Managed it in 33 minutes! I love puzzles like this where you have to figure out a few meta characteristics in order to be able to solve it, rather than just working on extending the regions little by little.
I think when Simon counted the factors he missed the point that you can't put the region size on an arrow. If you put x on an arrow it sees x cells plus itself making it a x+1 size region, which would have removed all degrees of freedom Edit: he sees it a few minutes later, saved lol
I love the pencil puzzles and hope you continue to do them. I think you got lucky with one correct but not fully supported deduction. At 47:35 you said R7C5 had to be red because you can't have another size 1 region. However, I believe it could still be the final green cell. It turns out to be correct though, and you can determine that as follows. If you did put green in that cell, youd have to complete red using R6C4. Then you'd need to finish purple with another cell, which ends up leaving an empty space with six cells and only a one arrow. The only way that space could be filled at that point is with a 5 and 1 region, which have already been used. So that rules out R7C5 as green. So your deduction to fill it red was correct, but I think it requires the above logic to rule out green first. Love the videos. You guys are my favorite TH-cam channel these days!
I really enjoyed solving that. 10-15 minutes in, after working out the key points (consecutive arrows having to be in the same region; needing to use all 23 possible factors; diagonal arrows having to be 3 or less), I started to intuit a solution. I initially thought "no I can't guess, I have to prove it". Then I thought "ah forget that, it's not a Sudoku puzzle". It was fun solving a puzzle in a completely different way.
10:33 for me! - I feel like joining up all of the arrow cells with at least the first cell it can see in the direction of the arrow would've made it a lot more visually obvious how restricted/forced a lot of the regions/arrow sizes were.
A bit quick there at 47:37 as that cell could be green, There is probably a counting argument or something to resolve that if one wants to. It is resolved by the size 7 region, as that wuold be 6.
I have never been so lost. 41:40 Like, how do you know there has to be a three in the 12 region when the rules say a region can have any combination of its factors "including none of them"?
Managed it in 33 minutes! I love puzzles like this where you have to figure out a few meta characteristics in order to be able to solve it, rather than just working on extending the regions little by little.
Lizzy01 is a great setter and I am glad to see another feature.
Of all of the references to make, Me Julie didn’t make my list of predictions 😂
Made my day 😂
I think when Simon counted the factors he missed the point that you can't put the region size on an arrow. If you put x on an arrow it sees x cells plus itself making it a x+1 size region, which would have removed all degrees of freedom
Edit: he sees it a few minutes later, saved lol
I love the pencil puzzles and hope you continue to do them.
I think you got lucky with one correct but not fully supported deduction. At 47:35 you said R7C5 had to be red because you can't have another size 1 region. However, I believe it could still be the final green cell.
It turns out to be correct though, and you can determine that as follows. If you did put green in that cell, youd have to complete red using R6C4. Then you'd need to finish purple with another cell, which ends up leaving an empty space with six cells and only a one arrow. The only way that space could be filled at that point is with a 5 and 1 region, which have already been used. So that rules out R7C5 as green. So your deduction to fill it red was correct, but I think it requires the above logic to rule out green first.
Love the videos. You guys are my favorite TH-cam channel these days!
also blue can't be 4 or 8 so must be 3 meaning green must take the cell in the last column.
When do we get our "I'm one of Simon's favorite people/ I know the secret" t-shirts?
I enjoy this series of non sudoku puzzles. Variety keeps things fresh! Keep them coming.
I really enjoyed solving that. 10-15 minutes in, after working out the key points (consecutive arrows having to be in the same region; needing to use all 23 possible factors; diagonal arrows having to be 3 or less), I started to intuit a solution. I initially thought "no I can't guess, I have to prove it". Then I thought "ah forget that, it's not a Sudoku puzzle". It was fun solving a puzzle in a completely different way.
Does region imply that it is orthotogonally connected?
Came here to find this out.
Loving this Saturday series!! Beauty of a puzzle from Lizzy01!!
I don't solve these Saturday features but I do enjoy the change from sudoku.
I like the SuDON'Tku Saturday puzzles.
How do we know the regions have to be connected, let alone orthogonally connected?
Great puzzle, and in all the places to hear an Ali G reference in 2024, I wasn't counting on it being on Cracking the Cryptic.
triangular # for 12 = 12x13/2 Simon n(n+1)/2
Mark presented a double diagonal sudoku yesterday. Anyone knows minimum of clues in these puzzles?
Is the winner of the competition announced somewhere? Have not seen that for the last one.
The triangular number for 12 is indeed 78- as known to all accountants.
10:33 for me! - I feel like joining up all of the arrow cells with at least the first cell it can see in the direction of the arrow would've made it a lot more visually obvious how restricted/forced a lot of the regions/arrow sizes were.
Made you look, and made you see?
... not the best Del Boy impression I've ever heard, Simon ...
LETSGOOO ANOTHER ONEEE DAY:9
E
I do NOT enjoy this non sudoku series on Saturday.
A bit quick there at 47:37 as that cell could be green, There is probably a counting argument or something to resolve that if one wants to. It is resolved by the size 7 region, as that wuold be 6.
I have never been so lost. 41:40 Like, how do you know there has to be a three in the 12 region when the rules say a region can have any combination of its factors "including none of them"?
47:34 Why can't that one be Light Green?
I think needing the 7 to be size 7 justifies it but if you knew that you certainly didn't communicate it
14:40 uh... what? None of that makes any sense to me...