Great teaching sir. I am your student from adgitm, you taught me emft in 2nd year. I really enjoy watching these lessons, they are simple to understand. Thank you for your effort.
thank u for this helpful teaching sir......its better if you would solve more examples...... the assignment answer is mentioned below. a. L=1024 b. step size= 0.0029296875 c. Xq = 1.201171875 d. Eq= 0.001171875 e. dynamic range= 60.2 f. SNR = 61.96
Thank you so much sir for your all effective lectures it really helped us a lot . Sir actually we preparing for ugc net which is about to be held in june 2019 so sir can u pls send us notes of digital and analog communication it will be very kind of u thank u
Thank u so much sir,for such a nice lecture ...it really helped us a lot.....pls sir provide us the notes of analog and digital communication....as it will be very heplful for us while preparing for ucg net exam...
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Sir, there is a formula of quantization error which is del^2/12. del being step size . Why cant we use that here ... if we use that , the answer is not mathing with the answer of quantization erroe provided here...
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Great teaching sir. I am your student from adgitm, you taught me emft in 2nd year.
I really enjoy watching these lessons, they are simple to understand.
Thank you for your effort.
a) L=1024
b) stepsize=0.0029296875
c) Xq=1.201171875
d) e=0.00171875
e) dynamic range=60.2db
f) SNR=61.96db
dynamic and snr are Wrong
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I compair my ans to other comment ans and it is right 😅, thank you 😊
Power of students
thank u for this helpful teaching sir......its better if you would solve more examples......
the assignment answer is mentioned below.
a. L=1024
b. step size= 0.0029296875
c. Xq = 1.201171875
d. Eq= 0.001171875
e. dynamic range= 60.2
f. SNR = 61.96
L-1025
∆-0.0029296875
I-410
Xq- 1.201171875
Eq-0.001171875
Dynamic range-60.2
Snr-61.96
your welcome
Thank you so much sir for your all effective lectures it really helped us a lot . Sir actually we preparing for ugc net which is about to be held in june 2019 so sir can u pls send us notes of digital and analog communication it will be very kind of u thank u
a. L=1024
b. STEP SIZE=0.00293
c. Xq=1.2000108
d. e=0.0000108
e. DYNAMIC RANGE=60.2 dB
f. SNR=61.96 dB
Sir please upload random variables and random processes in detail. Thank you sir
Thank u so much sir,for such a nice lecture ...it really helped us a lot.....pls sir provide us the notes of analog and digital communication....as it will be very heplful for us while preparing for ucg net exam...
tnx sir
Your Appreciations, care and share matters a lot to me. #EnginneringLove.
Let me give the details of few exciting features of Engineering Funda:
1. A link to more than 30 Courses is given in the Comment Section.
2. Detailed Syllabus of the subject along with chapters is given in the description of videos.
я безумно тебе благодарен индус
thank you sir
It is great lecture can you show us how to compute the binary codded value that ADC generates
a) L = 1024
b) Delta = 0.0029296
c) Xq = 1.2011718
d) Eq = Xq - X = 0.0011718
e) Dynamic Range = 60.2
f) SNR = 61.96
Thanks and welcome
Thank you sir 😊
Most welcome
Sir, there is a formula of quantization error which is del^2/12. del being step size . Why cant we use that here ... if we use that , the answer is not mathing with the answer of quantization erroe provided here...
Quantization Noise=(del^2)/12
You are saying about Mean square quantization error.
Video tells about Quantization error
where does the 6.02 for dynamic range (and SNR) come from?
Don't skip any lectures ⚠
6.02 comes from the 20log10(2^bit). n = bit and 20log10(2) = 6.02
@@umangverma3660 nobody don't have to follow anything.
thank you saar
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
Sir good evening
I want to ask if impulse response of matched filter and transfer function of matched filter is same thing
a. 1024
b. 0.00292968
c.1.2011688
d.0.0011688
e. 60.2
f. 61.96
sir please make video on delta modulation
I will complete that for sure and you will get complete digital communication here.
@@EngineeringFunda thank you sir
Sir please upload these notes on your website
Please sir to calculate the number of quantization level of 416
416 requires 9 bits
bro you don't say one point seventy six its one point seven six
Yeah
Thank you sir 🙏
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