ME565 Lecture 10: Analytic Solution to Laplace's Equation in 2D (on rectangle)
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- เผยแพร่เมื่อ 26 เม.ย. 2016
- ME565 Lecture 10
Engineering Mathematics at the University of Washington
Analytic Solution to Laplace's Equation in 2D (on rectangle)
Notes: faculty.washington.edu/sbrunto...
Course Website: faculty.washington.edu/sbrunto...
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Thanks a lot, Prof.
at 41:30, why the 2 is missing from An??
Would it still be valid if I assume u(x,y,z) = F(x)G(y)H(z)? How do we deal with this such that they will relate to lambda?
This might not answer your question but I would say in general the separation between two sets of variables, such as time and space, is sufficient for most physical problem, even the space is in 3D. So u(t,x)=F(t)G(x) where x could be vector of space variables.
@@wowowowdog yeah but you would still end up with a PDE in x,y and z for the spacial function, how would you solve that?
How does the boundary condition on F(x) (being f(y) implying that there exists x s.t. F(x)=f(y)) make sense if you have already assumed that it has no y as an argument.
I guess they fulfil Dirichlet conditions, claiming that if the boundary of a (differentiated) function domain is fully described then a (unique) solution can be found. Since the square surrounds the domain of that function the solution is determined by that infinit sum with one boundary having constant value *f(y)*
Because it is equaling some constant. The only way for a function of 2 separate variables to be equal is if they are equaling some constant
Im going to deal with this 💀💀💀💀