Sir for PP-1 13:58 idk I'm getting none of the options as the answer 😅 I'm getting (e/2R).exp(-4Rt/5L) As fluxes are aiding both of the emfs (self and mut) will be of same sign so Leq=5L/2 and Req=2 so Tau=5L/4R And for finding initial current , equating total flux so Lio+L/4.0+L.0+L/4.io=2(L+L/4)i , so i=io/2 .. am i correct sir ?
@@PHYSICSSIRJEE If I don't consider Lio/4 initially in the second inductance then answer is matching as D .. but wouldn't it be wrong as initially some flux is there in the second inductance ?
Sir please dont leave the channel ♡ We know its hectic for you as advanced is getting near. We do share it to our friends but they dont follow videos regularly 😔
i sincerely hope that a gifted person as yourself will aid us throughout our journey and i hope you will be there to support us when we find mistakes in jee adv 2021
sir 55 is correct since...if we see in the left loop from down side it first goes to right side...where as if we observer the left loop from down side it goes to right side this shows the winding is in opposite sense...and since the current direction is also opposite so effectively it aids and 55 is correct 10:29
finest explanation ever to this question...love how you've broken it down into simple parts. I definitely understand creating such content for free requires a lot of motivation. I urge everyone to share and like this so we can get more and more and moree.........thank you very much for this sir.
Relieved to see your video...what does your community post mean sir? Please don't leave us sir...we will do best to boost your channel...likes have been increasing on your past few videos and it will continue to grow...thanks sir for all the content ure providing us for free...
Sir main problems for the channel growths that students don't share channel with advanced content because they think that competition will increase...same with mohit tyagi sir...
It's not like that...it's just dat rarely some students only appreciate advanced content..that's why reach is low..students are mainly satisfied with board/mains level
14:18 Sir is the ans D? . Before switching Initial flux is Le/R. If i take Leq then since after switching current through circuit will be same and since the inductors aid each other Leqdi/dt=(Ldi/dt +Mdi/dt +Ldi/dt+Mdi/dt) so Leq= 5L/2. Then conserving flux for the circuit at t=0 initial current will be 2/5e/R and tau will be Leq/2R so 5L/4R
Sir you assume one coiling for an inductor, and then rotate the diagram and apply the same coiling for the other inductor too, you will see that they are aiding only,
Sir after jee advanced I will surely work towards promoting your channel. It is something different from the other channels, I have already told my friends about this channel who are going to give advanced this year, please sir don't feel demotivated.
For 14:31 sir is it b) √L1/L2 ? I just wrote the eqns by Kirchoff's law and then eliminated di2/dt, then coeff of di1/dt became 0(as ideal L1L2-M²=0) . After that i arrived at this ratio
@@PHYSICSSIRJEE Good evening sir I tried solving 14:31 got it using the transformer theory but I am unable to proceed using Kirchoff's laws. I have gotten stuck after V1/V2=[L1(dI1/dt) + M(dI2/dt)] / [L2(dI2/dt)+MdI1/dt]
Sir I think the key is right ...Atleast what I have been taught is that inductor opposes changing current so the EMF induced would be opposite to direction of battery already present in the circuit and if you think like that it is aiding type of circuit and hence the answer is correct
Sorry sir I think I made the wording wrong... What I meant is that simple inductor tries to oppose the current so it will induce EMF in direction opposite to the battery [not including mutual inductance] and hence the magnetic field produced will be in anticlockwise direction similarly 2nd inductor will oppose the battery and EMF induced[not including mutual inductance] will again give anticlockwise field...And they are additive. Sir please correct If I am still getting something wrong....
Sir there is not much difference even if we dont zoom , it clearly appears that they are opposing each other and 35 joule would have been the only correct answer .
Sir.. U along with only a few educators have the notion that jee advanced content can be accessed by everyone... U are the only hope for me... U are in complete contrast with those teachers who think that only 99+ jee main percentilers have a chance in jee adv😏 Respect🙏🙏
Bhai tu RKH Sir ki baat kar raha lagta hai............baat maan woh bhi insaan bure nhin hain. Par unhe koi bar toh lagana padega naa ki kaun include hoga aur kaun nhin
I don't understand how you concluded direction of turn of helix after zooming in. It is actually impossible to find it out from a 2 dimensional diagram.
@@PHYSICSSIRJEE Right, so another question in JEE 2020 was actually wrong. Probably the most controversial JEE ever. I really like your content. Physics teacher myself.
aren't you supposed to wrap the wire in one direction only for it to behave like an inductor suppose take a wire and wrap it around a in clockwise direction and it bahaves as an inductor due to increase in magnetice field and and due to lens law emf iis induced so as to reduce it now if we take the same wire and start wrapping it in anti clockwise the magnetic field will beinncreasing in opposite direction so by lenz law the emf induced will further increase current ? i am confused
yes but the direction in which you have to wrap is not clear, as when u look at it slightly different then u see unaiding. Once you see it , u can't unsee it
If we consider the windings of both inductors as same. In one, current in going upwards whereas in other it's going downwards.Magnetic field inside both of the inductors will be in opposite direction. There will be aiding. Am I right?
