Because jitta charge hone mei time lga utta hi discharge hone ke liye chahiye . So if it would have been T to 3T then it would have achieved 5V or more than that. But in T to 2T it would achieve 0V only.
How will Vc rise from 5 to 5.5 exponentially? Because already they are at steady state , So due to the 1v battery the node will go to 0.5V and Vc will instantaneously be 5.5 na?
Becoz the current going through the resistor is non zero finite current and It is not Inifinitely increasing, if it would have been the case then the time constant would have been Infinite, Draw the equivalent circuit after tnot, you will see there is a time constant which if finite so it will rise Exponentially.
4:45 2/R current will flow through the capacitor.
Very good question 👏 nice concepts you explained it very nicely
In the interval from T to 2T, why should Vo stop at 0V and not go to +5 V ?
Because jitta charge hone mei time lga utta hi discharge hone ke liye chahiye . So if it would have been T to 3T then it would have achieved 5V or more than that. But in T to 2T it would achieve 0V only.
In second cycle from T to 2T the output can go to +5 right..? and -5.5 for Vc
It should go to 0V only I think. For +5V the current has to be on for longer time in neg cycle(more than 2T)
How will Vc rise from 5 to 5.5 exponentially? Because already they are at steady state , So due to the 1v battery the node will go to 0.5V and Vc will instantaneously be 5.5 na?
@Ebadur Rahman Khan Yup. correct.
Becoz the current going through the resistor is non zero finite current and It is not Inifinitely increasing, if it would have been the case then the time constant would have been Infinite, Draw the equivalent circuit after tnot, you will see there is a time constant which if finite so it will rise Exponentially.
sir please make some videos on BJT practice questions
Please watch Analog Question series
Time wise , how do you know Vc is 5 volts before time T , why can’t it take T time period to reach to 5 V why it is before time T?
Nice video
I think it’s because we assumed fast charging may be
Yup. We just assumed the fast charging. The interviewer himself will tell you that it would reach the steady state before applying -1 voltage
Sir, when texxas will out results
FIT TI? No idea
Thankyou+