#bayeinhaathkakhel and then uses her left hand...sense of humour along with superrrrrr intelligence...hats off!!!!!!Excellent videos(each and every one)...😲😲😍👏👏👏
I was just looking for it so long.... Thank you mam ...and the final answer is 6th term. And mam impressively you write with your both hands ..amazing and super
Now I feel like I am confident for JEE Mains April, Thank You very much mam for your tricks, These are really time efficient and are perfect for competitive exams like JEE. Please keep making these videos with awesome short and simple tricks as these are really helpful for JEE aspirants.
Can't express my gratitude towards you with the combination of 26 alphabets....BTW answer of the question is sixth term....Thanks from the core of my heart 🥰🥰😍😍😇😇🙏🏻🙏🏻🙏🏻🙏🏻
Mam please do a favor for always that please mention in the starting the serial number of the video in the playlist because sometimes it's difficult to find out the serial wise videos of the playlist...
if the value of r come in decimal form then what we do.... plzzz expain.... question is (2x^2 -1/x)^10 how we find the value of r bcoz if we use your mathod then the answer is 6.6🤔🤔🤔🤔
Hlo beautiful mam.. I'm your die hard fan.. love you so much 💐💐.. teaching is bhil khul amazing .... DIY Ans is r=5 and T 6 th term is independent term ... Bingo..😍😍😘
#bayeinhaathkakhel and then uses her left hand...sense of humour along with superrrrrr intelligence...hats off!!!!!!Excellent videos(each and every one)...😲😲😍👏👏👏
T 6 term is independent of x
Very fine
7
Sixth term mam
2:16 she's a superhuman
She is the next Shakuntala Devi...Amazing tricks..in love with maths now😍😍
T6 is the answer, its super easy.
YES
BUT TAKEN TOOOOOOOO LONG TO SOLVE😂😂😂😂
It's that fast you wanna know how let the magic begin
mine also
Ya
Yes buddy
We can solve now questions with tricks
The correct answer is '6'
Nice teaching mam
I'm really excited ,after getting answers in seconds...... 🌹🌹
Brilliant way of explanation especially in 1.25× 😅
AWESOME MAM ! loving your videos
ALSO IN 2x
What is meant by term independent of x?
@@nerengen0054 constant term I guess
For me 1.5 😂😂
@@nerengen0054that doesn't have x
I am able to do even hard questions of my book just because of you and your tricks mam....
You are awesome like your trick mam. 👍😎
Thanks alot...😄
Gobar kha lio
Mam thanks from bottom of the heart for quenching our thirst of mathematics Please continue making these videos we will support your channel a lot
Ma'am you are just AMAZING!!!😊😊
Answer : 6 th term.
Right answer
How man
@@snehlatakarn4418 (8x1/3) / (1/5 + 1/3) ....after simplifying you will get r = 5...so, 6th term is the term independent of x.
uh are a perfect teacher......i have ever seen....uh made all of my problems so easy...😊😊.....
4
last minute prepration made easy
thanks for the efforts that you are putting in.
world needs ppl like u
solve {x4 +x(-3)}15 find r . 4 and -3 are power of x . and 15 is whole power
Y trick work nhi karti
MOstly in NDA quetions
r=p
r=1 Σ nCr = ???, Where p
I was just looking for it so long....
Thank you mam ...and the final answer is 6th term.
And mam impressively you write with your both hands ..amazing and super
nC1+nC2+nC3+....... +nCr=??? , where r
Ans for DIY is T6 thanks love you 😍😘
Thanku so much ma'am....
May your channel gets 10 million subscribers as soon as possible
6 term is ans aap ham logo ke liye best,supper,👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌hamesa rahengi,thanks a lot of
I always rise a smile whenever i see your videos of my maths search in TH-cam
6th term is independent of x...
Thank u so much ma'am
U can be a JEE advanced mentor...
bruh kya kar rahe ab? job lag gayi?
Nhi yr
When she says " ye to mere baaya haath ka khel he " she actually means it
Now I feel like I am confident for JEE Mains April, Thank You very much mam for your tricks, These are really time efficient and are perfect for competitive exams like JEE. Please keep making these videos with awesome short and simple tricks as these are really helpful for JEE aspirants.
Bro is this series sufficient for jee
How did it go,and what you are doing rn?
how'd it go?
Mam I am poor in maths but these videos of you..making me queen...this is only because of you...😍😍😍
Ma’am your videos and tricks are great 😃. Please from your next video also explain why your tricks work that will help make the concept more clear 🙏
My first video on your channel... Great help in these lockdown
Answer for DIY is T6
Rong t5
@@aimeepulongbarit9025 r= 5 but T(r+1) is the term that we need, thus the answer will be 6th term only.
Right
Your so intelligent mam ajj mera math ka exam hai thankuu so much for clear this topic 😍😍😊😊👍👍👌👌👌👏👏👏✌✌✌
mam pls tell the trick of ...how to find 5 term, 6term or any in the expansion
msm pls help
Mam your voice is so sharp and nice voice to explain we thank you!
How to find independent terms in multinomial expansion miss
mam please tell how will we find the term independent of x in (1+x)^m * (1+1/x)^n
Mam, any amount of thanks would be insufficient for you! Hats off to you for bringing maths to its knees!
The derivation of this trick was easy but could please add those aswell in your videos so that we could know WHY that trick came?
Answer of this question is 6..i.e .sixth term is independent of x
Ma'am I found T6
I am really thankful to you 🙏
Your are outstanding 👏😍
MAM PLSE UPLOAD FULL VIDEO ON CONCEPT OF BINOMIAL THEOREM PLSE
Mam donot know
Mam solves this ?