Sir when i tried to use curl rule , i saw that both are opposing each other but the direction of fields in both the coils was opposite of what u have depicted , is it some mistake i am doing , please clarify , also sir are we supposed to take negative of what we get in answer as direction of magnetic field or simple positive like i have done , as the formula is -Ldi/dt , so i was having trouble in sign convention
sir should we consider the flux associated between inductors due to mutual inductance or not.If we consider it then none of the option is matching and if dont then option d.simply written the flux associated with inductor in intial and final case and then equated it and then decayed the current as no power source is present.(14:15)
Sir when i solved the question i thought be positive and took M to be positive and got ans as 55 😂😂. Fortunately IIT gave ans as 55. Hence proved, we should stay positive. 😂😂
Sir i do share your videos everyday to my friends but they neither appreciate the effort nor follow it regularly. Sir u can reduce the frequency of videos and Create a mega video as per your schedule allows. 🙏🏻🙏🏻
Sir this hunger for likes won't get u anywhere This was said by a student on Nitin sirs channel and he was roasted badly by 30 students in the reply to his comment
Its totally an illusion..we can see both ways of the winding i think..nonsense by jee just give both keys as answer, ruined future of so many students for sure
Sir for PP-1 13:58 idk I'm getting none of the options as the answer 😅 I'm getting (e/2R).exp(-4Rt/5L)
As fluxes are aiding both of the emfs (self and mut) will be of same sign so Leq=5L/2 and Req=2 so Tau=5L/4R
And for finding initial current , equating total flux so Lio+L/4.0+L.0+L/4.io=2(L+L/4)i , so i=io/2 .. am i correct sir ?
Tau part is correct 👍🏼
Then sir can u give a hint to find initial current ?
@@PHYSICSSIRJEE If I don't consider Lio/4 initially in the second inductance then answer is matching as D .. but wouldn't it be wrong as initially some flux is there in the second inductance ?
Lio/4 because flux from the first inductance would pass through the second one right ? And equal to M.I ?
@@amiyancandol4499 perfect ,👍🏼 , 🙂 I misread your equation.
Sir please dont leave the channel ♡
We know its hectic for you as advanced is getting near.
We do share it to our friends but they dont follow videos regularly 😔
i sincerely hope that a gifted person as yourself will aid us throughout our journey and i hope you will be there to support us when we find mistakes in jee adv 2021
I always wondered about sign in this but I was not not taught of sign in mutual inductance. Tysm
sir 55 is correct since...if we see in the left loop from down side it first goes to right side...where as if we observer the left loop from down side it goes to right side this shows the winding is in opposite sense...and since the current direction is also opposite so effectively it aids and 55 is correct
10:29
Sir please don't leave the channel. We can't lose a legend of physics plzzz 😢😢😭😭🙏🙏
Glad to see the video, please don't leave🙏
14:41, PP-2: ans is B, it doesn't matter if both inductors support or oppose each other as the terms get cancelled
finest explanation ever to this question...love how you've broken it down into simple parts. I definitely understand creating such content for free requires a lot of motivation. I urge everyone to share and like this so we can get more and more and moree.........thank you very much for this sir.
Very true indeed
This is really nostalgic LOL, I'm in college ab but still watching your video just for the memory!!!
This is my favourite channel on youTube 🤩...
Actually I'm engineering we use dot notation , for sign😊 ..
Taught by only few teachers😊
There can be either right side helix or left side helix
Taught by ambarish sir
Relieved to see your video...what does your community post mean sir? Please don't leave us sir...we will do best to boost your channel...likes have been increasing on your past few videos and it will continue to grow...thanks sir for all the content ure providing us for free...
14:00 I am getting i= (E/2R)×e^-4Rt/5L so answer should be E option.
and
15:08 B option
Why e/2R
Feeling so motivated
I couldn't even attempt this question out of fear in exam but I solved it in minutes today with same dilemma of ± signs
14:04 - D)
14:44 - B)
It makes me more prepare for these challenges thanks sir nice explain ❤
Sir you are just amazing :)
Sir main problems for the channel growths that students don't share channel with advanced content because they think that competition will increase...same with mohit tyagi sir...
It's not like that...it's just dat rarely some students only appreciate advanced content..that's why reach is low..students are mainly satisfied with board/mains level
@@yatharthgupta6468 yes that may be one reason...Also students mostly attractive towards theory oriented channel...
