buy that

  • @ekminigodage2724
    @ekminigodage2724 3 ปีที่แล้ว

    BEST BEST BEST....Thanku so much for getting me away frm stress coz by this topic

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      Most welcome 😊

  • @mohammadshabih5293
    @mohammadshabih5293 11 หลายเดือนก่อน

    thank you, this helped a lot

  • @PravatAryal650
    @PravatAryal650 3 ปีที่แล้ว +1

    Thanks

  • @himaniverma5504
    @himaniverma5504 4 ปีที่แล้ว +2

    Thank you so much!

    • @eng1048
      @eng1048  4 ปีที่แล้ว

      Awesome! Glad it helped :)

  • @OMARYassin1
    @OMARYassin1 4 ปีที่แล้ว +1

    Very great video

    • @eng1048
      @eng1048  4 ปีที่แล้ว +1

      Thank you! Cheers!

  • @bhargabborah4194
    @bhargabborah4194 3 ปีที่แล้ว +1

    thank u so much

  • @thefuckdidyousaytomelittle7580
    @thefuckdidyousaytomelittle7580 4 ปีที่แล้ว +1

    Clear explanation

    • @eng1048
      @eng1048  4 ปีที่แล้ว +1

      Appreciate it!

  • @rayd5173
    @rayd5173 2 ปีที่แล้ว

    Thanks it is well Explained

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      You are welcome

  • @titanblazer9112
    @titanblazer9112 ปีที่แล้ว +1

    u r hero

  • @brentlackey8316
    @brentlackey8316 2 ปีที่แล้ว

    The resultant truly does have components

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      give a timestamp my guy, idk what ur talking about

  • @devesh5739
    @devesh5739 2 ปีที่แล้ว +1

    Thank you sir

  • @billyandmandy286
    @billyandmandy286 4 ปีที่แล้ว +1

    yes yes yes el jef the machine

  • @swaroopdewal4626
    @swaroopdewal4626 3 ปีที่แล้ว

    You have student from India. Awesome explanation 💙

    • @eng1048
      @eng1048  3 ปีที่แล้ว +1

      Thank you!

  • @drlx8708
    @drlx8708 2 ปีที่แล้ว +1

    Great

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      Thanks :)

  • @yourlifementor9869
    @yourlifementor9869 2 ปีที่แล้ว

    Thank You

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      You're welcome. can i get some advice life mentor?

    • @yourlifementor9869
      @yourlifementor9869 2 ปีที่แล้ว

      @@eng1048 Keep uploading this type of content 👏 👌.

  • @duckie9923
    @duckie9923 3 ปีที่แล้ว

    THANK U!

  • @raghavkumar4914
    @raghavkumar4914 ปีที่แล้ว

    Helpfull for jee exam thx

  • @nf_mendoza9767
    @nf_mendoza9767 10 หลายเดือนก่อน

    Might just need a little more videos for TH-cam to recommend your channel 😮

  • @kawambwadaniel-kd3685
    @kawambwadaniel-kd3685 ปีที่แล้ว

    Does each instant in the motion of the particle have its own unit vector?

    • @eng1048
      @eng1048  ปีที่แล้ว

      It's more like this:
      For each instant of motion, the particle has the tranverse and radial unit vector, whose magnitude is a constant of 1, but whose direction changes

  • @tauseefshaikh7331
    @tauseefshaikh7331 3 ปีที่แล้ว +1

    At last....
    Thanks pal

    • @eng1048
      @eng1048  3 ปีที่แล้ว

      Thanks for the thank-you!

  • @sophialindsay6253
    @sophialindsay6253 4 ปีที่แล้ว

    Thank you!!!

    • @eng1048
      @eng1048  4 ปีที่แล้ว

      I am glad it helped!

  • @Megha-rv2hd
    @Megha-rv2hd 3 ปีที่แล้ว

    Is engineering and bsc both are same thing.🤔🤔🤔🤔

  • @coolbits2235
    @coolbits2235 2 หลายเดือนก่อน

    Thumbs up if you are watching this to understand orbital mechanics

  • @only_one_edgy614
    @only_one_edgy614 3 ปีที่แล้ว

    how u are getting the positive and negative ...thank you

    • @eng1048
      @eng1048  3 ปีที่แล้ว

      hello Rafi, please give time stamp

  • @Im_sonu0x
    @Im_sonu0x 4 หลายเดือนก่อน

    Thank u sir for clear explanation but mixup hindi please sir

  • @abdullahjan861
    @abdullahjan861 4 ปีที่แล้ว

    Good vedio sir.

    • @eng1048
      @eng1048  4 ปีที่แล้ว

      No problem, thanks for your comment!

  • @brentlackey8316
    @brentlackey8316 2 ปีที่แล้ว

    Not a satelite

    • @eng1048
      @eng1048  2 ปีที่แล้ว

      Hi, did you see my answer to your other question? :)

  • @successsteps1117
    @successsteps1117 3 ปีที่แล้ว

    🙂

  • @brentlackey8316
    @brentlackey8316 2 ปีที่แล้ว

    -7:38 True velocity? You must be an EE, I don't think that the Magnitude of the velocity is called the true velocity. It is not like electricy where you have true power. All part of the velocity vector are real. If you were standing next to this particle it would push you sideways. It you were above it. It would push you up. It's all real.

    • @eng1048
      @eng1048  2 ปีที่แล้ว +1

      The only real thing is the true velocity vector. It's another word for magnitude of the velocity. I like using the word true velocity because magnitude is used all the time by textbooks and professors. I like using different words to describe the same concepts to lend additional perspective.
      Here's what I mean. In the above video, I'm telling how we can take a velocity and split it up into transverse and radial components. Well, we could take that same velocity vector and split it up into x and y components couldn't we? We make the choice of what style components based on what situation we are in. If we were calculating what motor we need, radial/transverse is the way to go (because a radial/transverse approach gets us angular speed). If we were maybe trying to calculate the total distance travelled by a particle , x/y might be the way to go.
      So for this reason, the choice of components to use is subjective, it depends on the context. See what I mean? I try to remind students that the only REAL, TRUE thing that's going on is that you have a velocity vector.
      I think I see where you're coming from but hopefully I've illuminated why wording choice here :)

  • @fortrixtr
    @fortrixtr 6 หลายเดือนก่อน

    😢😢

    • @eng1048
      @eng1048  4 หลายเดือนก่อน

      You have problem?

  • @yesithwaduge4593
    @yesithwaduge4593 3 ปีที่แล้ว +1

    Thank you! ❤️❤️

    • @eng1048
      @eng1048  3 ปีที่แล้ว

      welcome :)

  • @fredmwanainchi6295
    @fredmwanainchi6295 3 ปีที่แล้ว +1

    Thank You!

    • @eng1048
      @eng1048  3 ปีที่แล้ว

      you're welcome!