[√x/3+3/2x^2]^10
Under root x/3 par hi hai
a. 5/4
b. 7/4
c. 9/4
d. 45
answer 2
Good concept..But, first just introduce about what is independent of x,for better understand
Madam please what does the T stand for
T6th....
Mam plz discuss problem of maths jee question...
In tricks form before 8th april.....🙏🙏🙏🙏🙏
Mam in first question independent term is 4th term
KOMARA CHANDRA its fifth term lol
It's the T(r+1)th term
R=4
Then the independent term is just the next term
Therfore the 5th term
Ur short methods r awesome
Plz tell me a book with all these shortcuts...
Neha mam: ye to mere bayein haath ka khel hai
* Literally does the sum with the left hand *
Hmm that's clever
Mam , if (2x - 1/3x) ^ 11 .. Then what will b (r+1)th ???
What if (x+1/x)^3
My r=3/2
The term independent of x in the binomial expansion of (2/x^2-sqrtx)^10 is equal to. Mam please tell me how to do this
Did anyone noticed ??? She used to write with both of her hand !!!!!
T6
Writing with both hands woww... She developed both parts of brain (iq level 100)👍
please provide more such tricks for JEE
Ashutosh Mishra yes...
I also need...😢🙏🙏🙏🙏
Mam the ques type is (1/60-x^8/81)(2x^2-3/x^2) then how to solve by your trick...
Ma'am , the answer for the DIY is : *6th term*
Hope i'm correct
Thnx a lot ma'am
Q. Find the term independent of x in the expansion of (x-3/x^2)^8.
Plzzzz answer mam...
Aap ab tk kaha thi ma'am 🔥
Mam u r super
Filled my mind with tricks
😀
Mam the ans for DIY IS T6
6 th term mam thankxxx
Yes 6th term!
T6 is the answer
Very easy and quick trick
Thanks mam 😊
6th term
Answer of DIY is T6
Very helpful video. Thank you so much ma'am.
Can't express my gratitude towards you with the combination of 26 alphabets....BTW answer of the question is sixth term....Thanks from the core of my heart 🥰🥰😍😍😇😇🙏🏻🙏🏻🙏🏻🙏🏻
May God bless You Mam ❤
Thnku ma'am u should be my maths tecaher in school 💗
T6 is the answer for the D.I.Y. question.
And thanks a lot for giving us so many amazing tricks
How
Neha ma'am you are rocking.
This is supercool trick just like you.
T6 is the answer of your diy....
Thanks mam for this amazing tricks...
Mam again and again ur impressing me by ur teaching skill
Ans is T6=T5+1
Mam, I love ur style of teaching. The DIY answer is T6. Love u mam
Wow it is very easy
Thanks you teacher....
Im from sri lanka
Well explained
Mam answer of DIY question that isT6 thank you for this amazing and awesome .
You r super great mam....from where u get these superb ideas😎😎😎😎
r = np/(p-q) for q if taken in numerator
Mam can you suggest for the vslue of n where n is odd
Mam please, how we find the🙏🏻indepedent term (x+1/x^2)^n
Sister it was a great tric but how can we find the independent term for ( 1+x)^2 (1+1÷x)^10 could you please tell me
P=0 anyways the first term is independent of x in (1+x)^n
T6 is answer of. Last question thankyou mam for this. Super trick
Thank u mam for the super amazing trick.
I am from class 8th but I am preparing for PRMO. The amswer to the HW is 6th term.
OMG 😳😳❤️ thankuuuu soooooo much... amazing
Mam please do a favor for always that please mention in the starting the serial number of the video in the playlist because sometimes it's difficult to find out the serial wise videos of the playlist...
if the value of r come in decimal form then what we do.... plzzz expain.... question is (2x^2 -1/x)^10 how we find the value of r bcoz if we use your mathod then the answer is 6.6🤔🤔🤔🤔
T6 is the answer mam. I have almost watched all your short trick videos u are really amazing mam. Thanks for making such videos.
Is it only for the coefficients of "x" or for all "x to be raised power"????
Love ur teaching mam 😘😘
Thank you mam please upload more video ........👏👏👏👏👏👏
Mam can you write in two hands simultaneously
Mam what if (x^2+c/x)^5 how we use the method
Atc k liye pdha de mam. Plz
Superb Trick Madam Ans For Diy Is 6th Term.
God bless you mam!
Mam is there any trick to find independent term if two binonomial terms are in multiplication
Hlo beautiful mam.. I'm your die hard fan.. love you so much 💐💐.. teaching is bhil khul amazing .... DIY Ans is r=5 and T 6 th term is independent term ... Bingo..😍😍😘
The answer to the given DIY is T6th term is independent of x. Thanks
If the power pf x is negative will the formula work??
hello mam what if we get r value in fractions eg: r=9/4??
I am impressed by your talent
Nice tricks and very helpful for defence exam, thank you mam
Man I like your concept,tricks,and explanations.
Man pls arrange your videos by chapter wise man.
Excellent teaching skills mam your wonderful😍😍👌👍❤️👌
Mam plz post a video on remainder theorem in BINOMIAL
It's is helpful NDA preparation.....
Mam what if answer comes in fraction
Answer to the DIY is T6..Thanks ma'm for this trick..
mam ...i have a question ....number of terms in the expansion of (x+a) to the power -3
mam mains question 2013 ese type ka he es method se solve karke bataye