@shivansh mishra true
@@yatharthgupta6468 yes I tried to share this channel but nobody shows intrest.
aisa nahi hai ..max to max this content will appeal to 5-6 k students so there is upper limit for this advanced content
thanks sir!
answers to practice problems-
1) 13:58 option E
2) 14:47 option B
how is your answer for second question B please tell broo
14:18 Sir is the ans D? . Before switching Initial flux is Le/R. If i take Leq then since after switching current through circuit will be same and since the inductors aid each other Leqdi/dt=(Ldi/dt +Mdi/dt +Ldi/dt+Mdi/dt) so Leq= 5L/2. Then conserving flux for the circuit at t=0 initial current will be 2/5e/R and tau will be Leq/2R so 5L/4R
Any justification for leaving out the initial flux of the right side ( zero current ) inductor due to M
14:02 Option D and 14:52 Option B ?
This channel will grow sir much much faster just keep doing this we will keep spreading this
14:00 (D)
14:31 (B)
Sir this video still helping us to understand the magnetic coupling (course name -Introduction to electric engineering) at IIT Delhi .
Thanks
Thank you for the kind words 🙂
@@PHYSICSSIRJEE ❣
Love from bottom of my heart
Sir you assume one coiling for an inductor, and then rotate the diagram and apply the same coiling for the other inductor too, you will see that they are aiding only,
Sir after jee advanced I will surely work towards promoting your channel. It is something different from the other channels, I have already told my friends about this channel who are going to give advanced this year, please sir don't feel demotivated.
16:39 ans is B
Sir is very good i too found but never had confidence that this question has ambiguity
Sir in 14:12 shouldn't be I max E/R
thanks sir alpha omega series is the best
all guns blazing jee 2022
Sir, so i guess this means that by default always we should consider aiding ?
U r a jewel sir..u will be recognized very soon ...I will help ur channel to grow within upcoming year's don't worry sir...
Sir plz make video on how to solve ques involving both self and mutual inductance I have not studied this concept plz
Congratulations sir...
Now we r 8k family...🎉🎉🥳🥳
14:31
Ans:B
14:56 My answer for Q. 23 is Option B
Sir why did u post close to full stop on community post... please sir don't leave TH-cam...😞😞
For 14:31 sir is it b) √L1/L2 ? I just wrote the eqns by Kirchoff's law and then eliminated di2/dt, then coeff of di1/dt became 0(as ideal L1L2-M²=0) . After that i arrived at this ratio
Another easier but less elegant way could be using the result Vp/Vs=Np/Ns from transformer theory , and L is prop to N² so becomes √L1/L2
👍🏼🙂
@@PHYSICSSIRJEE Good evening sir I tried solving 14:31 got it using the transformer theory but I
am unable to proceed using Kirchoff's laws. I have gotten stuck after
V1/V2=[L1(dI1/dt) + M(dI2/dt)] / [L2(dI2/dt)+MdI1/dt]
@@aayushsenapati5002 put I2 = 0
@@PHYSICSSIRJEE sir so this relation wont work in a real transformer? How can I2 be zero?
Sir I think the key is right ...Atleast what I have been taught is that inductor opposes changing current so the EMF induced would be opposite to direction of battery already present in the circuit and if you think like that it is aiding type of circuit and hence the answer is correct
Basic understanding of mutual induction is wrong in your comment . Please watch the video again ( especially zoomed part )
Sorry sir I think I made the wording wrong... What I meant is that simple inductor tries to oppose the current so it will induce EMF in direction opposite to the battery [not including mutual inductance] and hence the magnetic field produced will be in anticlockwise direction similarly 2nd inductor will oppose the battery and EMF induced[not including mutual inductance] will again give anticlockwise field...And they are additive.
Sir please correct If I am still getting something wrong....
Thank you sir 🙌🙌
yesterday i spent my whole day on this ...tried hard and finaly now : )
Did you get the ans?
OK
In my opinion JEE must have provided a Zoomed diagram also .
However since they didn't provide they must have given both 35 and 55 as answers
If zoomed diagram was provided , answer should be 35 as explained in the video
pp1 option D?
Sir there is not much difference even if we dont zoom , it clearly appears that they are opposing each other and 35 joule would have been the only correct answer .
Sir.. U along with only a few educators have the notion that jee advanced content can be accessed by everyone... U are the only hope for me...
U are in complete contrast with those teachers who think that only 99+ jee main percentilers have a chance in jee adv😏
Respect🙏🙏
Bhai tu RKH Sir ki baat kar raha lagta hai............baat maan woh bhi insaan bure nhin hain. Par unhe koi bar toh lagana padega naa ki kaun include hoga aur kaun nhin
there is a lot of truth in that lol
Ikr , I know somebody who got a 18k rank in mains and 1300s rank in adv(2016)
@@emmynoether2198 I've got 18k in mains 😂 😂
let's see how well i do in advanced 🌚
I don't understand how you concluded direction of turn of helix after zooming in. It is actually impossible to find it out from a 2 dimensional diagram.
Actually I assumed and not concluded from what I saw. It's actually difficult for students in the exam . That was my point too
@@PHYSICSSIRJEE Right, so another question in JEE 2020 was actually wrong. Probably the most controversial JEE ever.
I really like your content. Physics teacher myself.
thank you sir
aren't you supposed to wrap the wire in one direction only for it to behave like an inductor
suppose take a wire and wrap it around a in clockwise direction and it bahaves as an inductor due to increase in magnetice field and and due to lens law emf iis induced so as to reduce it
now if we take the same wire and start wrapping it in anti clockwise the magnetic field will beinncreasing in opposite direction so by lenz law the emf induced will further increase current ?
i am confused
yes but the direction in which you have to wrap is not clear, as when u look at it slightly different then u see unaiding.
Once you see it , u can't unsee it
for ques.n in 15:05 is the answer option b, kindly reply.
👍🏼
Continue uploading jee advanced pyq
If we consider the windings of both inductors as same. In one, current in going upwards whereas in other it's going downwards.Magnetic field inside both of the inductors will be in opposite direction.
There will be aiding.
Am I right?
You mean to say the right side diagram of 2:50 ?
Sir 14:37 d?
13:58 sir is the answer OPTION E??
Sir where do you teach phsics in jee coaching
Should have been 35 and 55
IITs are now messing up
13:58 D?
Please try again
Yes sir , read other comments and got my mistake 👍....i didn't take l/4io initially
But we need to prove that too . We have to see if D or E is the answer
Amazingly explained sir!🙌,are the ans
13:58 D
14:34 B?
how is your answer for second quesin B please tell
14:31 kirchoffs equation will help you out to B
Sor plz bring solution of jee adv paper 2 Qn 2 of train inside tunnel i have a difficulty in applying bernoulli equation
Why why question no 6 of paper 2 was deleted. What was wrong in it?? Pls reply
I will take it up if it's worth it 👍🏼
Sir please don't leave
Sir when i tried to use curl rule , i saw that both are opposing each other but the direction of fields in both the coils was opposite of what u have depicted , is it some mistake i am doing , please clarify , also sir are we supposed to take negative of what we get in answer as direction of magnetic field or simple positive like i have done , as the formula is -Ldi/dt , so i was having trouble in sign convention
sir, were students expected to see it so magnified that they are able to decide about aiding or opposing?
No , that was unfair to expect. It should have been a double key
Sir are you and Nitin sachan sir frnds
35 or 55 both :-(
sir should we consider the flux associated between inductors due to mutual inductance or not.If we consider it then none of the option is matching and if dont then option d.simply written the flux associated with inductor in intial and final case and then equated it and then decayed the current as no power source is present.(14:15)
None is correct 🙂
Ok sir.🙂
Sir these types of questions are never taught nor asked in any tests of coachings so how are we supposed to do these in exam
They might have asked this like" sum of possible values of work done by batteries against induced emf"
Can mutual inductance exist between an open and a closed circuit with inductors?
I get confuse what will happen if we change polarity of both circuits pls reply sir jee
Think in terms of the 'zoomed' diagram in the video
8k 🥳🤩
I can imagine inductor in 2 ways
Arey please don't worry, sir humare saath halka phulka mazzak kar rahe hein.😊😊😊😊
😻😻
🛐🛐🛐
Sir my suggestion is to start teaching theory... because students mainly like theory oriented channel
the views might be less due to upcoming mains i think
👍
Advance people whenever try to go higher they make mistakes
Sir when i solved the question i thought be positive and took M to be positive and got ans as 55 😂😂. Fortunately IIT gave ans as 55. Hence proved, we should stay positive. 😂😂
Yeah negative answers are rare and even if ans is negative they put mod😁
what rank did you get
@@Ferb56 mind ur business
Sir I fear discord will distract as only 1 month is hardly left for jee advanced
Sir i do share your videos everyday to my friends but they neither appreciate the effort nor follow it regularly. Sir u can reduce the frequency of videos and Create a mega video as per your schedule allows. 🙏🏻🙏🏻
Sir this hunger for likes won't get u anywhere
This was said by a student on Nitin sirs channel and he was roasted badly by 30 students in the reply to his comment
Lol
Its totally an illusion..we can see both ways of the winding i think..nonsense by jee just give both keys as answer, ruined future of so many students for sure
True
Sir kya khel gaye,
8k completed 🔥🔥🔥🔥🔥
Scam 2021🤣🤣🤣🤣